Problem 174
Question
. Find the joint cdf of the independent random variables \(X\) and \(Y\), where \(f_{X}(x)=\frac{x}{2}, 0 \leq x \leq 2\), and \(f_{Y}(y)=2 y, 0 \leq y \leq 1 .\)
Step-by-Step Solution
Verified Answer
To find the joint cumulative distribution function (CDF) of the two independent random variables \(X\) and \(Y\), we first compute their individual CDFs given by their specific probability density functions, and then calculate the joint CDF by simply taking the product of the two individual CDFs.
1Step 1: Compute the CDF of X
We first need to calculate the cumulative distribution function (CDF) of \(X\). \[F_{X}(x)=\int_{0}^{x} f_{X}(t) dt \]Substitute \(f_{X}(t) = \frac{t}{2}\) into the equation, the value of \(F_{X}(x)\) is then calculated by integrating \(\frac{t}{2}\) from 0 to \(x\).
2Step 2: Compute the CDF of Y
Next, we compute the cumulative distribution function (CDF) of \(Y\). \[F_{Y}(y)=\int_{0}^{y} f_{Y}(s) ds \]Substitute \(f_{Y}(s) = 2s\) into the equation, the value of \(F_{Y}(y)\) is then computed by integrating \(2s\) from 0 to \(y\).
3Step 3: Compute the Joint CDF
Since \(X\) and \(Y\) are independent, the joint cumulative distribution function \(F(x,y)\) is the product of \(F_{X}(x)\) and \(F_{Y}(y)\):\[ F(x,y) = F_{X}(x)F_{Y}(y)\]
Key Concepts
CDF of independent random variablesProbability density functionIntegration in probability
CDF of independent random variables
Understanding the cumulative distribution function (CDF) of independent random variables is crucial in the field of probability and statistics. If we have two independent random variables, let's call them 'X' and 'Y', their joint CDF can be expressed as the product of their individual CDFs. This is a direct consequence of their independence, which implies that the occurrence of an event for 'X' does not affect the probability of an event for 'Y' and vice versa.
For example, let's consider a step-by-step solution where we are given two independent random variables 'X' and 'Y' with their corresponding probability density functions (PDFs). To find their joint CDF, we would first determine the CDF of each variable separately by integrating their PDFs. Then, because of their independence, we multiply these individual CDFs together to get the joint CDF, which is the probability that 'X' is less than or equal to some value 'x' and 'Y' is less than or equal to some value 'y'. Such straightforward methods greatly simplify the process of understanding multivariate distributions for students.
For example, let's consider a step-by-step solution where we are given two independent random variables 'X' and 'Y' with their corresponding probability density functions (PDFs). To find their joint CDF, we would first determine the CDF of each variable separately by integrating their PDFs. Then, because of their independence, we multiply these individual CDFs together to get the joint CDF, which is the probability that 'X' is less than or equal to some value 'x' and 'Y' is less than or equal to some value 'y'. Such straightforward methods greatly simplify the process of understanding multivariate distributions for students.
Probability density function
A probability density function, often abbreviated as PDF, is a function that describes the likelihood of a random variable to take on a certain value. For continuous random variables, the PDF provides the probability that the variable falls within a particular range of values. The fundamental property of a PDF is that the integral over the entire space is equal to 1, representing the certainty that the random variable will take on a value within its range.
The exercise given involves finding the PDFs for the random variables 'X' and 'Y', which are denoted as 'f_X(x)' and 'f_Y(y)', respectively. The PDFs are critical for calculating the CDFs later on. Adequate comprehension of PDFs is essential for students tackling probability theory, as they form the basis for interpreting and computing various statistical measures. It is the cornerstone for building up to more complex concepts, such as the calculation of expected values, variances, and even the application of Bayes' theorem.
The exercise given involves finding the PDFs for the random variables 'X' and 'Y', which are denoted as 'f_X(x)' and 'f_Y(y)', respectively. The PDFs are critical for calculating the CDFs later on. Adequate comprehension of PDFs is essential for students tackling probability theory, as they form the basis for interpreting and computing various statistical measures. It is the cornerstone for building up to more complex concepts, such as the calculation of expected values, variances, and even the application of Bayes' theorem.
Integration in probability
Integration is a powerful tool in probability theory which is often used to calculate cumulative distribution functions (CDFs) from probability density functions (PDFs). Integration can be thought of as a way to add up all probabilities up to a certain point, providing us with the cumulative probability.
For instance, in our exercise, to find the CDF of 'X', we integrate its PDF from the lower limit of the variable up to 'x'. Similarly, to find the CDF of 'Y', we integrate its PDF from zero to 'y'. This process essentially sums up the probabilities of 'X' being less than or equal to 'x' and 'Y' being less than or equal to 'y'. Especially for students, grasping the concept of integration within the context of probability is fundamental, as it is a frequent operation in many probabilistic applications. It enables them to transition from the density function, which shows the probability per unit, to the cumulative function, which illustrates the accumulated probability.
For instance, in our exercise, to find the CDF of 'X', we integrate its PDF from the lower limit of the variable up to 'x'. Similarly, to find the CDF of 'Y', we integrate its PDF from zero to 'y'. This process essentially sums up the probabilities of 'X' being less than or equal to 'x' and 'Y' being less than or equal to 'y'. Especially for students, grasping the concept of integration within the context of probability is fundamental, as it is a frequent operation in many probabilistic applications. It enables them to transition from the density function, which shows the probability per unit, to the cumulative function, which illustrates the accumulated probability.
Other exercises in this chapter
Problem 172
Are the random variables \(X\) and \(Y\) independent if \(f_{X, Y}(x, y)=\frac{2}{3}(x+2 y), 0 \leq x \leq 1,0 \leq y \leq 1 ?\)
View solution Problem 173
Suppose that random variables \(X\) and \(Y\) are independent with marginal pdfs \(f_{X}(x)=2 x, 0 \leq x \leq 1\), and \(f_{Y}(y)=3 y^{2}, 0 \leq y \leq 1\). F
View solution Problem 175
If two random variables \(X\) and \(Y\) are independent with marginal pdfs \(f_{X}(x)=2 x, 0 \leq x \leq 1\), and \(f_{Y}(y)=1\), \(0 \leq y \leq 1\), calculate
View solution Problem 176
Suppose \(f_{X, Y}(x, y)=x y e^{-(x+y)}, x>0, y>0\). Prove for any real numbers \(a, b, c\), and \(d\) that $$ P(a
View solution