Problem 17
Question
Telephone and electrical lines are allowed to sag between poles so that the tension will not be too great when something hits or sits on the line. (a) Is it possible to have the lines perfectly horizontal? Why or why not? (b) Suppose that a line were stretched almost perfectly horizontally between two poles that are \(30 \mathrm{~m}\) apart. If a \(0.25-\mathrm{kg}\) bird perches on the wire midway between the poles and the wire sags \(1.0 \mathrm{~cm},\) what would be the tension in the wire? (Neglect the mass of the wire.)
Step-by-Step Solution
Verified Answer
(a) No, perfectly horizontal lines require infinite tension. (b) The tension is approximately 3675 N.
1Step 1: Understanding Tension and Angle
For perfectly horizontal lines, the angle of sag would be zero. If the line cannot be horizontal, it suggests that no finite tension could support any load at zero angle, as it would require an infinite tension force to counteract any additional weight or force applied onto the line.
2Step 2: Analyzing Forces on the Wire (Part B)
We assume the center of the wire sags by 1 cm due to the weight of a bird. This creates a right angle triangle with the sag and half the distance between poles (30/2 = 15 m) as legs. Applying trigonometry, the horizontal tension forces balance the bird's downward force.
3Step 3: Calculating Sag Component
We use the vertical component of the tension (T_y) and equate it to the bird's weight. If T is the tension in the wire, then T_y can be expressed by trigonometric relations as T sin(θ). The angle θ can be calculated using sag and half the distance (0.01 m/15 m = tan(θ)).
4Step 4: Calculating Bird's Weight
The bird's weight (W) is calculated using W = mg, where m = 0.25 kg and g = 9.81 m/s². Therefore, W = 0.25 kg * 9.81 m/s² = 2.4525 N.
5Step 5: Using Trigonometric Relations
With tan(θ) = opposite/adjacent = 0.01 m / 15 m, we find sin(θ) ≈ tan(θ) ≈ 0.01/15. We estimate sin(θ) = 0.000667 since the sag is small.
6Step 6: Solving for Tension in the Wire
Equating T_y to the bird's weight: T · 0.000667 = 2.4525 N. Solving for T, we get T ≈ 2.4525 / 0.000667 ≈ 3675 N.
Key Concepts
Sag tension problemTrigonometrical analysis in physicsPhysics problem-solving stepsBird's weight calculation
Sag tension problem
In the context of physics, when we talk about tension in wires or ropes, it's crucial to consider the concept of sag tension. This tension is particularly important in situations where wires or ropes are used to span distances, such as between telephone poles or electricity towers. Sag happens because gravity pulls down on the line, creating a natural curve. Not allowing a line to sag would mean it needs to be perfectly straight, requiring infinite tension to support any weight on it. This is why you never see perfectly horizontal wires; they couldn't physically handle the added weight without breaking.
Trigonometrical analysis in physics
Trigonometry is a powerful tool in physics used to analyze forces in cases like the sag tension problem. When a bird perches on a wire, the sag creates a right triangle where:
- One leg is the sag amount (in this case, 1 cm or 0.01 m),
- The other is half the distance between the poles, 15 m.
Physics problem-solving steps
Solving physics problems involves a systematic approach to understanding and calculating relevant quantities. In this exercise, we followed several key steps:
- First, comprehend the limitation of perfectly horizontal lines and why some sag is necessary.
- Next, relate the forces acting on the system, like how the bird contributes to the sag by providing a downward force.
- Then, break down these forces using trigonometry to find the relationship between the wire's tension and the bird's weight.
- Finally, calculate the necessary quantities, like the angle and the tension, to fully understand the physics of the problem.
Bird's weight calculation
To understand the effect a bird has on a wire, you must first calculate its weight. Weight is determined using the formula: \[ W = mg \]where \( m \) is the mass (0.25 kg for our bird) and \( g \) is the acceleration due to gravity (9.81 m/s² on Earth). Put these together, and you calculate the bird's weight:\[ W = 0.25 \times 9.81 = 2.4525 \text{ N} \]This number helps us quantify the force the bird applies downwards on the wire, a necessary step to figure out how much tension the wire will experience. Knowing the bird's weight allows you to equate it to the vertical component of tension (\( T_y \)) and use trigonometry to solve for the total tension in the wire, as we did in this exercise.
Other exercises in this chapter
Problem 13
Two children are sitting on opposite ends of a uniform seesaw of negligible mass. (a) Can the seesaw be balanced if the masses of the children are different? Ho
View solution Problem 14
A uniform meterstick pivoted at its center, as in Example 8.5 , has a 100 -g mass suspended at the 25.0 -cm position. (a) At what position should a 75.0 - \(\ma
View solution Problem 20
A bowling ball (mass \(7.00 \mathrm{~kg}\) and radius \(17.0 \mathrm{~cm}\) ) is released so fast that it skids without rotating down the lane (at least for a w
View solution Problem 25
(a) How many uniform, identical textbooks of width \(25.0 \mathrm{~cm}\) can be stacked on top of each other on a level surface without the stack falling over i
View solution