Problem 17
Question
The ratio of neutrons to protons in stable nuclei increases with increasing atomic number. Use this trend to explain why multiple \(\alpha\) decay steps in the \(^{238} \mathrm{U}\) decay series are often followed by \(\beta\) decay.
Step-by-Step Solution
Verified Answer
Answer: Multiple alpha decay steps in the Uranium-238 decay series are often followed by beta decay due to the trend of increasing neutron to proton ratio in stable nuclei. As the decay process continues, the nuclei need to reach a more suitable neutron to proton ratio. Beta decay helps the resulting nucleus to achieve a more stable configuration by transforming a neutron into a proton, increasing the atomic number while maintaining the neutron to proton ratio, and providing the required conditions for the stability of the nucleus.
1Step 1: Understanding the trend in stable nuclei
For stable nuclei, the ratio of neutrons to protons increases as atomic number increases. This is because of the increasing effect of the electrostatic repulsion between protons in the nucleus. As the atomic number increases, more protons are added to the nucleus and the electrostatic force between them also increases. Hence, more neutrons are required to maintain the balance and keep the nucleus stable.
2Step 2: Defining alpha and beta decay
Alpha decay occurs when a nucleus emits an alpha particle, which consists of 2 protons and 2 neutrons (a helium nucleus). When a nucleus undergoes alpha decay, it loses 2 protons and 2 neutrons, resulting in a lower atomic number and mass number.
Beta decay occurs when a nucleus transforms a neutron into a proton and emits an electron (beta particle). In this process, the mass number of the nucleus remains unchanged, but the atomic number increases by 1 because a neutron is converted into a proton.
3Step 3: The Uranium-238 decay series
The decay series of Uranium-238 involves multiple alpha decay steps followed by beta decay. As Uranium-238 undergoes successive alpha decays, the atomic number and mass number of the resulting nuclei decrease. After each alpha decay, based on specific nuclei properties, the newly formed nucleus may be unstable. Instead of undergoing further alpha decay, the nucleus can undergo beta decay, which increases the atomic number without affecting mass number, in order to reach a more stable configuration.
4Step 4: Connecting the trend and decay process
Due to the trend of increasing neutron to proton ratio in stable nuclei, as the decay process continues, the nuclei need to reach a more suitable neutron to proton ratio. Beta decay helps the resulting nucleus to achieve a more stable configuration. By transforming a neutron into a proton, it increases the atomic number while maintaining the neutron to proton ratio, thus providing the required conditions for the stability of the nucleus. This is why multiple alpha decay steps in the Uranium-238 decay series are often followed by beta decay.
Other exercises in this chapter
Problem 15
How can the belt of stability be used to predict the probable decay mode of an unstable nuclide?
View solution Problem 16
Compare and contrast positron-emission and electron-capture processes.
View solution Problem 20
Write a balanced nuclear equation for a. Beta emission by \(^{161} \mathrm{Tb}\) b. Alpha emission by \(^{255} \mathrm{Lr}\) c. Electron capture by \(^{67} \mat
View solution Problem 21
If the mass number of an isotope is more than twice the atomic number, is the neutron-to-proton ratio less than greater than, or equal to \(1 ?\)
View solution