Problem 17
Question
In Problems 17-24, find the nth term of the arithmetic sequence \(\left\\{a_{n}\right\\}\) whose first term \(a_{1}\) and common difference d are given. What is the 51st term? $$ a_{1}=2 ; \quad d=3 $$
Step-by-Step Solution
Verified Answer
The 51st term is 152.
1Step 1: Identify the formula for the nth term
The nth term of an arithmetic sequence can be found using the formula: \[a_{n} = a_{1} + (n - 1) \times d\] where \(a_{1}\) is the first term and \(d\) is the common difference.
2Step 2: Substitute the given values into the formula
Given, \(a_{1} = 2\) and \(d = 3\). To find the 51st term, substitute the values into the formula: \[a_{n} = 2 + (51 - 1) \times 3\]
3Step 3: Simplify the expression
Calculate the expression inside the parenthesis first: \[a_{n} = 2 + 50 \times 3\]
4Step 4: Multiply and add to find the 51st term
Multiply 50 by 3 and add it to 2: \[a_{n} = 2 + 150 = 152\]
Key Concepts
nth term formulacommon differencesequence calculationsimplifying expressions
nth term formula
The nth term formula is key to unraveling arithmetic sequences. In any arithmetic sequence, each term increases by a consistent amount known as the common difference. The general formula to find the nth term in such a sequence is: \(a_{n} = a_{1} + (n - 1) \times d\) Here, \(a_{n}\) represents the nth term, \(a_{1}\) is the first term, and \(d\) is the common difference. This formula helps in determining any term in the sequence without listing all terms before it. For example, in our exercise, with \(a_{1} = 2\) and \(d = 3\), substituting these values directly into the formula gives the desired nth term.
common difference
The common difference is a critical parameter in an arithmetic sequence. It tells you how much the sequence increases or decreases with each term. The common difference is denoted by \(d\). In our given problem, the common difference is 3, meaning that each term in the sequence is 3 more than the preceding one. This constant change gives arithmetic sequences their unique structure. Let's consider quick examples:
- If the first term is 2 and the common difference is 5, the sequence will be: 2, 7, 12, 17, ...
- If the first term is 10 and the common difference is -3, the sequence will be: 10, 7, 4, 1, ...
sequence calculation
Sequence calculation involves applying the nth term formula to obtain specific terms in the sequence. For our exercise, we needed the 51st term with \(a_{1} = 2\) and \(d = 3\). Substituting these values into the nth term formula, we get: \[a_{51} = 2 + (51 - 1) \times 3\] The idea is to calculate step-by-step:
- First, simplify the term inside the parentheses: \(51 - 1 = 50\).
- Then, multiply the result by the common difference: \(50 \times 3 = 150\).
- Finally, add this product to the first term: \(2 + 150 = 152\)
simplifying expressions
A significant aspect when working with arithmetic sequences is simplifying expressions. This skill ensures efficiency and precision in finding terms within the sequence. To simplify correctly, follow a methodical approach:
- Identify and isolate the parts of the formula that require computation.
- Perform operations within parentheses first.
- Follow the order of operations, multiplying before adding or subtracting.
Other exercises in this chapter
Problem 17
Show that each sequence is geometric. Then find the common ratio and list the first four terms. $$ \left\\{t_{n}\right\\}=\left\\{\frac{3^{n-1}}{2^{n}}\right\\}
View solution Problem 17
List the first five terms of each sequence. \(\left\\{a_{n}\right\\}=\left\\{\frac{n}{n+2}\right\\}\)
View solution Problem 18
Use the Principle of Mathematical Induction to show that the given statement is true for all natural numbers \(n\). $$ 1 \cdot 2+3 \cdot 4+5 \cdot 6+\cdots+(2 n
View solution Problem 18
Expand each expression using the Binomial Theorem. $$ (x-1)^{5} $$
View solution