Problem 17
Question
When the following reactions come to equilibrium, does he equilibrium mixture contain mostly reactants or mostly broducts? a) \(\mathrm{N}_{2}(g)+\mathrm{O}_{2}(g) \rightleftharpoons 2 \mathrm{NO}(g) ; K_{c}=1.5 \times 10^{-10}\) b) \(2 \mathrm{SO}_{2}(g)+\mathrm{O}_{2}(g) \rightleftharpoons 2 \mathrm{SO}_{3}(g) ; K_{p}=2.5 \times 10^{9}\)
Step-by-Step Solution
Verified Answer
For Reaction A (\(\mathrm{N}_{2}(g)+\mathrm{O}_{2}(g) \rightleftharpoons 2 \mathrm{NO}(g)\)) with \(K_{c}=1.5 \times 10^{-10}\), the equilibrium mixture contains mostly reactants since \(K_{c}\) is much smaller than 1. For Reaction B (\(2 \mathrm{SO}_{2}(g)+\mathrm{O}_{2}(g) \rightleftharpoons 2\mathrm{SO}_{3}(g)\)) with \(K_{p}=2.5 \times 10^{9}\), the equilibrium mixture contains mostly products since \(K_{p}\) is much larger than 1.
1Step 1: Reaction A: Determining if equilibrium favors reactants or products
Given reaction A: \(\mathrm{N}_{2}(g)+\mathrm{O}_{2}(g) \rightleftharpoons 2 \mathrm{NO}(g)\).
The equilibrium constant is \(K_{c}=1.5 \times 10^{-10}\).
Since \(K_{c}\) is much smaller than 1, this reaction is reactant-favored. Therefore, the equilibrium mixture contains mostly reactants - nitrogen and oxygen gases.
2Step 2: Reaction B: Determining if equilibrium favors reactants or products
Given reaction B: \(2 \mathrm{SO}_{2}(g)+\mathrm{O}_{2}(g) \rightleftharpoons 2\mathrm{SO}_{3}(g)\).
The equilibrium constant is \(K_{p}=2.5 \times 10^{9}\).
Since \(K_{p}\) is much larger than 1, this reaction is product-favored. Therefore, the equilibrium mixture contains mostly products - sulfur trioxide gas.
In conclusion, for Reaction A, the equilibrium mixture contains mostly reactants while in Reaction B, the equilibrium mixture contains mostly products.
Key Concepts
Equilibrium ConstantsReaction FavorabilityGaseous Reactions
Equilibrium Constants
The concept of equilibrium constants is a fundamental aspect of chemical equilibrium. An equilibrium constant is a numerical value that reflects the ratio of concentrations of products to reactants at equilibrium. This constant is represented by either \( K_c \) for concentration in molarity or \( K_p \) for partial pressures in gaseous systems.
When analyzing a chemical equation, the equilibrium constant helps to determine the relative amounts of products and reactants in the mixture at equilibrium. If \( K \) is much greater than 1, it suggests that the reaction heavily favors the formation of products. Conversely, if \( K \) is much less than 1, it indicates a greater concentration of reactants at equilibrium.
When analyzing a chemical equation, the equilibrium constant helps to determine the relative amounts of products and reactants in the mixture at equilibrium. If \( K \) is much greater than 1, it suggests that the reaction heavily favors the formation of products. Conversely, if \( K \) is much less than 1, it indicates a greater concentration of reactants at equilibrium.
- Large \( K \) value: more products than reactants
- Small \( K \) value: more reactants than products
Reaction Favorability
Reaction favorability describes whether a given chemical reaction is more likely to proceed towards the formation of products or the preservation of reactants. It is largely dependent on the equilibrium constant value.
In a chemical reaction, the direction of favorability is evident from the comparison of \( K \) values:
The conditions under which these reactions occur, like temperature and pressure, can also influence the equilibrium but are not solely responsible for driving the direction of favorability.
In a chemical reaction, the direction of favorability is evident from the comparison of \( K \) values:
- \( K \) greater than 1: Reaction is product-favored, resulting in a larger quantity of products
- \( K \) less than 1: Reaction is reactant-favored, producing fewer products
The conditions under which these reactions occur, like temperature and pressure, can also influence the equilibrium but are not solely responsible for driving the direction of favorability.
Gaseous Reactions
Gaseous reactions are chemical processes that involve substances in the gas phase. Such reactions are particularly influenced by changes in volume, pressure, and temperature due to the nature of gases.
For gaseous equilibria, the use of \( K_p \) (equilibrium constant in terms of pressure) is common because gases behave according to the ideal gas law; hence, their concentrations are directly related to pressure. In scenarios where gaseous reaction equilibrium is concerned:
For gaseous equilibria, the use of \( K_p \) (equilibrium constant in terms of pressure) is common because gases behave according to the ideal gas law; hence, their concentrations are directly related to pressure. In scenarios where gaseous reaction equilibrium is concerned:
- Partial pressures of the gases are key in calculating \( K_p \).
- Changes in pressure affect equilibrium positions based on Le Chatelier's principle — increasing pressure will shift the equilibrium towards the side with fewer moles of gas.
Other exercises in this chapter
Problem 15
Write the expression for \(K_{c}\) for the following reactions. In each case indicate whether the reaction is homogeneous or heterogeneous. (a) \(3 \mathrm{NO}(
View solution Problem 16
Write the expressions for \(K_{c}\) for the following reactions. In each case indicate whether the reaction is homogeneous or heterogeneous. (a) \(2 \mathrm{O}_
View solution Problem 18
Which of the following reactions lies to the right, favoring the formation of products, and which lies to the left, favoring formation of reactants? (a) \(2 \ma
View solution Problem 19
Can the equilibrium constant ever be a negative number? Explain.
View solution