Problem 172
Question
Which of the following statement(s) is/are correct? (a) The nucleophilic addition of \(\mathrm{HCN}\) to \(\mathrm{CH}_{3}-\mathrm{CH}=\) \(\mathrm{CH}-\mathrm{CHO}\) results in major addition to \(\mathrm{C}=\mathrm{O}\). (b) The nucleophilic addition of \(\mathrm{HCN}\) to \(\mathrm{CH}_{3}-\mathrm{CH}=\) \(\mathrm{CH}-\mathrm{CHO}\) results in major addition to \(\overrightarrow{\mathrm{C}}=\mathrm{C}\). (c) The nucleophilic addition of \(\mathrm{PhMgBr}\) to \(\mathrm{PhCH}=\) \(\mathrm{CH}-\mathrm{COCMe}_{3}\) results in addition to \(\mathrm{C}=\mathrm{C}\). (d) The nucleophilic addition of \(\mathrm{PhMgBr}\) to \(\mathrm{PhCH}\) \(\mathrm{CH}-\mathrm{CHO}\) results in addition to \(\mathrm{C}=\mathrm{O}\).
Step-by-Step Solution
Verified Answer
Statements (a) and (d) are correct.
1Step 1: Understand the Reaction Mechanisms
In nucleophilic addition reactions, the nucleophile attacks the carbon with the highest positive charge, usually found in carbonyl groups \( (C=O) \) or at the double bonds \( (C=C) \) when sufficiently activated. We need to consider the reactivity and the structural aspects of the compounds in question.
2Step 2: Analyze Statement (a)
Statement (a) mentions the addition of \( \text{HCN} \) to \( \text{CH}_3-\text{CH}=\text{CH}-\text{CHO} \). This compound contains both \( C=O \) and \( C=C \) groups. Generally, \( \text{HCN} \) as a nucleophile will preferentially add to the carbonyl group because the \( C=O \) group is more polar and thus more electrophilic. Therefore, major addition to \( C=O \) is expected.
3Step 3: Analyze Statement (b)
Statement (b) suggests major addition of \( \text{HCN} \) to the \( C=C \) bond. However, due to the preference of \( \text{HCN} \) to add to more electrophilic centers such as carbonyl \( C=O \) over less polar \( C=C \), this statement doesn't align with typical nucleophilic addition behavior. Thus, this is incorrect.
4Step 4: Analyze Statement (c)
Statement (c) considers \( \text{PhMgBr} \) (a Grignard reagent) adding to \( \text{PhCH}=\text{CH}-\text{COCMe}_3 \). Grignard reagents strongly favor reaction with carbonyl groups \( C=O \), not \( C=C \) unless the circumstance is unique, such as activation of \( C=C \) by adjacent electron-withdrawing groups. Here, primary activity would be at the \( C=O \), so addition to \( C=C \) is unlikely to be the major pathway.
5Step 5: Analyze Statement (d)
Statement (d) states that \( \text{PhMgBr} \) adds to the \( C=O \) bond in \( \text{PhCH}=\text{CH}-\text{CHO} \). Grignard reagents are well-known for attacking carbonyl groups \( C=O \) efficiently, making this statement correct.
Key Concepts
Grignard ReactionCarbonyl Group ReactivityElectrophilic Centers
Grignard Reaction
The Grignard reaction is a crucial transformation in organic chemistry that involves the use of Grignard reagents. These are organomagnesium compounds, which are typically represented as R-Mg-X, where R denotes an organic group (often an alkyl or aryl group), and X is a halogen.
Although Grignard reagents are also capable of reacting with other electrophilic sites, their selectivity towards carbonyl groups makes them a preferred tool for organic chemists looking to construct complex molecules.
- Grignard reagents are highly reactive and serve as powerful nucleophiles.
- Their main function is to attack electrophilic carbon atoms, particularly in carbonyl groups (C=O), to form new carbon-carbon bonds.
Although Grignard reagents are also capable of reacting with other electrophilic sites, their selectivity towards carbonyl groups makes them a preferred tool for organic chemists looking to construct complex molecules.
Carbonyl Group Reactivity
Carbonyl groups, characterized by a carbon double-bonded to oxygen (C=O), are notable for their high reactivity in organic chemistry. This prominence is attributed to the polar nature of the C=O bond.
Consequently, carbonyl groups are more reactive than non-polar C=C double bonds in compounds that contain both. In competitive scenarios, as in the presence of both C=O and C=C, nucleophiles often prefer engaging with carbonyl sites, barring any exceptional structural influences.
- The oxygen atom is more electronegative, attracting electrons and creating a partial negative charge.
- The carbon atom, conversely, holds a partial positive charge, making it an electrophilic center.
Consequently, carbonyl groups are more reactive than non-polar C=C double bonds in compounds that contain both. In competitive scenarios, as in the presence of both C=O and C=C, nucleophiles often prefer engaging with carbonyl sites, barring any exceptional structural influences.
Electrophilic Centers
Electrophilic centers in a molecule are regions that are electron-deficient and thus seek electrons to achieve a stable electronic configuration. Such centers often arise from polar bonds where one atom is significantly more electronegative than the other.
- In a carbonyl group, the electrophilic center is typically the carbon atom due to the partial positive charge it bears.
- These centers are hotspots for nucleophilic attacks where electron-rich species donate electrons to these electron-deficient atoms.
Other exercises in this chapter
Problem 166
Which of the following undergoes aldol condensation? 1\. Acetaldehyde 2\. Propionaldehyde 3\. Benzaldehyde 4\. Trideuteroacetaldehyde. (a) 1,2 (b) \(1,2,3\) (c)
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A new carbon-carbon bond formation is possible in 1\. Cannizzro reaction 2\. Feirdel-Craft's reaction 3\. Clemmensen reduction 4\. Reimer - Teimann reaction (a)
View solution Problem 176
Which of the following reactions, yield a product with a three membered ring? (a) \(\mathrm{CH}_{3}-\mathrm{C}(\mathrm{O})-\mathrm{CH}_{2} \mathrm{CH}_{2} \math
View solution Problem 177
Identify the products formed \((\mathrm{X})\) and \((\mathrm{Y})\) in the following reaction \(\mathrm{C}_{6} \mathrm{H}_{5} \mathrm{CHO}+\mathrm{HCHO}_{\text {
View solution