Problem 177
Question
The electrons identified by quantum numbers \(\mathrm{n}\) and \(l\) \([\mathbf{2 0 1 2}]\) (1) \(\mathrm{n}=4, l=0\) (2) \(\mathrm{n}=4, l=1\) (3) \(\mathrm{n}=3, l=1\) (4) \(\mathrm{n}=3, l=2\) can be placed in order of increasing energy as (a) \(4<2<3<1\) (b) \(2<4<1<3\) (c) \(1<3<2<4\) (d) \(3<4<2<1\)
Step-by-Step Solution
Verified Answer
The correct order of increasing energy is option (d) \(3<4<2<1\).
1Step 1: Understanding the Quantum Numbers
Quantum numbers are sets of values that describe the unique quantum state of an electron. Here we are using principal quantum number \(n\), which denotes the energy level, and azimuthal quantum number \(l\), which determines the subshell. The energy of electrons increases with increasing \(n+l\). For electrons with the same \(n+l\), the one with the smaller \(n\) has lower energy.
2Step 2: Calculate \(n+l\) Values
Calculate \(n+l\) for each given set of quantum numbers:1. For \(\mathrm{n}=4,\ l=0\), \(n+l = 4+0 = 4\).2. For \(\mathrm{n}=4,\ l=1\), \(n+l = 4+1 = 5\).3. For \(\mathrm{n}=3,\ l=1\), \(n+l = 3+1 = 4\).4. For \(\mathrm{n}=3,\ l=2\), \(n+l = 3+2 = 5\).
3Step 3: Determine Energy Using \(n+l\) Rule
Determine the relative energies of the electrons based on their \(n+l\) values and principal quantum numbers. Electrons with lower \(n+l\) values have lower energy. If \(n+l\) is the same, the one with a lower \(n\) has lower energy.- Both options (1) and (3) have \(n+l = 4\), but option (3) with \(n=3\) is lower in energy than option (1) with \(n=4\).- Both options (2) and (4) have \(n+l = 5\), but option (4) with \(n=3\) is lower in energy than option (2) with \(n=4\).
4Step 4: Arrange in Increasing Energy Order
Based on the \(n+l\) rule:- Option (3) with \(n=3, l=1\) is the lowest energy.- Next is option (1) with \(n=4, l=0\).- Then comes option (4) with \(n=3, l=2\).- Lastly, option (2) with \(n=4, l=1\) has the highest energy.This sequence corresponds to choice (d) \(3<4<2<1\).
Key Concepts
The n+l RulePrincipal Quantum Number (n)Azimuthal Quantum Number (l)
The n+l Rule
The "n+l rule" is used to determine the energy levels of electrons in an atom. It's a handy method to find which electrons are more likely to be closer to the nucleus and therefore possess lower energy. Here's how it works:
- The sum of the principal quantum number ( defined as "n") and the azimuthal quantum number ( defined as "l") gives the term "n+l".
- Electrons with the lowest "n+l" value are at a lower energy state and are more stable.
- If two electrons have the same "n+l" value, the electron with the lower "n" value is considered lower in energy.
Principal Quantum Number (n)
The principal quantum number, often represented by the letter "n," plays a critical role in defining an electron's state within an atom. It primarily indicates the electron's energy level and distance from the nucleus. Let's break it down:
- The principal quantum number "n" can take positive integer values starting from 1 (e.g., 1, 2, 3, ...).
- Higher values of "n" mean the electron is in a higher energy level, which generally means a greater average distance from the nucleus.
- As "n" increases, the number of available subshells and orbitals for electrons also increases.
Azimuthal Quantum Number (l)
The azimuthal quantum number "l" is critical for understanding the shape and type of the electron's orbital within an atom. This number helps to specify the subshell an electron occupies, adding detail to what's initially described by the principal quantum number "n." Here's a closer look:
- The possible values of "l" range from 0 to (n-1), where "n" is the principal quantum number for that electron.
- Each value of "l" corresponds to a particular type of subshell or orbital: 0 = s, 1 = p, 2 = d, 3 = f, and so forth.
- The "l" value doesn't just designate the type of subshell but also indirectly influences the potential energy of an electron within its respective energy level.
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