Problem 17
Question
Solve each exponential equation by expressing each side as a power of the same base and then equating exponents. $$4^{x}=\frac{1}{\sqrt{2}}$$
Step-by-Step Solution
Verified Answer
The solution to the equation \(4^{x}=\frac{1}{\sqrt{2}}\) is \(x = -\frac{1}{4}\)
1Step 1: Converting to the same base
Express both sides of the equation as a power of 2. Since 4 is \(2^2\), write \(4^{x}\) as \((2^2)^x\). The right side expression, \(\frac{1}{\sqrt{2}}\), can also be written as \(2^{-\frac{1}{2}}\). This leads to \((2^2)^x = 2^{-\frac{1}{2}}\).
2Step 2: Simplify the power expression
Next, simplify the left side of the expression using the power of power rule, which says that \((a^m)^n = a^{mn}\). So, we have \(2^{2x} = 2^{-\frac{1}{2}}\). Now both sides of the equation are expressed as a power of 2.
3Step 3: Equating the Exponents
Since both sides have the same base, the exponents must also be equal to each other. Set the exponents equal to each other and solve for x, yielding \(2x = -\frac{1}{2}\). Solving for x gives us \(x = -\frac{1}{4}\).
Other exercises in this chapter
Problem 16
Use properties of logarithms to expand each logarithmic expression as much as possible. Where possible, evaluate logarithmic expressions without using a calcula
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Write each equation in its equivalent logarithmic form. $$15^{2}=x$$
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Write each equation in its equivalent logarithmic form. $$b^{3}=1000$$
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Use properties of logarithms to expand each logarithmic expression as much as possible. Where possible, evaluate logarithmic expressions without using a calcula
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