Problem 17
Question
The sum of the measures of the angles of any triangle is \(180^{\circ} .\) In \(\Delta A B C, \angle A\) measures \(100^{\circ}\) less than the sum of the measures of \(\angle B\) and \(\angle C,\) and the measure of \(\angle C\) is \(40^{\circ}\) less than twice the measure of \(\angle B .\) Find the measure of each angle of the triangle.
Step-by-Step Solution
Verified Answer
Angle A is \(40^{\circ}\), angle B is \(60^{\circ}\), angle C is \(80^{\circ}\).
1Step 1: Understand the problem
We need to find the measures of angles \(\angle A\), \(\angle B\), and \(\angle C\) in triangle \(\Delta ABC\). We know two key facts: The sum of all angles in a triangle equals \(180^{\circ}\), \(\angle A\) is \(100^{\circ}\) less than the sum of \(\angle B\) and \(\angle C\), and \(\angle C\) is \(40^{\circ}\) less than twice \(\angle B\).
2Step 2: Express relationships as equations
Let the measures of angles \(B\) and \(C\) be \(b\) and \(c\) respectively. According to the problem, \(A = (b + c) - 100^{\circ}\) and \(c = 2b - 40^{\circ}\). Also, \(a + b + c = 180^{\circ}\). We'll use these equations to find each angle.
3Step 3: Substitute and eliminate
Substitute \(c = 2b - 40^{\circ}\) into the equation \(a = b + c - 100^{\circ}\) to express \(a\) in terms of \(b\): \[ a = b + (2b - 40) - 100 = 3b - 140^{\circ} \].
4Step 4: Form a single equation in one variable
Now substitute \(a = 3b - 140^{\circ}\) and \(c = 2b - 40^{\circ}\) into \(a + b + c = 180^{\circ}\): \[ (3b - 140) + b + (2b - 40) = 180 \] Simplify to form the equation: \[ 6b - 180 = 180 \].
5Step 5: Solve for angle B
Add \(180\) to both sides to isolate \(b\): \[ 6b = 360 \] Divide both sides by 6 to find \(b\): \[ b = 60^{\circ} \].
6Step 6: Find angle C using B's value
Substitute \(b = 60^{\circ}\) back into \(c = 2b - 40^{\circ}\): \[ c = 2(60) - 40 = 120 - 40 = 80^{\circ} \].
7Step 7: Find angle A using B and C's values
Use the expression \(a = 3b - 140^{\circ}\) or \(a = b + c - 100^{\circ}\) with \(b = 60^{\circ}\) and \(c = 80^{\circ}\): \[ a = 60 + 80 - 100 = 40^{\circ} \].
8Step 8: Verify the angle sum
Check if \(a + b + c = 180^{\circ}\): \[ 40 + 60 + 80 = 180 \]. This confirms the calculations and verifies the solution.
Key Concepts
Solving EquationsTriangle PropertiesAngle Relationships
Solving Equations
Solving equations is a fundamental skill in mathematics, particularly when analyzing geometric relationships. In order to determine unknown values, we translate the given conditions of a problem into mathematical equations.
In this exercise, we are tasked with finding the measures of the angles in triangle \(\Delta ABC\). Given the relationships between the angles, our first step is to express these conditions as equations.
In this exercise, we are tasked with finding the measures of the angles in triangle \(\Delta ABC\). Given the relationships between the angles, our first step is to express these conditions as equations.
- Equation 1: Reflects that \(\angle A\) is \(100^{\circ}\) less than the sum of \(\angle B\) and \(\angle C\): \(A = (b + c) - 100^{\circ}\).
- Equation 2: Tells us \(\angle C\) is \(40^{\circ}\) less than twice \(\angle B\): \(c = 2b - 40^{\circ}\).
- Equation 3: Represents the triangle angle sum property: \(a + b + c = 180^{\circ}\).
Triangle Properties
Triangles have unique properties that define their behavior and allow us to solve for unknowns. One such critical property is the Triangle Angle Sum Property. This property states that the sum of the interior angles of any triangle is always \(180^{\circ}\).
When dealing with triangle problems, understanding and leveraging these intrinsic properties is crucial:
When dealing with triangle problems, understanding and leveraging these intrinsic properties is crucial:
- Angle Sum: The three interior angles \(a\), \(b\), and \(c\) of triangle \(\Delta ABC\) add up to \(180^{\circ}\).
- Types of Angles: While considering the type of triangle formed, knowing whether the triangle is acute, obtuse, or right can help predict what the angle measures might be.
Angle Relationships
Understanding angle relationships enables us to link given conditions to mathematical expressions. In the context of a triangle, these relationships often involve comparisons between angles, which can provide insights into their absolute measures.
In our exercise, we have:
In our exercise, we have:
- \(\angle A\) is described in relation to the sum of \(\angle B\) and \(\angle C\). This provides a relational expression aiding in solving for \(\angle A\): \(A = (b + c) - 100^{\circ}\).
- \(\angle C\) is positioned relative to \(\angle B\), allowing the expression \(c = 2b - 40^{\circ}\).
Other exercises in this chapter
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