Problem 17
Question
Write each equation in standard form. State whether the graph of the equation is a parabola, circle, ellipse, or hyperbola. Then graph the equation. $$ x^{2}+y^{2}+6 y+13=40 $$
Step-by-Step Solution
Verified Answer
The equation represents a circle and its graph is centered at (0, -3) with radius 6.
1Step 1: Convert to Standard Form
Start by rewriting the given equation: \( x^2 + y^2 + 6y + 13 = 40 \). First, move the constant term to the right side: \( x^2 + y^2 + 6y = 27 \). Next, complete the square for the \(y\) terms.
2Step 2: Complete the Square
Take the equation \( x^2 + y^2 + 6y = 27 \). To complete the square on \( y \), use the formula \((b/2)^2\) where \( b \) is the coefficient of \( y \). Here, \( b = 6 \). So, \((6/2)^2 = 9\). Add and subtract 9 inside the equation: \( x^2 + (y^2 + 6y + 9 - 9) = 27 \).This becomes: \( x^2 + (y + 3)^2 - 9 = 27 \).Simplify to: \( x^2 + (y + 3)^2 = 36 \).
3Step 3: Identify the Conic Section
The equation \( x^2 + (y + 3)^2 = 36 \) is in the form \((x-h)^2 + (y-k)^2 = r^2\), which is the standard form for a circle.Here, the center is \((h, k) = (0, -3)\) and the radius \( r = 6 \). So, the graph is a circle.
Key Concepts
circlestandard formcomplete the square
circle
A circle is a perfect geometrical shape where every point on the edge is equidistant from a central point, known as the center of the circle. This distance from the center to any point on the circle is called the radius.
In mathematics, circles are one of the basic shapes studied in the branch of geometry called conic sections.
In mathematics, circles are one of the basic shapes studied in the branch of geometry called conic sections.
- A circle can be derived from slicing a cone horizontally parallel to its base.
- Its characteristics include uniform symmetry, constant curvature, and a simple central point forming symmetry around it.
- It is often represented in an equation form which helps in graphical analysis.
standard form
The standard form of a circle is a way to express its equation in the most compact and recognizable manner. This form sets the foundation for easily interpreting and graphing the circle.
Learners can apply this knowledge to solve and graph equations efficiently in various mathematical and real-world problems.
- The general representation is: \((x-h)^2 + (y-k)^2 = r^2\).
- Here, \((h, k)\) is the center of the circle, and \(r\) is the radius.
- Its center
- Its radius.
Learners can apply this knowledge to solve and graph equations efficiently in various mathematical and real-world problems.
complete the square
Completing the square is a key algebraic technique used to manipulate a quadratic equation into a form that reveals significant properties about the shape of its graph. This method is especially helpful in converting an equation into the standard form.
When applied to equations of conic sections:
When applied to equations of conic sections:
- This method helps specify the center and radius of circles or vertex of parabolas, making it easier to graph them.
- In our example, we had to complete the square for the \(y\) terms in the equation \(x^2 + y^2 + 6y = 27\).
- First, identify the coefficient \(b\) in the \(y\) terms, and use the formula \((b/2)^2\) to find the value to add and subtract for completing the square.
- This gives us the expression \((y + 3)^2\), turning the original equation into a recognizable, standard form.
Other exercises in this chapter
Problem 17
Find the exact solution(s) of each system of equations. $$ \begin{array}{l}{y^{2}+x^{2}=25} \\ {y^{2}+9 x^{2}=25}\end{array} $$
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Find the coordinates of the vertices and foci and the equations of the asymptotes for the hyperbola with the given equation. Then graph the hyperbola. $$ \frac{
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Graph each equation. $$ y=x^{2}-12 x+20 $$
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Write an equation for the circle that satisfies each set of conditions. center \((-8,7),\) radius \(\frac{1}{2}\) unit
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