Problem 17
Question
Let \(g(t)\) give the market value (in \(\$ 1000\) s) of a house in year \(t\). Say what the following statements tell you about the house. \(g(5)-g(0)=30\)
Step-by-Step Solution
Verified Answer
Answer: The statement represents that the market value of the house increased by \(\$30,000\) between the years \(0\) and \(5\).
1Step 1: Interpret the Function
The function \(g(t)\) represents the market value of a house in year \(t\). This means that \(g(t)\) gives the market value (in \(\$ 1000\) s) of a house in a given year.
2Step 2: Identify the Years
In the given statement, we have \(g(5) - g(0) = 30\). Here, \(g(5)\) represents the market value of the house in year \(5\), and \(g(0)\) represents the market value of the house in year \(0\) (initial value).
3Step 3: Interpret the Difference
The statement \(g(5) - g(0) = 30\) tells us the difference in market value of the house between year \(5\) and the initial year, year \(0\). This difference is equal to \(30\), which means that the market value has increased by \(30 \times \$1000 = \$30,000\) over these years.
4Step 4: Summarize the Interpretation
The given statement \(g(5) - g(0) = 30\) tells us that the market value of the house increased by \(\$30{,}000\) between the years \(0\) and \(5\).
Key Concepts
Market ValueDifference InterpretationYearly Change
Market Value
The market value is essentially the current worth of a property, such as a house, in a given market. In our function \(g(t)\), the market value is quantified in thousands of dollars and represented for different years by varying the variable \(t\). The function \(g(t)\) indicates the financial value of the house at specific times, helping us understand how the property's worth changes over time. Understanding market value can help potential buyers or sellers make informed decisions. For instance, if the market value increases, it might be a good time for a homeowner to sell the property for a profit. Conversely, a decrease might suggest waiting for better market conditions or improvements to increase the house's worth. In this context, when we discuss market value, we're examining how much someone would realistically pay for the house in a specified year, based on the function \(g(t)\).
Difference Interpretation
The concept of difference interpretation is crucial in analyzing how values change over a time period. In the function \(g(t)\), when we speak of \(g(5) - g(0) = 30\), we are looking at how much the value of the house has changed from the initial year (year 0) to year 5. Looking at this calculation more closely:
- \(g(5)\) is the house's market value at year 5.
- \(g(0)\) is the initial market value at year 0.
- The difference, or \(g(5) - g(0)\), tells us how much the value has increased or decreased over this time frame.
Yearly Change
Yearly change provides insights into how consistently, and at what rate, a property's market value is evolving each year. Interpreting yearly change in the context of \(g(t)\), where \(g(5) - g(0) = 30\), can be extremely valuable for forecasting future trends or making investment decisions.To understand the yearly change, we break down the total change over the given period:
- The total increase over 5 years is \(\\(30,000\).
- Dividing this increase by the number of years (5), we find the average yearly increase.
- This calculation: \(\frac{30,000}{5} = \\)6,000\) per year.
Other exercises in this chapter
Problem 16
Are the two functions the same function? $$ B(v)=30-\frac{480}{v} \text { and } C(v)=30\left(\frac{v-16}{v}\right) $$
View solution Problem 17
In Exercises 14-17, assume the two quantities are directly proportional to each other. If \(s=35\) when \(t=25,\) find \(t\) when \(s\) is 14 .
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Chicago's average monthly rainfall, \(R=f(t)\) inches, is given as a function of month, \(t,\) in Table 4.7 . (January is \(t=1 .\) ) Solve and interpret: (a) \
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In Exercises \(17-20,\) which letters stand for variables and which for constants? $$ V(r)=(4 / 3) \pi r^{2} $$
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