Problem 17
Question
The number of solutions of equations \(x_{2}-x_{3}=1,-x_{1}+\) \(2 x_{3}=2, x_{1}-2 x_{2}=3\) is (A) zero (B) one (C) two (D) infinite
Step-by-Step Solution
Verified Answer
The system of equations has zero solutions.
1Step 1: Write the System of Equations
The given equations are:1. \(x_2 - x_3 = 1\)2. \(-x_1 + 2x_3 = 2\)3. \(x_1 - 2x_2 = 3\)
2Step 2: Use Substitution or Elimination Methods
First, solve equation 1 for \(x_2\):\(x_2 = x_3 + 1\).Substitute \(x_2 = x_3 + 1\) in equation 3 to express \(x_1\) in terms of \(x_3\).
3Step 3: Solve for \(x_1\)
Substitute \(x_2 = x_3 + 1\) into the third equation:\(x_1 - 2(x_3 + 1) = 3\)Simplify:\(x_1 - 2x_3 - 2 = 3\)\(x_1 - 2x_3 = 5\).
4Step 4: Compare Modified System
Now compare the modified equations:Equation 2: \(-x_1 + 2x_3 = 2\)New equation from 3: \(x_1 - 2x_3 = 5\)Add these two equations: \(0 = 7\), a contradiction.
5Step 5: Determine the Number of Solutions
Since the resulting equation \(0 = 7\) is a contradiction, it indicates the system of equations is inconsistent. Therefore, there are no solutions.
Key Concepts
Substitution MethodElimination MethodInconsistent System
Substitution Method
The substitution method is a way to solve a system of linear equations. It involves solving one equation for one variable and then substituting this expression into the other equations. This method simplifies the system by reducing the number of equations and unknowns.
Here’s a simple way to understand substitution:
Here’s a simple way to understand substitution:
- First, isolate one variable in one of the equations. In our case, equation 1 (\(x_2 - x_3 = 1\)) is chosen, and we solve for \(x_2\). This gives \(x_2 = x_3 + 1\).
- Next, substitute this expression into the other equations. For example, in equation 3 (\(x_1 - 2x_2 = 3\)), substitute \(x_2 = x_3 + 1\).
- This substitution allows us to express \(x_1\) in terms of \(x_3\). After simplifying, we find that \(x_1 - 2x_3 = 5\).
Elimination Method
The elimination method is another technique to solve systems of linear equations. It focuses on removing one variable by adding or subtracting equations, making it possible to solve for the remaining variables.
Here's a step-by-step process:
Here's a step-by-step process:
- Choose two equations from your system. In this case, we have equation 2 (\(-x_1 + 2x_3 = 2\)) and the modified equation 3 (\(x_1 - 2x_3 = 5\)).
- Add these equations together. This step helps eliminate one of the variables. For our example, adding the equations \(-x_1 + 2x_3 = 2\) and \(x_1 - 2x_3 = 5\) results in \(0 = 7\).
- Notice any contradictions or new discoveries about the system’s consistency. The contradiction, \(0 = 7\), signals that the system is inconsistent, meaning no solutions exist for these equations.
Inconsistent System
An inconsistent system of linear equations is one where no set of values for the variables can satisfy all the equations simultaneously. In simpler terms, the equations contradict each other, making it impossible to find a common solution.
Understanding the concept:
Understanding the concept:
- Recognize an inconsistency by searching for contradictions. In our previous steps, after applying substitution and elimination, we encountered the contradiction \(0 = 7\).
- This contradiction implies that the equations are not logically compatible. They aim to describe conditions that can't simultaneously be true.
- Such scenarios usually emerge when two lines represented by the equations are parallel and never intersect in a two-dimensional plane.
Other exercises in this chapter
Problem 15
For each real number \(x\) such that \(-1
View solution Problem 16
The inverse of a skew symmetric matrix of odd order is (A) a symmetric matrix (B) a skew symmetric matrix (C) diagonal matrix (D) does not exist
View solution Problem 18
If \(\left[\begin{array}{cc}\alpha & \beta \\ \gamma & -\alpha\end{array}\right]\) is to be the square root of two-rowed unit matrix, then \(\alpha, \beta\) and
View solution Problem 19
Let \(A\) and \(B\) be two symmetric matrices of order 3 . Statement 1: \(A(B A)\) and \((A B) A\) are symmetric matrices. Statement \(2: A B\) is symmetric mat
View solution