Problem 17
Question
Solve the given system of differential equations by systematic elimination. $$ \begin{aligned} &D x=y \\ &D y=z \\ &D z=x \end{aligned} $$
Step-by-Step Solution
Verified Answer
The solutions are \( x(t) = c_1 e^t + c_2 e^{-\frac{1}{2}t} \cos(\frac{\sqrt{3}}{2}t) + c_3 e^{-\frac{1}{2}t} \sin(\frac{\sqrt{3}}{2}t) \), with \( y(t) \) and \( z(t) \) derived from it.
1Step 1: Equate the Derivatives
First, we write down the system of equations given in terms of derivatives: \( Dx = y \) \( Dy = z \) \( Dz = x \). Our goal is to systematically eliminate variables to find a single equation involving only one of the variables.
2Step 2: Eliminate y
Take the derivative of the equation \( Dx = y \), which gives us \( D^2x = Dy \). Using the second equation \( Dy = z \), substitute \( D^2x = z \). Now, we have two equations: \( D^2x = z \) \( Dz = x \).
3Step 3: Substitute to Find Single Variable Equation
Substitute \( z \) from \( D^2x = z \) into \( Dz = x \) to obtain \( D(D^2x) = x \). This simplifies to the third derivative equation: \( D^3x = x \).
4Step 4: Solve the Single Differential Equation
The equation \( D^3x = x \) is a third-order ordinary differential equation. The characteristic equation is \( r^3 = 1 \). The roots of this equation are \( r = 1, -\frac{1}{2} + i\frac{\sqrt{3}}{2}, -\frac{1}{2} - i\frac{\sqrt{3}}{2} \).
5Step 5: Write the General Solution for x
From the characteristic equation, the solution for \( x(t) \) can be written as: \( x(t) = c_1 e^{t} + c_2 e^{-\frac{1}{2}t} \cos(\frac{\sqrt{3}}{2}t) + c_3 e^{-\frac{1}{2}t} \sin(\frac{\sqrt{3}}{2}t) \), where \( c_1, c_2, \) and \( c_3 \) are constants.
6Step 6: Find Solutions for y and z
Now, use the relationships \( Dx = y \) and \( Dy = z \) to find \( y(t) \) and \( z(t) \): - Differentiate \( x(t) \) to get \( y(t) \). - Differentiate \( y(t) \) to obtain \( z(t) \).
Key Concepts
Systematic EliminationOrdinary Differential EquationCharacteristic EquationGeneral Solution
Systematic Elimination
Systematic elimination is a method used to solve a system of equations by reducing the number of variables one by one until you are left with an equation involving only a single variable. This process simplifies the system, allowing for easier integration and solution.
- Start by organizing the equations so they contain variables to be eliminated sequentially.
- Take derivatives of the equations as necessary to match variables and eliminate step by step.
- Transform the system into a single differential equation.
Ordinary Differential Equation
An ordinary differential equation (ODE) is an equation containing a function of one independent variable and its derivatives. The derivatives indicate the rate of change.
In our system, we are working with a third-order ODE: \( D^3x = x \). Here, the third derivative of \( x \) is equal to \( x \) itself.
In our system, we are working with a third-order ODE: \( D^3x = x \). Here, the third derivative of \( x \) is equal to \( x \) itself.
- Ordinary Differential Equations involve only one independent variable.
- They can be first, second, or even higher order, indicating the highest derivative present in the equation.
- ODEs describe dynamic systems and can model phenomena in physics, engineering, and other fields.
Characteristic Equation
The characteristic equation arises from an ordinary differential equation by assuming a trial solution of exponential form, typically \( x(t) = e^{rt} \), where \( r \) represents a constant.
In our case, from \( D^3x = x \), the trial leads to the characteristic equation \( r^3 = 1 \). To find solutions:
In our case, from \( D^3x = x \), the trial leads to the characteristic equation \( r^3 = 1 \). To find solutions:
- Solve for the roots of the polynomial equation.
- The nature of roots (real and distinct, real and repeated, or complex) will indicate different forms of the solution.
General Solution
The general solution of a differential equation takes into account all possible solutions that satisfy the equation, using the different roots found from the characteristic equation.
For the third-order ODE \( D^3x = x \), we found roots \( 1 \), \( -\frac{1}{2} + i\frac{\sqrt{3}}{2} \), and \( -\frac{1}{2} - i\frac{\sqrt{3}}{2} \). The general solution for \( x(t) \) becomes:
For the third-order ODE \( D^3x = x \), we found roots \( 1 \), \( -\frac{1}{2} + i\frac{\sqrt{3}}{2} \), and \( -\frac{1}{2} - i\frac{\sqrt{3}}{2} \). The general solution for \( x(t) \) becomes:
- \( x(t) = c_1 e^t + c_2 e^{-\frac{1}{2}t} \cos(\frac{\sqrt{3}}{2}t) + c_3 e^{-\frac{1}{2}t} \sin(\frac{\sqrt{3}}{2}t) \)
- The constants \( c_1 \), \( c_2 \), and \( c_3 \) are determined by initial conditions or boundary values.
Other exercises in this chapter
Problem 17
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In calculus, the curvature of a curve that is defined by a function \(y=f(x)\) is defined as $$ \kappa=\frac{y^{\prime \prime}}{\left[1+\left(y^{\prime}\right)^
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Solve the given differential equation. $$ x y^{(4)}+6 y^{\prime \prime \prime}=0 $$
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