Problem 17
Question
Which of the series in Exercises 13 46 converge, and which diverge? Give reasons for your answers. (When you check an answer, remember that there may be more than one way to determine the series' convergence or divergence.) $$ \sum_{n=1}^{\infty} \frac{3}{\sqrt{n}} $$
Step-by-Step Solution
Verified Answer
The series diverges because it is a p-series with \( p = 0.5 < 1 \).
1Step 1: Identify the series type
The given series is \( \sum_{n=1}^{\infty} \frac{3}{\sqrt{n}} \). This is a p-series, which can be written as \( \sum_{n=1}^{\infty} n^{-p} \), with \( p = 0.5 \) in this case, since \( \frac{3}{\sqrt{n}} \) can be rewritten as \( 3n^{-0.5} \).
2Step 2: Recall the p-series convergence test
A p-series \( \sum_{n=1}^{\infty} n^{-p} \) converges if \( p > 1 \) and diverges if \( p \leq 1 \). In the given series, the exponent \( p \) is 0.5, which is less than 1.
3Step 3: Apply the convergence test
Since \( p = 0.5 \leq 1 \), according to the p-series test, the series \( \sum_{n=1}^{\infty} \frac{3}{\sqrt{n}} \) diverges.
4Step 4: Conclude with the test result
The series does not meet the criteria for convergence as the p-value is less than 1. Therefore, the series diverges.
Key Concepts
p-series TestConvergenceDivergenceInfinite Series
p-series Test
The p-series test is a vital tool used in calculus to determine whether an infinite series converges or diverges. An infinite series is referred to as a p-series when it takes the form \[ \sum_{n=1}^{\infty} \frac{1}{n^p} \] where
- \( p \) is a positive constant.
Convergence
Convergence of an infinite series occurs when the sum of all its terms approaches a finite number as the number of terms becomes very large. In mathematical terms, we say that the series sum, when considered up to infinity, results in a finite limit. For any series \( \sum a_n \), if the series' partial sums \( S_N = a_1 + a_2 + \cdots + a_N \) tend to a definite number as \( N \to \infty \), the series is convergent.Some key facts about convergence include: - Convergent series do not "blow up" or approach infinity.- They often stabilize at some number, making them particularly useful in mathematical and real-world applications.In the context of p-series, if \( p > 1 \), the terms decrease fast enough that the series converges. For example, \( \sum_{n=1}^{\infty} \frac{1}{n^2} \) converges because the exponent \( p = 2 \) is greater than 1.
Divergence
Divergence, in contrast to convergence, occurs when the sum of a series grows indefinitely as more terms are added. If a series does not meet the criteria for convergence, it is usually divergent. This can happen, for instance, if the series doesn't approach a finite limit, indicating the partial sums increase without bound.Generally, for the p-series \( \sum_{n=1}^{\infty} \frac{1}{n^p} \): - If \( p \leq 1 \), the series diverges. - When \( p = 1 \), it matches the harmonic series \( \sum_{n=1}^{\infty} \frac{1}{n} \), which is a well-known example of a divergent series. In the exercise, \( \sum_{n=1}^{\infty} \frac{3}{\sqrt{n}} \) diverges because the term \( n^{-0.5} \) doesn't decrease fast enough for the series to approach a finite limit. Understanding divergence helps us recognize series that do not settle into a steady value, making them behave unpredictably over large sums.
Infinite Series
An infinite series is an important mathematical structure formed by adding up infinitely many terms. It takes the form \[ \sum_{n=1}^{\infty} a_n \] where
- \( a_n \) represents the general term of the series.
Other exercises in this chapter
Problem 17
Find the Maclaurin series for the functions. 7 \(\cos (-x)\)
View solution Problem 17
Use power series operations to find the Taylor series at \(x=0\) for the functions in Exercises \(13-30\) . $$x \cos \pi x$$
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Use series to estimate the integrals' values with an error of magnitude less than \(10^{-5}\) . (The answer section gives the integrals' values rounded to seven
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In Exercises \(1-36,\) (a) find the series' radius and interval of convergence. For what values of \(x\) does the series converge (b) absolutely (c) conditional
View solution