Problem 175
Question
Which of the following reaction is possible at anode? [2002] (a) \(\mathrm{F}_{2}+2 \mathrm{e}^{-} \longrightarrow 2 \mathrm{~F}^{-}\) (b) \(2 \mathrm{H}^{+}+1 / 2 \mathrm{O}_{2}+2 \mathrm{e}^{-} \longrightarrow \mathrm{H}_{2} \mathrm{O}\) (c) \(2 \mathrm{Cr}_{2}^{3+}+7 \mathrm{H}_{2} \mathrm{O} \longrightarrow \mathrm{Cr}_{2} \mathrm{O}_{7}^{2-}+14 \mathrm{H}^{+}+6 \mathrm{e}^{-}\) (d) \(\mathrm{Fe}^{2+} \longrightarrow \mathrm{Fe}^{3+}+\mathrm{e}^{-}\)
Step-by-Step Solution
Verified Answer
Option (d): \(\mathrm{Fe}^{2+} \longrightarrow \mathrm{Fe}^{3+}+\mathrm{e}^{-}\) is possible at the anode.
1Step 1: Introduction to Anodic Reactions
In electrochemical cells, the anode is the electrode where oxidation occurs. This means that at the anode, electrons are lost by the species.
2Step 2: Examining the Reactions
Go through each option and determine whether oxidation or reduction is taking place.- Option (a): \(\mathrm{F}_{2}+2 \mathrm{e}^{-} \longrightarrow 2 \mathrm{~F}^{-}\) represents reduction as electrons are gained by \(\mathrm{F}_2\).- Option (b): \(2 \mathrm{H}^{+}+1/2 \mathrm{O}_{2}+2 \mathrm{e}^{-} \longrightarrow \mathrm{H}_{2} \mathrm{O}\) is also a reduction reaction.- Option (c): \(2 \mathrm{Cr}_{2}^{3+}+7 \mathrm{H}_{2} \mathrm{O} \longrightarrow \mathrm{Cr}_{2} \mathrm{O}_{7}^{2-}+14 \mathrm{H}^{+}+6 \mathrm{e}^{-}\) is an oxidation reaction since electrons are produced.- Option (d): \(\mathrm{Fe}^{2+} \longrightarrow \mathrm{Fe}^{3+}+\mathrm{e}^{-}\) is oxidation as \(\mathrm{Fe}^{2+}\) loses an electron.
3Step 3: Identify the Correct Reaction
From the examination, options (c) and (d) are oxidation reactions. However, the correct or most common anodic reaction usually involves a simple one-electron transfer. Therefore, \(\mathrm{Fe}^{2+} \longrightarrow \mathrm{Fe}^{3+}+\mathrm{e}^{-}\) is more likely to be possible at the anode.
Key Concepts
Anodic ReactionsOxidation and ReductionElectron TransferReaction Mechanisms
Anodic Reactions
In electrochemical cells, the **anode** is the electrode where the process of **oxidation** takes place. Understanding anodic reactions begins with knowing that at the anode, molecules or ions lose electrons. This loss of electrons is a distinctive feature that separates oxidation from reduction.
During anodic reactions:
- One or more reactants lose electrons.
- The overall charge of the reactants increases.
Oxidation and Reduction
**Oxidation and reduction** are two fundamental chemical reactions that occur together and are often referred to as **redox reactions**. Understanding these processes is key to mastering electrochemistry.
**Oxidation** involves:
- Loss of electrons by a chemical species.
- An increase in oxidation state.
- Gain of electrons by a chemical species.
- A decrease in oxidation state.
Electron Transfer
The transfer of **electrons** is a fundamental part of redox reactions and electrochemical cell operation. It describes how electrons move from one species to another, facilitating the conversion of chemical energy into electrical energy.
**Key aspects of electron transfer:**
- Electrons move from a higher energy state to a lower one.
- The path traveled by electrons is from the anode to the cathode in a cell.
- Electron transfer ensures the completion of the electrochemical circuit.
Reaction Mechanisms
**Reaction mechanisms** provide a step-by-step description of how chemical reactions proceed. They are essential in understanding how anodic reactions occur and what factors influence them.
Important points about reaction mechanisms:
- They illustrate the detailed pathway from reactants to products.
- Show intermediate structures that exist during the reaction.
- Help predict the rate and feasibility of the reaction based on electron transfer.
Other exercises in this chapter
Problem 172
In the electrolysis of \(\mathrm{KI}, \mathrm{I}_{2}\) is formed at the anode by the reaction; \(2 \mathrm{I} \longrightarrow \mathrm{I}_{2}+2 \mathrm{e}^{-}\)
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Consider the following reaction at \(1100^{\circ} \mathrm{C}\) [2002] (I) \(2 \mathrm{C}+\mathrm{O}_{2} \longrightarrow 2 \mathrm{CO} \Delta \mathrm{G}^{0}=-460
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Conductivity (Seimens S) is directly proportional to area of the vessel and the concentration of the solution in it and is inversely proportional to the length
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