Problem 17
Question
Show that in an integral domain \(D\), a nonzero element \(p \in D\) is prime if and only if \(\langle p\rangle\) is a prime ideal in \(D\).
Step-by-Step Solution
Verified Answer
In an integral domain, an element is prime if its principal ideal is prime.
1Step 1: Understanding the Definitions
An integral domain is a commutative ring with no zero divisors. An element \( p \in D \) is prime if whenever \( p \) divides a product \( ab \), it divides at least one of \( a \) or \( b \). An ideal \( \langle p \rangle \) is a prime ideal if whenever a product \( ab \in \langle p \rangle \), then either \( a \in \langle p \rangle \) or \( b \in \langle p \rangle \).
2Step 2: Showing Prime Element Implies Prime Ideal
Assume \( p \) is a prime element. If a product \( ab \in \langle p \rangle \), then there exists some \( d \in D \) such that \( ab = pd \). Since \( p \) is prime and divides \( ab \), \( p \) must divide either \( a \) or \( b \). Therefore, either \( a \in \langle p \rangle \) or \( b \in \langle p \rangle \), which means \( \langle p \rangle \) is a prime ideal.
3Step 3: Showing Prime Ideal Implies Prime Element
Assume \( \langle p \rangle \) is a prime ideal. If \( p \mid ab \), then \( ab = pd \) for some \( d \). Since \( ab \in \langle p \rangle \), and \( \langle p \rangle \) is a prime ideal, \( a \in \langle p \rangle \) or \( b \in \langle p \rangle \). Thus, \( p \mid a \) or \( p \mid b \), proving \( p \) is prime.
4Step 4: Conclusion
Since both directions of implication have been established, a nonzero element \( p \in D \) is prime if and only if \( \langle p \rangle \) is a prime ideal.
Key Concepts
Integral DomainPrime IdealCommutative RingZero Divisors
Integral Domain
An integral domain is a mathematical structure that combines the features of a commutative ring with the absence of zero divisors, making it a highly consistent environment for solving problems involving division. To understand it, first know that:
- A **commutative ring** is a set equipped with two operations: addition and multiplication, where the multiplication operation is commutative, meaning for any two elements \( a \) and \( b \), \( ab = ba \).
- An integral domain takes it a step further by ensuring there are no zero divisors. This means for any non-zero elements \( a \) and \( b \) in the domain, the product \( ab e 0 \).
Prime Ideal
Prime ideals are a fascinating topic in ring theory, serving as a cornerstone for understanding various algebraic structures. To digest this, let's break down some key points:
- In a commutative ring, an **ideal** is a subset that absorbs multiplication by any element of the ring but doesn't need to include all ring elements.
- A prime ideal \( \langle p \rangle \) has an additional intriguing property: if a product of two elements \( ab \) is in the ideal, then at least one of the elements \( a \) or \( b \) must itself be in the ideal.
Commutative Ring
Commutative rings serve as a foundational structure in algebra, underpinning more complex concepts like fields and integral domains. They exhibit several critical traits:
- A commutative ring is equipped with two binary operations—addition and multiplication—that satisfy common arithmetic rules. Addition forms an abelian group and multiplication is associative and commutative.
- An important aspect is the presence of a multiplicative identity (often denoted by 1), although not all definitions require this as a component.
Zero Divisors
Zero divisors present an important concept in understanding the structure of rings and integral domains in particular. Here's what you need to know:
- A zero divisor is an element of a ring that provides a nonzero product when multiplied with another element, yet the result is zero.
- In an equation, if \( a \cdot b = 0 \) and both \( a \) and \( b \) are non-zero, then \( a \) and \( b \) are zero divisors.
Other exercises in this chapter
Problem 16
In Exercises 14 through 17 find the order and characteristic of the indicated fields. $$ \mathbb{Z}[i] /\langle 1+i\rangle $$
View solution Problem 16
Prove or disprove that for any field \(F, F[x, y]\) is a Euclidean domain.
View solution Problem 17
Let \(D\) be a Euclidean domain and \(a\) and \(b\) elements of \(D\). Show that (a) If \(a\) and \(b\) are associates, then \(v(a)=v(b)\). (b) If \(v(a)=v(b)\)
View solution Problem 18
Let \(D\) be a PID. Show that a nonzero element \(p \in D\) is irreducible in \(D\) if and only if \(p\) is prime in \(D\).
View solution