Problem 17
Question
Write the given nonhomogeneous differential equation as an operator equation, and give the associated homogeneous differential equation. $$y^{\prime \prime \prime}+x^{2} y^{\prime \prime}-(\sin x) y^{\prime}+e^{x} y=x^{3}$$
Step-by-Step Solution
Verified Answer
The given nonhomogeneous differential equation can be written as an operator equation: \(D^{3}y + x^{2}D^{2}y - (\sin x)Dy + e^{x}y = x^{3}\). The associated homogeneous differential equation is: \(y^{\prime \prime \prime} + x^{2}y^{\prime \prime} - (\sin x)y^{\prime} + e^{x}y = 0\).
1Step 1: Write the given nonhomogeneous differential equation as an operator equation
To do this, we will replace the derivatives of \(y\) and the function \(y\) itself with the corresponding differential operators:
- Replace \(y^{\prime \prime \prime}\) with \(D^3\)
- Replace \(x^{2}y^{\prime \prime}\) with \(x^{2}D^2\)
- Replace \((\sin x) y^{\prime}\) with \((\sin x)D\)
- Replace \(e^x y\) with \(e^x\)
Now we can rewrite the given equation as:
$$D^{3}y + x^{2}D^{2}y - (\sin x)Dy + e^{x}y = x^{3}$$
2Step 2: Identify the associated homogeneous differential equation
To find the associated homogeneous differential equation, we simply set the right-hand side of the equation to zero. This gives us:
$$D^{3}y + x^{2}D^{2}y - (\sin x)Dy + e^{x}y = 0$$
The associated homogeneous differential equation is:
$$y^{\prime \prime \prime} + x^{2}y^{\prime \prime} - (\sin x)y^{\prime} + e^{x}y = 0$$
Key Concepts
Differential OperatorsHomogeneous Differential EquationThird-order Differential EquationLinear Differential Equation
Differential Operators
In differential equations, a differential operator is a symbol that represents a mathematical operation involving derivatives. It effectively replaces the derivatives with algebraic symbols, streamlining calculations and manipulations. The most common differential operator, denoted as 'D', represents the derivative with respect to a variable, usually 'x'. For instance, if you have a function 'y', then 'Dy' would represent its first derivative, 'D^2y' its second derivative, and so on.
Applying differential operators to an equation can transform a complicated differential equation into an operator equation that resembles a polynomial equation. This form allows for the application of algebraic techniques to analyze and solve differential equations, which can be especially useful when dealing with higher-order and linear differential equations.
Applying differential operators to an equation can transform a complicated differential equation into an operator equation that resembles a polynomial equation. This form allows for the application of algebraic techniques to analyze and solve differential equations, which can be especially useful when dealing with higher-order and linear differential equations.
Homogeneous Differential Equation
A homogeneous differential equation is one where every term is a function of the variable and its derivatives only, without any external functions or constants. More formally, it can be characterized as an equation in which all terms involve the dependent variable or its derivatives, and it equals zero.
Recognizing a homogeneous differential equation is important because it allows the use of specific methods to find the general solution. When given a nonhomogeneous differential equation, which includes an additional function or constant, creating the associated homogeneous equation involves setting the 'nonhomogeneous' part to zero. Solving the homogeneous equation provides a complementary function that's part of the general solution for the nonhomogeneous equation.
Recognizing a homogeneous differential equation is important because it allows the use of specific methods to find the general solution. When given a nonhomogeneous differential equation, which includes an additional function or constant, creating the associated homogeneous equation involves setting the 'nonhomogeneous' part to zero. Solving the homogeneous equation provides a complementary function that's part of the general solution for the nonhomogeneous equation.
Third-order Differential Equation
A third-order differential equation is one in which the highest derivative is the third derivative of the dependent variable. Such equations are more complex than first or second-order differential equations because they can describe systems with more than one degree of freedom, leading to a richer set of behaviors and solutions.
Solutions to third-order differential equations typically involve three constants, correlating to the equation's order. Finding the complete solution often requires integration up to three times and may incorporate techniques such as undetermined coefficients or variation of parameters, particularly when dealing with nonhomogeneous equations.
Solutions to third-order differential equations typically involve three constants, correlating to the equation's order. Finding the complete solution often requires integration up to three times and may incorporate techniques such as undetermined coefficients or variation of parameters, particularly when dealing with nonhomogeneous equations.
Linear Differential Equation
A linear differential equation is an equation that involves the dependent variable and its derivatives to the first power; nonlinear terms such as the product of derivatives or powers of derivatives are not present. Linear equations maintain the principle of superposition, meaning that the sum of any two solutions is also a solution.
In the context of higher-order linear differential equations, like our example involving a third-order differential equation, the focus lies on additive solutions. The general solution is a sum of two parts: the complementary solution (solving the homogeneous equation) and the particular solution (which addresses the nonhomogeneous version). This structural complexity underscores the importance of mastering both homogeneous and nonhomogeneous techniques to tackle and thoroughly understand a wide array of mathematical and physical problems.
In the context of higher-order linear differential equations, like our example involving a third-order differential equation, the focus lies on additive solutions. The general solution is a sum of two parts: the complementary solution (solving the homogeneous equation) and the particular solution (which addresses the nonhomogeneous version). This structural complexity underscores the importance of mastering both homogeneous and nonhomogeneous techniques to tackle and thoroughly understand a wide array of mathematical and physical problems.
Other exercises in this chapter
Problem 16
Determine the general solution to the given differential equation. $$y^{\prime \prime}+8 y^{\prime}+20 y=0$$
View solution Problem 17
Determine the annihilator of the given function. $$F(x)=4 x \sin x-3 e^{-2 x}$$
View solution Problem 17
Solve the given differential equation on the interval \(x>0 .\) [Remember to put the equation in standard form.] $$x^{2} y^{\prime \prime}-x y^{\prime}+5 y=8 x(
View solution Problem 17
Determine the general solution to the given differential equation. Derive your trial solution using the annihilator technique. $$(D-1)(D+2) y=5 e^{3 x}$$.
View solution