Problem 17
Question
Solve each equation. For equations with real solutions, support your answers graphically. $$x^{2}=-16$$
Step-by-Step Solution
Verified Answer
The equation \( x^2 = -16 \) has no real solutions.
1Step 1: Analyze the Equation
The given equation is \( x^2 = -16 \). This is a quadratic equation where the variable \( x \) is squared.
2Step 2: Consider Real Solutions
For an equation of the form \( x^2 = a \), if \( a < 0 \), there are no real solutions because the square of any real number is non-negative.
3Step 3: Explain with Graphical Insight
Since the function \( x^2 \) represents a parabola opening upwards, it never reaches negative values. Thus, the graph of \( y = x^2 \) will not intersect the line \( y = -16 \), confirming there are no real solutions.
Key Concepts
Real Solutions in Quadratic EquationsParabola and its Graphical RepresentationGraphical Analysis of Quadratic Equations
Real Solutions in Quadratic Equations
In the context of quadratic equations, a 'real solution' refers to the value(s) of the variable that satisfy the equation, where the variable encodes a real number. For a quadratic equation of the form \[ ax^2 + bx + c = 0 \]to have real solutions, the discriminant, calculated as \( b^2 - 4ac \), must be greater than or equal to zero. If the discriminant is positive, there are two distinct real solutions. If it is zero, there is one real solution.
Quadratic equations like \( x^2 = -16 \), pose a unique challenge because when the constant term is negative, the equation suggests that the square of a number is negative. Since the square of any real number is always non-negative, such an equation does not have real solutions. This concept plays a central role in determining the nature of the solutions without needing to solve the equation explicitly.
When faced with a negative constant in a quadratic expression set equal to zero, it's important to recognize that real solutions are impossible, indicating the non-existence of an intersection between the function (in this case \( x^2 \)) and the proposed value (\(-16\)).
Quadratic equations like \( x^2 = -16 \), pose a unique challenge because when the constant term is negative, the equation suggests that the square of a number is negative. Since the square of any real number is always non-negative, such an equation does not have real solutions. This concept plays a central role in determining the nature of the solutions without needing to solve the equation explicitly.
When faced with a negative constant in a quadratic expression set equal to zero, it's important to recognize that real solutions are impossible, indicating the non-existence of an intersection between the function (in this case \( x^2 \)) and the proposed value (\(-16\)).
Parabola and its Graphical Representation
A parabola is a U-shaped curve that represents the graph of a quadratic function. The standard equation of a parabola is \[ y = ax^2 + bx + c \]. This curve can either open upwards or downwards depending on the sign of \( a \).
When considering a simple quadratic function like \( y = x^2 \), the parabola opens upwards. This means that the value of \( y \) increases as \( x \) moves away from zero in either direction, forming the classic 'U' shape. As a result, the minimum point of an upward-opening parabola is at its vertex, where \( x = 0 \) and \( y = 0 \).
In practical terms, the graph of such a parabola never dips below the x-axis. This visual feature helps in understanding why equations like \( x^2 = -16 \) have no real solutions; the graph of \( y = x^2 \) can never meet \( y = -16 \) because negative \( y \)-values are out of reach for an upward-opening parabola.
When considering a simple quadratic function like \( y = x^2 \), the parabola opens upwards. This means that the value of \( y \) increases as \( x \) moves away from zero in either direction, forming the classic 'U' shape. As a result, the minimum point of an upward-opening parabola is at its vertex, where \( x = 0 \) and \( y = 0 \).
In practical terms, the graph of such a parabola never dips below the x-axis. This visual feature helps in understanding why equations like \( x^2 = -16 \) have no real solutions; the graph of \( y = x^2 \) can never meet \( y = -16 \) because negative \( y \)-values are out of reach for an upward-opening parabola.
Graphical Analysis of Quadratic Equations
Graphical analysis is a useful method for visualizing the solutions of quadratic equations. By plotting the graph of the quadratic function, one can easily see where, or if, the function intersects with a particular horizontal line (representing the constant or right-hand side in the equation) to determine the number and nature of real solutions.
For instance, when evaluating the equation \( x^2 = -16 \) graphically, you would plot the function \( y = x^2 \), which is a parabola opening upwards. Alongside that, plot the horizontal line \( y = -16 \). It becomes immediately apparent that these two graphs do not intersect because they are on completely separate levels; the parabola never reaches below the x-axis.
This analysis visually confirms that there are no real solutions to the equation, supplementing the algebraic understanding with a clear geometric perspective. Graphical analysis not only aids in visualizing the solutions but also reinforces the mathematical principles, enhancing comprehension through a multi-faceted approach.
For instance, when evaluating the equation \( x^2 = -16 \) graphically, you would plot the function \( y = x^2 \), which is a parabola opening upwards. Alongside that, plot the horizontal line \( y = -16 \). It becomes immediately apparent that these two graphs do not intersect because they are on completely separate levels; the parabola never reaches below the x-axis.
This analysis visually confirms that there are no real solutions to the equation, supplementing the algebraic understanding with a clear geometric perspective. Graphical analysis not only aids in visualizing the solutions but also reinforces the mathematical principles, enhancing comprehension through a multi-faceted approach.
Other exercises in this chapter
Problem 17
Determine whether each statement is true or false. If is false, tell why. Every pure imaginary number is a complex number.
View solution Problem 17
Find all complex solutions of each equation. $$x^{4}-11 x^{2}+10=0$$
View solution Problem 17
Use the intermediate value theorem to show that each function has a real zero between the two numbers given. Then, use your calculator to approximate the zero t
View solution Problem 17
Solve each problem. Hitting a Baseball A baseball is hit so that its height in feet after \(t\) seconds is $$ s(t)=-16 t^{2}+44 t+4 $$ (a) How high is the baseb
View solution