Problem 17
Question
\(\mathrm{U} \operatorname{sing} \cos ^{2} \theta=\frac{1}{2}(\cos 2 \theta+1)\) we have $$\begin{aligned} P_{2}(\cos \theta) &=\frac{1}{2}\left(3 \cos ^{2} \theta-1\right)=\frac{3}{2} \cos ^{2} \theta-\frac{1}{2} \\ &=\frac{3}{4}(\cos 2 \theta+1)-\frac{1}{2}=\frac{3}{4} \cos 2 \theta+\frac{1}{4}=\frac{1}{4}(3 \cos 2 \theta+1), \end{aligned}$$
Step-by-Step Solution
Verified Answer
We simplify \(P_2(\cos \theta)\) to \(\frac{1}{4}(3\cos 2\theta + 1)\).
1Step 1: Understanding the Problem
We are given an expression for \(\cos^2 \theta\) and a polynomial \(P_2(\cos \theta)\). The task is to verify the transformation of \(P_2(\cos \theta)\) using the expression of \(\cos^2 \theta\).
2Step 2: Expand \(P_2(\cos \theta)\) using \(\cos^2 \theta\)
Start by replacing \(\cos^2 \theta\) with \(\frac{1}{2}(\cos 2 \theta + 1)\) in the expression for \(P_2(\cos \theta)\): \[P_2(\cos \theta) = \frac{3}{2}\left(\frac{1}{2}(\cos 2 \theta + 1)\right) - \frac{1}{2}\]
3Step 3: Simplify the Expression
Simplify the expression obtained in Step 2:\[P_2(\cos \theta) = \frac{3}{4}(\cos 2 \theta + 1) - \frac{1}{2}\]This becomes:\[P_2(\cos \theta) = \frac{3}{4}\cos 2 \theta + \frac{3}{4} - \frac{2}{4}\]
4Step 4: Final Simplification
Continue simplifying the expression:\[P_2(\cos \theta) = \frac{3}{4}\cos 2 \theta + \frac{1}{4}\]And thus,\[P_2(\cos \theta) = \frac{1}{4}(3\cos 2 \theta + 1)\]
5Step 5: Verification
The transformation and simplification lead to the desired expression:\(P_2(\cos \theta) = \frac{1}{4}(3 \cos 2 \theta + 1)\), verifying the initial condition given in the problem.
Key Concepts
Trigonometric IdentitiesPolynomial TransformationMathematical Verification
Trigonometric Identities
Trigonometric identities are essential tools in mathematics. They allow us to transform and simplify expressions involving trigonometric functions. In this exercise, we're particularly interested in the identity for \(\cos^2 \theta\). The identity \(\cos^2 \theta = \frac{1}{2} ( \cos 2\theta + 1)\) is one of the double-angle identities.
These identities are valuable because they express trig functions in terms of angles twice as large or in forms that make calculations easier. Knowing these identities helps when working with polynomials involving trigonometric functions, allowing transformations and simplifications that reveal more details or make functions easier to integrate or differentiate.
These identities are valuable because they express trig functions in terms of angles twice as large or in forms that make calculations easier. Knowing these identities helps when working with polynomials involving trigonometric functions, allowing transformations and simplifications that reveal more details or make functions easier to integrate or differentiate.
- Example: \(\cos^2 \theta\) can be written as \(\frac{1}{2}(\cos 2\theta + 1)\).
- Purpose: Simplifies expressions to make further calculations manageable.
Polynomial Transformation
Polynomial transformation refers to altering a polynomial expression's form while retaining its core properties. This concept is evident in the task involving the Legendre polynomial \(P_2(x)\). Given as \(\frac{1}{2}(3x^2 - 1)\), this polynomial is transformed using a trigonometric identity.
Here, the identity \(\cos^2 \theta = \frac{1}{2}(\cos 2\theta + 1)\) allows us to express \(x\) in terms of \(\cos 2\theta\), effectively transforming the polynomial into an expression that's easier to work with.
Here, the identity \(\cos^2 \theta = \frac{1}{2}(\cos 2\theta + 1)\) allows us to express \(x\) in terms of \(\cos 2\theta\), effectively transforming the polynomial into an expression that's easier to work with.
- Initial Form: \(P_2(\cos \theta) = \frac{1}{2}(3\cos^2 \theta - 1)\)
- Transformed Form: Uses the identity to become \(\frac{1}{4}(3\cos 2\theta + 1)\).
Mathematical Verification
Mathematical verification ensures that our transformations and calculations result in correct outcomes. In trigonometric and polynomial exercises, verifying each step is crucial to confirm our results are accurate and consistent with known identities and formulas.
To verify the transformation in this exercise, we start by substituting the trigonometric identity into the polynomial and simplifying along each step. By doing so, we ensure that any errors can be traced and corrected efficiently.
To verify the transformation in this exercise, we start by substituting the trigonometric identity into the polynomial and simplifying along each step. By doing so, we ensure that any errors can be traced and corrected efficiently.
- Initial Verification: Replace \(\cos^2 \theta\) with its identity form.
- Simplification: Rework the expression to show that it matches the given form.
- Final Check: Confirm that the achieved expression \(\frac{1}{4}(3\cos 2\theta + 1)\) aligns with the expected result.
Other exercises in this chapter
Problem 16
$$\begin{array}{l} a_{0}=\frac{1}{\pi} \int_{-\pi}^{\pi} f(x) d x=\frac{1}{\pi} \int_{0}^{\pi}\left(e^{x}-1\right) d x=\frac{1}{\pi}\left(e^{\pi}-\pi-1\right) \
View solution Problem 16
Using the facts that \(\phi_{0}\) and \(\phi_{1}\) are orthogonal to \(\phi_{n}\) for \(n>1\), we have $$\begin{aligned} \int_{a}^{b}(\alpha x+\beta) \phi_{n}(x
View solution Problem 17
Using the fact that \(\phi_{n}\) and \(\phi_{m}\) are orthogonal for \(n \neq m\) we have $$\begin{aligned} \left\|\phi_{m}(x)+\phi_{n}(x)\right\|^{2} &=\int_{a
View solution Problem 18
Since \(f(x)\) is an odd function, we expand in a sine series: $$b_{n}=\frac{2}{\pi} \int_{0}^{\pi} x^{3} \sin n x d x=\frac{2}{\pi}\left(-\left.\frac{x^{3}}{n}
View solution