Problem 17
Question
Simplify. $$ x 2+2 x 2+3 x-28+x-22 x 2+3 x-28 $$
Step-by-Step Solution
Verified Answer
The expression simplifies to \(x^2 + 7x - 56\).
1Step 1: Combine Like Terms
Identify and combine like terms in the expression: \(x^2 + 2x^2 + 3x - 28 + x - 2x^2 + 3x - 28\). Like terms are those terms that have the same variables raised to the same powers.
2Step 2: Simplify the Polynomial Terms
First, simplify the quadratic terms: \(x^2 + 2x^2 - 2x^2\). Combine these to get \(x^2\).
3Step 3: Simplify the Linear Terms
Next, simplify the linear terms: \(3x + x + 3x\). Combine these to get \(7x\).
4Step 4: Simplify the Constant Terms
Finally, simplify the constant terms: \(-28 - 28\). Combine these to get \(-56\).
5Step 5: Write the Simplified Expression
Combine the simplified terms to write the final simplified expression: \(x^2 + 7x - 56\).
Key Concepts
Like TermsQuadratic TermsLinear TermsConstant Terms
Like Terms
When simplifying polynomials, the first thing to do is to identify like terms. Like terms in algebra are terms that have the same variable raised to the same power. This means you can combine or add them together easily.
In the given exercise, we have the expression: \(x^2 + 2x^2 + 3x - 28 + x - 2x^2 + 3x - 28\). Identify and circle the terms with the same variables and powers.
In the given exercise, we have the expression: \(x^2 + 2x^2 + 3x - 28 + x - 2x^2 + 3x - 28\). Identify and circle the terms with the same variables and powers.
- \(x^2\), \(2x^2\), and \(-2x^2\) are like terms because they all have the variable \(x\) squared.
- \(3x\), \(x\), and \(3x\) are another set of like terms; they have the variable \(x\) to the power of 1.
- -28 and -28 are also like terms, as they are constant terms.
Quadratic Terms
Quadratic terms are those that contain a variable raised to the power of two. These are important in algebra because they define the shape of a parabola on a graph.
In our example, the quadratic terms are \(x^2\), \(2x^2\), and \(-2x^2\). To simplify, add or subtract these coefficients and keep the variable and its exponent the same. Here's how it's done:
In our example, the quadratic terms are \(x^2\), \(2x^2\), and \(-2x^2\). To simplify, add or subtract these coefficients and keep the variable and its exponent the same. Here's how it's done:
- Combine: \(x^2 + 2x^2 - 2x^2\).
- The result is: \(x^2\). The coefficients (1, 2, and -2) add up to 1.
Linear Terms
Linear terms are the elements of an expression that have variables raised to the power of one. They are fundamental for defining straight lines in algebraic equations.
In the expression \(3x + x + 3x\), these are the linear terms, where the variable \(x\) is to the first power. We combine them as follows:
In the expression \(3x + x + 3x\), these are the linear terms, where the variable \(x\) is to the first power. We combine them as follows:
- Add the coefficients: \(3 + 1 + 3\).
- The sum is: \(7x\).
Constant Terms
Constant terms in a polynomial are numbers without variables. They remain constant—they do not change as the variables in an expression rise and fall.
In the expression, \(-28 - 28\) are constant terms. Simplify them as you would with simple arithmetic:
In the expression, \(-28 - 28\) are constant terms. Simplify them as you would with simple arithmetic:
- Combine these numbers: \(-28 - 28\).
- The sum is: \(-56\).
Other exercises in this chapter
Problem 16
For each problem below, approximate the weight of a 120-pound object at the given height above the surface of earth. (1 mile \(=5,280\) feet). 90,000 feet
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Solve. $$1-2 x=48 \times 2$$
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Sally was able to drive an average of 20 miles per hour faster in her car after the traffic cleared. She drove 23 miles in traffic before it cleared and then dr
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Simplify. (Assume all denominators are nonzero.) $$ 23 y-46-1 y $$
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