Problem 17
Question
Use power series operations to find the Taylor series at \(x=0\) for the functions in Exercises \(11-28 .\) $$\cos ^{2} x\left(\operatorname{Hin} t \cdot \cos ^{2} x=(1+\cos 2 x) / 2\right)$$
Step-by-Step Solution
Verified Answer
Expand and simplify the terms from the cosine identity.
1Step 1: Start with the given substitution
Given: \[\cos^2 x = \frac{1+\cos 2x}{2}\]This substitution simplifies \(\cos^2 x\) using a trigonometric identity.
2Step 2: Expand using the Taylor series for \(\cos 2x\)
The Taylor series for \(\cos x\) around \(x = 0\) is:\[\cos x = 1 - \frac{x^2}{2} + \frac{x^4}{24} - \frac{x^6}{720} + \cdots\]Thus, substitute \(2x\) to find \(\cos 2x\):\[\cos 2x = 1 - \frac{(2x)^2}{2} + \frac{(2x)^4}{24} - \frac{(2x)^6}{720} + \cdots\]Simplify:\[\cos 2x = 1 - 2x^2 + \frac{4x^4}{6} - \frac{8x^6}{720} + \cdots\]
Key Concepts
Power SeriesTrigonometric IdentitiesSeries ExpansionCalculus
Power Series
Power series are mathematical expressions that help us represent complex functions in simpler terms. They are similar to polynomials, but with an infinite number of terms. The general form of a power series is:
- \[ a_0 + a_1(x - c) + a_2(x - c)^2 + a_3(x - c)^3 + \cdots \]
Trigonometric Identities
Trigonometric identities are equations involving trigonometric functions that hold true for all values of the involved variables. These identities are instrumental in simplifying expressions and solving trigonometric equations. One such identity used in the solution is:
- \(\cos^2 x = \frac{1 + \cos 2x}{2}\)
Series Expansion
Series expansion is a method used to express a function as a sum of terms, typically involving powers of a variable. The Taylor series is a renowned type of series expansion.When we talk about a Taylor series, we are expanding a function around a specific point, usually 0, similar to our current problem. For instance, the Taylor series for \(\cos x\) around \(x=0\) is:
- \[\cos x = 1 - \frac{x^2}{2} + \frac{x^4}{24} - \cdots \]
Calculus
Calculus is a significant branch of mathematics focusing on change. It incorporates both differentiation and integration, essential for analyzing dynamic systems.
In our exercise, calculus principles are applied to find the Taylor series, a process that involves infinitely differentiable functions. Familiarity with derivatives is important because each term in a Taylor series relates to derivatives of the function at a specific point. Understanding these concepts is crucial:
- Differentiation: Helps find the rate of change of quantities.
- Integration: Helps determine the accumulation of quantities.
Other exercises in this chapter
Problem 16
In Exercises \(13-26,\) find a formula for the \(n\) th term of the sequence. The sequence \(1,-\frac{1}{4}, \frac{1}{9},-\frac{1}{16}, \frac{1}{25}, \dots\)
View solution Problem 17
Use series to estimate the integrals' values with an error of magnitude less than \(10^{-5}\) . (The answer section gives the integrals' values rounded to seven
View solution Problem 17
Find the Maclaurin series for the functions 7 \(\cos (-x)\)
View solution Problem 17
Which of the series Converge absolutely, which converge, and which diverge? Give reasons for your answers. $$ \sum_{n=1}^{\infty}(-1)^{n} \frac{1}{\sqrt{n}} $$
View solution