Problem 17
Question
True (with reason) or false (with example): (a) If \(f(t)<0\) then \(d f / d t<0\) (b) The derivative of \((f(t))^{2}\) is \(2 d f / d t\) (c) The derivative of \(2 f(t)\) is \(2 d f / d t\). (d) The derivative is the limit of \(\Delta f\) divided by the limit of \(\Delta t\).
Step-by-Step Solution
Verified Answer
(a) False, (b) False, (c) True, (d) False.
1Step 1: Analyzing Statement (a)
The statement is "If \(f(t) < 0\), then \(df/dt < 0\)." This claim implies that for a function with a negative value, its derivative must also be negative. This is false because the sign of \(f(t)\) does not dictate the sign of its derivative. For instance, \(f(t) = -t^2\) is a function where \(f(t) < 0\) for \(t eq 0\), but \(df/dt = -2t\) can be positive, negative, or zero depending on the value of \(t\).
2Step 2: Analyzing Statement (b)
The statement is "The derivative of \((f(t))^2\) is \(2 df/dt\)." By applying the chain rule to \((f(t))^2\), we get \(d((f(t))^2)/dt = 2f(t) \cdot (df/dt)\). Therefore, the statement is false by omission of the \(f(t)\) term.
3Step 3: Analyzing Statement (c)
The statement is "The derivative of \(2f(t)\) is \(2 df/dt\)." Using the constant multiple rule, if you differentiate \(2f(t)\), you directly apply \(d(2f(t))/dt = 2(df/dt)\). This is true because the constant 2 remains as a factor of the derivative of \(f(t)\).
4Step 4: Analyzing Statement (d)
The statement is "The derivative is the limit of \(\Delta f\) divided by the limit of \(\Delta t\)." The derivative is actually defined as the limit of the ratio \(\Delta f/\Delta t\) as \(\Delta t\) approaches zero: \(df/dt = \lim_{\Delta t \to 0} (\Delta f/\Delta t)\). Therefore, it is false to say that it is the division of the individual limits of \(\Delta f\) and \(\Delta t\), should always be considered as a ratio where \(\Delta t\) approaches zero.
Key Concepts
Chain ruleDerivativeDifferentiationLimitConstant multiple rule
Chain rule
The chain rule is an essential concept in calculus. It allows us to differentiate composite functions, which are functions composed of two or more simpler functions. The chain rule can be thought of as a process to unravel these compositions.
To apply the chain rule, think of one function nested within another, like cases in mathematics where a variable substitution might simplify solving an equation.
If you have a function of the form \(g(f(t))\), its derivative is determined using the chain rule: \(\frac{d}{dt}[g(f(t))] = g'(f(t)) \cdot f'(t)\).
To apply the chain rule, think of one function nested within another, like cases in mathematics where a variable substitution might simplify solving an equation.
If you have a function of the form \(g(f(t))\), its derivative is determined using the chain rule: \(\frac{d}{dt}[g(f(t))] = g'(f(t)) \cdot f'(t)\).
- The outer function is differentiated as normal but keeping the inner function in place.
- The inner function is then differentiated on its own, and its derivative multiplies the derivative of the outer function.
Derivative
The derivative represents the rate of change of a function with respect to its variable. It's the calculus tool used to analyze how a function changes as its input changes.
For a function \(f(t)\), the derivative is denoted as \(df/dt\). It measures how \(f(t)\) changes for an infinitesimal change in \(t\).
For a function \(f(t)\), the derivative is denoted as \(df/dt\). It measures how \(f(t)\) changes for an infinitesimal change in \(t\).
- If the derivative is positive, the function is increasing.
- If the derivative is negative, the function is decreasing.
Differentiation
Differentiation is the action of calculating a derivative. It's the process of finding how a function changes at any point, visually interpreted as the slope of the tangent line to the function's graph.
- This requires a function to be well-behaved, meaning it must be continuous and smooth where you intend to differentiate it.
- Some primary differentiation techniques include power, product, quotient, and chain rules.
Limit
A limit is a fundamental concept in calculus, and it is used to define derivatives. The limit describes the value that a function approaches as the input approaches a specific point.
Understanding limits grants insight into the behavior of functions at points of discontinuity or where the function's behavior sharply changes.
The derivative of a function \(f(t)\) is defined as:\[\frac{df}{dt} = \lim_{\Delta t \to 0} \frac{\Delta f}{\Delta t}\] This describes the derivative as the limiting value of the average rate of change of the function as the interval \(\Delta t\) becomes infinitesimally small. The idea of limits is crucial as it underlies differentiation and helps solve problems regarding continuity and convergence.
Understanding limits grants insight into the behavior of functions at points of discontinuity or where the function's behavior sharply changes.
The derivative of a function \(f(t)\) is defined as:\[\frac{df}{dt} = \lim_{\Delta t \to 0} \frac{\Delta f}{\Delta t}\] This describes the derivative as the limiting value of the average rate of change of the function as the interval \(\Delta t\) becomes infinitesimally small. The idea of limits is crucial as it underlies differentiation and helps solve problems regarding continuity and convergence.
Constant multiple rule
The constant multiple rule is a basic but powerful differentiation rule. It allows you to pull constants out of a derivative operation.
If given a function \(f(t)\) scaled by a constant \(c\), the derivative \(\frac{d}{dt}[c \cdot f(t)]\) becomes \(c \cdot \frac{df}{dt}\). This means:
If given a function \(f(t)\) scaled by a constant \(c\), the derivative \(\frac{d}{dt}[c \cdot f(t)]\) becomes \(c \cdot \frac{df}{dt}\). This means:
- The constant \(c\) multiplies the derivative just like it multiplies the function.
- This rule simplifies the differentiation process when functions are scaled by constants.
Other exercises in this chapter
Problem 17
Find the derivatives of the functions in \(1-26\). $$ \sec ^{2} x-\tan ^{2} x $$
View solution Problem 17
For \(y=x^{3}+4 x^{2}-3 x+1,\) find all points where the tangent is horizontal.
View solution Problem 18
Find the limits if they exist. An \(\varepsilon-\delta\) test is not required. $$ \lim _{x \rightarrow 5} \frac{x^{2}-25}{x-5} $$
View solution Problem 18
When \(f\) is in feet and \(t\) is in seconds, what are the units of \(f^{\prime}\) and its derivative \(f^{\prime \prime \prime}\) ? In \(f=16 t-16 t^{2},\) th
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