Problem 17
Question
Solve the equation. $$ |x-1|=|3 x+2| $$
Step-by-Step Solution
Verified Answer
The solutions are \(x = -\frac{3}{2}\) and \(x = -\frac{1}{4}\).
1Step 1: Understanding Absolute Value Equation
The equation given is \(|x-1| = |3x+2|\). Absolute value expressions can be solved by considering both the positive and negative scenarios.
2Step 2: Case 1: Positive Scenario
In the positive scenario, assume both expressions inside the absolute values are positive or equal. This means we solve \(x-1 = 3x+2\).
3Step 3: Solve Equation for Case 1
Starting with \(x - 1 = 3x + 2\), subtract \(x\) from both sides to get \(-1 = 2x + 2\). Then, subtract \(2\) from both sides to obtain \(-3 = 2x\). Finally, divide both sides by \(2\) to find \(x = -\frac{3}{2}\).
4Step 4: Case 2: Negative Scenario
In the negative scenario, assume one expression inside the absolute value is negative while the other is positive. Consider \(x-1 = -(3x+2)\).
5Step 5: Solve Equation for Case 2
Starting with \(x - 1 = -3x - 2\), add \(3x\) to both sides to get \(4x - 1 = -2\). Then, add \(1\) to both sides for \(4x = -1\). Divide by \(4\) to solve for \(x = -\frac{1}{4}\).
6Step 6: Verification of Solutions
Verify the solutions \(x = -\frac{3}{2}\) and \(x = -\frac{1}{4}\) into the original equation \(|x-1| = |3x+2|\). Both satisfy the equation: \(|-\frac{5}{2}| = |-\frac{7}{2}|\) and \(|-\frac{5}{4}| = |-\frac{1}{4}|\) respectively.
Key Concepts
Positive and Negative ScenariosSolving Linear EquationsVerification of Solutions
Positive and Negative Scenarios
When solving absolute value equations, it is important to consider all possible cases. The expression \(|x-1| = |3x+2|\) implies that the contents within each absolute value could be either both positive, both negative, or one positive and the other negative. Understanding these scenarios aids in crafting the correct method to solve the equation.
Understanding these scenarios is key because they define the domain over which different expressions can operate, covering all potential outcomes.
- **Positive scenario:** Both expressions \((x-1)\) and \((3x+2)\) are either equal or positive.
- **Negative scenario:** One expression is positive while the other is negative, creating an opposite balance.
Understanding these scenarios is key because they define the domain over which different expressions can operate, covering all potential outcomes.
Solving Linear Equations
Once the scenarios are clearly laid out, the next step involves solving the linear equations formed in each case. Let's delve into the steps needed for solving these equations.
In the *positive scenario*, we form the equation \(x-1 = 3x+2\). To solve, manipulate the terms to isolate \(x\). This involves:
In the *negative scenario*, we use \(x-1 = -(3x+2)\). The steps are similar, yet different equations:
In the *positive scenario*, we form the equation \(x-1 = 3x+2\). To solve, manipulate the terms to isolate \(x\). This involves:
- Subtracting \(x\) from both sides to get \(-1 = 2x + 2\).
- Subtracting \(2\) from both sides to result in \(-3 = 2x\).
- Finally, dividing both sides by \(2\) to solve for \(x = -\frac{3}{2}\).
In the *negative scenario*, we use \(x-1 = -(3x+2)\). The steps are similar, yet different equations:
- Add \(3x\) to both sides yielding \(4x - 1 = -2\).
- Add \(1\) to both sides to have \(4x = -1\).
- Finally, divide by \(4\) to find \(x = -\frac{1}{4}\).
Verification of Solutions
Verification is a crucial step after obtaining solutions in any equation, especially for absolute value problems. It ensures that the derived solutions actually satisfy the original equation.
For our solutions, \(x = -\frac{3}{2}\) and \(x = -\frac{1}{4}\), we plug them back into the equation \(|x-1| = |3x+2|\) to verify:
For our solutions, \(x = -\frac{3}{2}\) and \(x = -\frac{1}{4}\), we plug them back into the equation \(|x-1| = |3x+2|\) to verify:
- For \(x = -\frac{3}{2}\): Substitute into the equation:
\(|-\frac{5}{2}| = |\frac{-9 + 2}{2}| = |-\frac{7}{2}|\)
Both sides equate to \(\frac{5}{2}\), thus verifying this is a correct solution. - For \(x = -\frac{1}{4}\): Again, substitute:
\(|-\frac{5}{4}| = |-\frac{1}{4}|\)
Both calculate to \(\frac{5}{4}\), confirming \(x = -\frac{1}{4}\) as a valid solution.
Other exercises in this chapter
Problem 16
Solve the equation by completing the square. \(x^{2}+3 x-\frac{7}{4}=0\)
View solution Problem 16
\(9- 46\) The given equation is either linear or equivalent to a linear equation. Solve the equation. $$ 5 t-13=12-5 t $$
View solution Problem 17
Salaries An executive in an engineering firm earns a monthly salary plus a Christmas bonus of \(\$ 8500\) . If she earns a total of \(\$ 97,300\) per year, what
View solution Problem 17
\(9-32\) me solve the linear inequality. Express the solution using interval notation and graph the solution set. $$ 3 x+11 \leq 6 x+8 $$
View solution