Problem 17
Question
Meso tartaric acid and \(d\)-tartaric acid are: (a) position isomers (b) racemic mixture (c) enantiomers (d) diastereomers
Step-by-Step Solution
Verified Answer
The compounds are diastereomers (d).
1Step 1: Understanding the Compounds
Meso tartaric acid and d-tartaric acid are stereoisomers of tartaric acid. Meso tartaric acid is optically inactive because it has an internal plane of symmetry, while d-tartaric acid is optically active, rotating plane-polarized light in one direction.
2Step 2: Identifying the Relationship
To determine the relationship between meso tartaric acid and d-tartaric acid, observe their optical activity and symmetry. Enantiomers are non-superimposable mirror images that differ in optical activity, whereas diastereomers are stereoisomers that are not mirror images of each other.
3Step 3: Using Optical Activity
Meso tartaric acid does not exhibit optical activity due to its symmetry; it is achiral. In contrast, d-tartaric acid is chiral and optically active. Therefore, they cannot be enantiomers as they do not exhibit opposite optical activity.
4Step 4: Understanding Diastereomers
Diastereomers include pairs of stereoisomers that are not mirror images of each other. Meso tartaric acid and d-tartaric acid are diastereomers because they have the same molecular formula but differ in spatial arrangement and optical activity.
Key Concepts
Optical ActivityDiastereomersChirality
Optical Activity
Optical activity is a fascinating property in chemistry that describes how a compound interacts with plane-polarized light. When a light beam passes through a chiral substance, it can be rotated to the right (dextrorotatory) or to the left (levorotatory). This rotating effect is optical activity.
Understanding optical activity can help us differentiate compounds, especially in stereochemistry, where examining the interaction with light helps in determining whether a compound is chiral or achiral.
- Chiral compounds: These are the ones that show optical activity. They don't have an internal plane of symmetry.
- Achiral compounds: These don't show optical activity because of their symmetrical structure, like meso compounds.
Understanding optical activity can help us differentiate compounds, especially in stereochemistry, where examining the interaction with light helps in determining whether a compound is chiral or achiral.
Diastereomers
Diastereomers are categories of stereoisomers that are not mirror images. Unlike enantiomers that are non-superimposable mirror images, diastereomers have different configurations at one or more (but not all) stereocenters.
- They can have different chemical and physical properties, like boiling points, melting points, and solubilities.
- They are identified when compounds have more than one chiral center but differ only partially in their configuration.
Chirality
Chirality is an essential concept in stereochemistry, describing the property of a molecule that makes it non-superimposable on its mirror image. It often comes into play with carbon atoms bonded to four different groups, creating a chiral center.
- A chiral molecule: Cannot be superimposed on its mirror image.
- An achiral molecule: Can be superimposed on its mirror image, often due to possessing a plane of symmetry.
Other exercises in this chapter
Problem 15
The \(\mathrm{CH}_{3}\) group in propene exerts (a) \(-\underline{I}\) effect (b) \(+\mathrm{I}\) effect (c) hyperconjugation effect (d) both \(+1\) and hyperco
View solution Problem 16
The conversion of enantiomer into racemic mixture is known as: (a) Resolution (b) Racemisation (c) Revolution (d) Inversion
View solution Problem 18
The two compounds \(\mathrm{CH}_{3} \mathrm{CH}_{2} \mathrm{CH}_{2} \mathrm{OCH}_{3}\) and \(\mathrm{CH}_{3} \mathrm{CH}_{2} \mathrm{OCH}_{2} \mathrm{CH}_{3}\)
View solution Problem 19
The number of sigma bonds in \(p\)-cresol is (a) 14 (b) 16 (c) 18 (d) 12
View solution