Problem 173
Question
The roots of the equation \(z^{4}+1=0\) are (A) \((\pm 1 \pm i)\) (B) \((\pm 2 \pm 2 i)\) (C) \(\frac{1}{\sqrt{2}}(\pm 1 \pm i)\) (D) None of these
Step-by-Step Solution
Verified Answer
(C) \(\frac{1}{\sqrt{2}}(\pm 1 \pm i)\)
1Step 1: Set the Equation to Standard Form
The given equation is \(z^4 + 1 = 0\). This can be rearranged to \(z^4 = -1\).
2Step 2: Express \(-1\) in Polar Form
In polar form, \(-1\) can be expressed as \(e^{i\pi}\). Thus, we can write \(-1 = e^{i(\pi + 2k\pi)}\), where \(k\) is any integer.
3Step 3: Find the Fourth Roots of \(e^{i\pi}\)
To find the roots of \(z^4 = -1\), we need to take the fourth root of \(e^{i\pi}\). The fourth roots can be given by \(z = e^{i((\pi + 2k\pi)/4)}\) for \(k = 0, 1, 2, 3\).
4Step 4: Calculate the Angles for Each Root
Calculate the angles for the four roots:- For \(k=0\): \(z = e^{i\pi/4}\)- For \(k=1\): \(z = e^{i3\pi/4}\)- For \(k=2\): \(z = e^{i5\pi/4}\)- For \(k=3\): \(z = e^{i7\pi/4}\)
5Step 5: Convert the Complex Numbers to Rectangular Form
Converting from polar to rectangular form using \(z = \text{Re} + i\text{Im}\), where \(\text{Re} = \cos\theta\) and \(\text{Im} = \sin\theta\):- \(e^{i\pi/4} = \frac{1}{\sqrt{2}} + \frac{i}{\sqrt{2}}\)- \(e^{i3\pi/4} = -\frac{1}{\sqrt{2}} + \frac{i}{\sqrt{2}}\)- \(e^{i5\pi/4} = -\frac{1}{\sqrt{2}} - \frac{i}{\sqrt{2}}\)- \(e^{i7\pi/4} = \frac{1}{\sqrt{2}} - \frac{i}{\sqrt{2}}\)
6Step 6: Compare with the Given Options
The roots of the equation are \(\frac{1}{\sqrt{2}}(1+i),\frac{1}{\sqrt{2}}(-1+i),\frac{1}{\sqrt{2}}(-1-i),\and \frac{1}{\sqrt{2}}(1-i)\). Compare these to the given options to identify the correct answer, which corresponds to option (C).
Key Concepts
Polar FormRoots of UnityRectangular Form
Polar Form
When dealing with complex numbers, an alternative to the traditional rectangular form is the polar form. This approach is particularly useful for simplifying products and powers of complex numbers.
To represent a complex number in polar form, we use a magnitude, denoted by \(r\), and an angle, \(\theta\), which is the argument of the complex number. The polar form is given by the expression \(z = re^{i\theta}\), where \(r = |z|\) is the modulus of the complex number and \(\theta\) is the argument.
To represent a complex number in polar form, we use a magnitude, denoted by \(r\), and an angle, \(\theta\), which is the argument of the complex number. The polar form is given by the expression \(z = re^{i\theta}\), where \(r = |z|\) is the modulus of the complex number and \(\theta\) is the argument.
- The modulus \(r\) is the distance from the origin to the complex number in the complex plane. It can be calculated using \(r = \sqrt{x^2 + y^2}\), where \(x\) and \(y\) are the real and imaginary parts of the number, respectively.
- The argument \(\theta\) is the angle formed with the positive direction of the real axis. It can be found using \(\theta = \tan^{-1}(y/x)\).
Roots of Unity
The 'Roots of Unity' are the solutions to the equation \(z^n = 1\), representing points evenly distributed around a circle in the complex plane at intervals of \(\frac{2\pi}{n}\). This idea extends naturally when solving equations like \(z^4 = -1\), where roots are distributed around a shifted unit circle by an angle such as \(\pi\) or \(\pi/4\).
For instance, for the equation \(z^4 = -1\), we express \(-1\) as \(e^{i\pi}\), transforming the equation into a problem of locating fourth roots:
For instance, for the equation \(z^4 = -1\), we express \(-1\) as \(e^{i\pi}\), transforming the equation into a problem of locating fourth roots:
- Calculate the principal angle: \(\pi\)
- Spread angles equally: \(\pi + 2k\pi\)
- Divide by the exponent dimension: \((\pi + 2k\pi)/4\)
- Compute for \(k = 0, 1, 2, 3\).
Rectangular Form
The rectangular form of complex numbers, denoted as \(z = x + yi\), is the most straightforward way of expressing complex numbers. It shows the number plainly as a sum of real and imaginary components. This form is very useful in basic arithmetic operations such as addition and subtraction.
To switch a complex number from polar to rectangular form, you perform a straightforward transformation using trigonometric functions:
This familiarity makes rectangular forms a convenient choice for identifying roots on the coordinate axis, while still benefiting from the computational efficiency of polar form for multiplication and division.
To switch a complex number from polar to rectangular form, you perform a straightforward transformation using trigonometric functions:
- The real part \(x = r \cos\theta\)
- The imaginary part \(y = r \sin\theta\)
This familiarity makes rectangular forms a convenient choice for identifying roots on the coordinate axis, while still benefiting from the computational efficiency of polar form for multiplication and division.
Other exercises in this chapter
Problem 171
One of the values of \((a+i b)^{m i n}+(a-i b)^{m / n}\) is (A) \(2\left(a^{2}+b^{2}\right)^{m / n} \cos \left(\frac{m}{n} \tan ^{-1} \frac{b}{a}\right)\) (B) \
View solution Problem 172
The values of \((16)^{1 / 4}\) are (A) \(\pm 2, \pm 2 i\) (B) \(\pm 4, \pm 4 i\) (C) \(\pm 1, \pm i\) (D) None of these
View solution Problem 174
If \(1, \omega, \omega^{2}, \ldots \omega^{n-1}\) are the \(n, n\)th roots of unity and \(z_{1}\) and \(z_{2}\) are any two complex numbers, then $$ \sum_{k=0}^
View solution Problem 175
If \(1, a_{1}, a_{2}, \ldots, a_{n-1}\) are the \(n, n\)th roots of unity, then \(\left(1-a_{1}\right)\left(1-a_{2}\right)\left(1-a_{3}\right) \ldots\left(1-a_{
View solution