Problem 17
Question
Solve each equation. $$ \log _{4} 2+\log _{4} x=0 $$
Step-by-Step Solution
Verified Answer
The solution is \( x = \frac{1}{2} \).
1Step 1: Use the Logarithm Addition Property
We start with the equation: \( \log_{4} 2 + \log_{4} x = 0 \). By applying the logarithm addition property, \( \log_{a} b + \log_{a} c = \log_{a}(b \cdot c) \), we combine the logs: \( \log_{4} (2x) = 0 \).
2Step 2: Convert Logarithmic Equation to Exponential Form
Next, we need to convert the logarithmic equation \( \log_{4} (2x) = 0 \) into its exponential form. By definition, if \( \log_{a} b = c \), then \( a^c = b \). Therefore, \( 4^0 = 2x \).
3Step 3: Solve the Exponential Equation
We have the equation \( 4^0 = 2x \). Since \( 4^0 = 1 \), we have \( 1 = 2x \). Dividing both sides by 2 gives us \( x = \frac{1}{2} \).
Key Concepts
Logarithm Addition PropertyExponential FormSolving Equations
Logarithm Addition Property
When dealing with logarithms, the addition property is a handy tool that helps simplify equations. If you encounter an equation like \( \log_{a} b + \log_{a} c \), you can combine the two logs by using the property that states:
For example, in the exercise \( \log_{4} 2 + \log_{4} x = 0 \), you can merge the logs into:
\( \log_{4} (2x) = 0 \).
Knowing how to use the logarithm addition property allows you to simplify complex logarithmic expressions, making it easier to solve them.
- \( \log_{a} b + \log_{a} c = \log_{a}(b \cdot c) \)
For example, in the exercise \( \log_{4} 2 + \log_{4} x = 0 \), you can merge the logs into:
\( \log_{4} (2x) = 0 \).
Knowing how to use the logarithm addition property allows you to simplify complex logarithmic expressions, making it easier to solve them.
Exponential Form
Converting a logarithmic equation to its exponential form is a crucial step in solving it. The logarithmic form \( \log_{a} b = c \) can be rewritten as an exponential equation:
In our example, after using the logarithm addition property, we end up with the equation \( \log_{4} (2x) = 0 \). By converting into exponential form, we express this as:
\( 4^0 = 2x \).
Understanding exponential form is key, as it reveals the corresponding relationship between the components of the logarithm, thereby simplifying the path to find the solution.
- \( a^c = b \)
In our example, after using the logarithm addition property, we end up with the equation \( \log_{4} (2x) = 0 \). By converting into exponential form, we express this as:
\( 4^0 = 2x \).
Understanding exponential form is key, as it reveals the corresponding relationship between the components of the logarithm, thereby simplifying the path to find the solution.
Solving Equations
Once an equation is simplified and transformed, solving it becomes a straightforward process. For the exponential form \( 4^0 = 2x \), it helps to remember that any non-zero number raised to the power of zero is 1:
To isolate \(x\), divide both sides of the equation by 2, resulting in:
- \( 4^0 = 1 \)
To isolate \(x\), divide both sides of the equation by 2, resulting in:
- \( x = \frac{1}{2} \)
Other exercises in this chapter
Problem 16
Graph each exponential function. $$ y=\left(\frac{1}{2}\right)^{x}+2 $$
View solution Problem 16
Write each difference as a single logarithm. Assume that variables represent positive numbers. $$ \log _{7}(x+9)-\log _{7}\left(x^{2}+10\right) $$
View solution Problem 17
Write each as a logarithmic equation. $$ 2^{4}=16 $$
View solution Problem 17
Solve. Unless noted otherwise, round answers to the nearest whole. National Park Service personnel are trying to increase the size of the bison population of Th
View solution