Problem 17
Question
Oxidation number of \(\mathrm{N}\) in \(\mathrm{NH}_{4} \mathrm{NO}_{3}\) is (a) \(-3\) (b) \(+5\) (c) \(-3\) and \(+5\)
Step-by-Step Solution
Verified Answer
The oxidation numbers of \(\mathrm{N}\) in \(\mathrm{NH}_4\mathrm{NO}_3\) are \(-3\) and \(+5\).
1Step 1: Understand the Compound
The compound in question is ammonium nitrate, \ \( \mathrm{NH}_4 \mathrm{NO}_3 \). This compound contains two different nitrogen atoms, one in the ammonium ion (\( \mathrm{NH}_4^+ \)) and one in the nitrate ion (\( \mathrm{NO}_3^- \)). Each nitrogen can potentially have a different oxidation state.
2Step 2: Oxidation State of Nitrogen in \( \mathrm{NH}_4^+ \)
For the ammonium ion, \( \mathrm{NH}_4^+ \), we assume the oxidation state of hydrogen is \(+1\), as it is typically in most compounds. Let \( x \) be the oxidation state of nitrogen in \( \mathrm{NH}_4^+ \). The formula for the charge balance in the ion is: \ \[ x + 4(+1) = +1 \] Solving for \( x \): \ \[ x + 4 = 1 \] \ \[ x = -3 \] Thus, the oxidation state of nitrogen in \( \mathrm{NH}_4^+ \) is \(-3\).
3Step 3: Oxidation State of Nitrogen in \( \mathrm{NO}_3^- \)
In the nitrate ion, \( \mathrm{NO}_3^- \), oxygen typically has an oxidation state of \(-2\). Let \( y \) be the oxidation state of nitrogen in \( \mathrm{NO}_3^- \). The formula for the charge balance in the ion is: \ \[ y + 3(-2) = -1 \] Solving for \( y \): \ \[ y - 6 = -1 \] \ \[ y = +5 \] Thus, the oxidation state of nitrogen in \( \mathrm{NO}_3^- \) is \(+5\).
4Step 4: Conclusion
Based on our calculations, the oxidation states of nitrogen in \( \mathrm{NH}_4 \mathrm{NO}_3 \) are \(-3\) for the ammonium ion and \(+5\) for the nitrate ion. This corresponds to option (c) in the question.
Key Concepts
Ammonium NitrateOxidation State CalculationChemical CompoundsNitrogen in Chemistry
Ammonium Nitrate
Ammonium nitrate, with the chemical formula \( \mathrm{NH}_4\mathrm{NO}_3 \), is a fascinating compound because it incorporates two distinctive types of nitrogen ions. This aspect makes it essential in various applications such as fertilizers and explosives.
- The ammonium ion, represented as \( \mathrm{NH}_4^+ \), consists of nitrogen bonded to four hydrogen atoms.
- The nitrate ion, symbolized by \( \mathrm{NO}_3^- \), features nitrogen bonded to three oxygen atoms.
Oxidation State Calculation
Calculating oxidation states is about understanding the charge each atom would have if all bonds were 100% ionic. This principle allows scientists to determine electron distributions in compounds. Here's a simple guide on how to compute these states:
- Assign oxidation states based on common charge conventions: for instance, hydrogen is generally \(+1\) and oxygen \(-2\).
- Formulate an equation based on these assignments to balance the compound or ion charge.
- Solve the equation to find the unknown oxidation state of the atom in question.
Chemical Compounds
Chemical compounds are substances formed by the joining of two or more different elements in fixed proportions. These compounds have unique properties, distinct from their individual constituent elements.
- Compounds are held together by chemical bonds. These could be ionic, covalent, or metallic bonds, depending on the involved elements.
- The ratios between elements in a compound are always fixed. Hence, every molecule of a compound like water \(H_2O\) always contains two hydrogen atoms for each oxygen atom.
Nitrogen in Chemistry
Nitrogen is a versatile element essential to life and biochemical processes. Its place in the periodic table allows it to form various stable bonds, making it integral in both organic and inorganic chemistry.
- Nitrogen typically forms three bonds, but it can work in diverse coordination environments, appearing in forms like \( \mathrm{N}_2 \) and multiple solid-state structures.
- In compounds, nitrogen's oxidation state can range from \(-3\) to \(+5\), giving it extensive functionality in chemical reactions.
- Its presence is crucial in amino acids, nucleic acids, and other biological molecules.
Other exercises in this chapter
Problem 16
On the basis of structure, the oxidation of two \(\mathrm{Cl}\) atoms in \(\mathrm{CaOCl}_{2}\) respectively are (a) \(-1\) and \(+1\) (b) \(+2,-2\) (c) \(-2,+2
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Which of the following cannot act as a buffer mixture? (a) \(\mathrm{Na}_{2} \mathrm{CO}_{3}+\mathrm{H}_{2} \mathrm{CO}_{3}\) (b) \(\mathrm{HCN}+\mathrm{NaOH}\)
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The decreasing order of strength of the following bases is: (a) \(\mathrm{Cl}, \mathrm{CH}_{3} \mathrm{COO}^{-}, \mathrm{NH}_{3}\) (b) \(\mathrm{CH}_{3} \mathrm
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A sample of \(2.5\) mol of hydrazine \(\left(\mathrm{N}_{2} \mathrm{H}_{4}\right)\) loses 25 mol of electrons on being converted to a new compound \(X\). Assumi
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