Problem 17
Question
Multiply. (Assume all denominators are nonzero.) $$ 9+x 3 x+1 \cdot 3 x+9 $$
Step-by-Step Solution
Verified Answer
The product is \(3x^2 + 28x + 9\).
1Step 1: Expand the expression
Write the expression to be multiplied: \[(9 + x)(3x + 1) \]We want to multiply each term in the first expression by every term in the second expression.
2Step 2: Distribute each term
Apply the distributive property:\[(9 + x)(3x + 1) = 9(3x) + 9(1) + x(3x) + x(1)\]This gives us the terms: \(27x\), \(9\), \(3x^2\), and \(x\).
3Step 3: Combine like terms
Add together like terms from the expression:\[27x + 9 + 3x^2 + x\]Combine \(27x\) and \(x\) together to get \(28x\).
4Step 4: Write the final expression
The fully simplified expression is:\[3x^2 + 28x + 9\]
Key Concepts
Distributive PropertyCombining Like TermsSimplifying Expressions
Distributive Property
The distributive property is a fundamental tool in algebra. It allows you to multiply a single term by two or more terms inside a parenthesis. When using this property, you effectively "distribute" the multiplication across each term within the parenthesis.
Consider the expression \(a(b + c)\). The distributive property allows us to expand this expression to \((ab + ac)\). In the original exercise, we have two binomials, \(9+x\) and \(3x+1\). By applying the distributive property, we multiply each term in the first binomial by each term in the second binomial.
Consider the expression \(a(b + c)\). The distributive property allows us to expand this expression to \((ab + ac)\). In the original exercise, we have two binomials, \(9+x\) and \(3x+1\). By applying the distributive property, we multiply each term in the first binomial by each term in the second binomial.
- Multiply \(9\) by \(3x\), yielding \(27x\).
- Multiply \(9\) by \(1\), yielding \(9\).
- Multiply \(x\) by \(3x\), yielding \(3x^2\).
- Multiply \(x\) by \(1\), yielding \(x\).
Combining Like Terms
After expanding our polynomial through the distributive property, the next crucial step is combining like terms. This process simplifies expressions by grouping and adding together the terms that have the same variables raised to the same power.
In the expanded expression, \[27x + 9 + 3x^2 + x\] observe that the terms \(27x\) and \(x\) are like terms. They both contain the variable \(x\) raised to the first power.
In the expanded expression, \[27x + 9 + 3x^2 + x\] observe that the terms \(27x\) and \(x\) are like terms. They both contain the variable \(x\) raised to the first power.
- Add \(27x\) and \(x\) together to get \(28x\).
Simplifying Expressions
Simplifying expressions is the final step that brings everything together. This process concludes the task of turning a more complicated polynomial into a cleaner, more understandable form.
In our current polynomial \[3x^2 + 28x + 9\] all terms are combined and simplified. Simplifying generally involves performing any necessary arithmetic and combining like terms, which we have already done in prior steps.
The expression \[3x^2 + 28x + 9\] is written in standard polynomial form, starting with the highest degree term, \(3x^2\).
Simplifying expressions not only helps in solving equations easily but also prepares the polynomial for further operations, like factoring or finding roots, if needed. This systematic approach ensures that expressions are orderly and as concise as possible, which is essential in algebraic problem solving.
In our current polynomial \[3x^2 + 28x + 9\] all terms are combined and simplified. Simplifying generally involves performing any necessary arithmetic and combining like terms, which we have already done in prior steps.
The expression \[3x^2 + 28x + 9\] is written in standard polynomial form, starting with the highest degree term, \(3x^2\).
Simplifying expressions not only helps in solving equations easily but also prepares the polynomial for further operations, like factoring or finding roots, if needed. This systematic approach ensures that expressions are orderly and as concise as possible, which is essential in algebraic problem solving.
Other exercises in this chapter
Problem 17
Construct a mathematical model given the following. \(y\) varies inversely as \(x\), and \(y=5\) when \(x=7\).
View solution Problem 17
If each share of a company stock is priced at \(\$ 22.40,\) then calculate the \(P /\) E ratio given the following values for the earnings per share. \(\$ 1.40\
View solution Problem 18
Harry traveled 15 miles on the bus and then another 72 miles on a train. If the train was 18 miles per hour faster than the bus and the total trip took 2 hours,
View solution Problem 18
Simplify. (Assume all denominators are nonzero.) $$ 5 y-1210-y y 2 $$
View solution