Problem 17
Question
In Exercises \(9-20,\) find each product and write the result in standard form. $$(-5+i)(-5-i)$$
Step-by-Step Solution
Verified Answer
The product of the two complex numbers \((-5+i)\) and \((-5-i)\) in standard form is 24.
1Step 1: Apply distributive property
Use the distributive property (also known as the FOIL method, which stands for 'First, Outer, Inner, Last') to multiply the two complex numbers together. This results in: \[(-5+i)(-5-i)=(-5*-5)+(-5*-i)+(i*-5)+(i*-i)\]
2Step 2: Simplify the result
Next, simplify the result. Remember, \(i^2\) equals -1. So this leads to:\[((-5*-5)+(-5*-i)+(i*-5)+(i*-i))=(25+5i-5i-1)=24\]
3Step 3: Write in standard form
Lastly, the resultant number is a real number, so it's standard form is the number itself, which is 24.
Key Concepts
Distributive PropertyFOIL MethodImaginary Unit
Distributive Property
The distributive property is a fundamental principle used in multiplication. It's like a mathematical way to handle multiplying a number by a group of numbers added together. Think of it like distributing a set of tasks among a team. When it comes to complex numbers, you can apply the distributive property to multiply the parts separately and then add them together.
For example, when given
For example, when given
- The expression \((-5+i)(-5-i)\), you treat it like \((a+b)(c+d)\),
- where you distribute each term in the first parenthesis to each term in the second parenthesis,
- this results in multiplying 'First', 'Outer', 'Inner', and 'Last' terms separately.
FOIL Method
The FOIL method is a specific application of the distributive property for multiplying two binomials. "FOIL" stands for:
Notice how the imaginary parts \(5i\) and \(-5i\) cancel each other out, simplifying to \(25 - 1 = 24\). This showcases the effectiveness of the FOIL method in handling multiplication of binomials.
- First: Multiply the first terms in each binomial together.
- Outer: Multiply the outer terms in the product.
- Inner: Multiply the inner terms.
- Last: Multiply the last terms.
- First: \(-5 \times -5 = 25\)
- Outer: \(-5 \times -i = 5i\)
- Inner: \(i \times -5 = -5i\)
- Last: \(i \times -i = -1\)
Notice how the imaginary parts \(5i\) and \(-5i\) cancel each other out, simplifying to \(25 - 1 = 24\). This showcases the effectiveness of the FOIL method in handling multiplication of binomials.
Imaginary Unit
The imaginary unit is a key component in the realm of complex numbers. Represented by the symbol \(i\), it has a unique property: \(i^2 = -1\). This concept allows us to extend the real number system.
In calculations, the imaginary unit helps resolve expressions that involve square roots of negative numbers. For instance, in the product \(i \times -i\), the use of \(i^2 = -1\) is crucial. It simplifies the expression \(i \times -i\) to \(-1\).
Understanding the imaginary unit helps in mastering operations with complex numbers. It acts as a building block for forming complex solutions, easing the process of solving equations that don't resolve neatly in the real number world.
In calculations, the imaginary unit helps resolve expressions that involve square roots of negative numbers. For instance, in the product \(i \times -i\), the use of \(i^2 = -1\) is crucial. It simplifies the expression \(i \times -i\) to \(-1\).
Understanding the imaginary unit helps in mastering operations with complex numbers. It acts as a building block for forming complex solutions, easing the process of solving equations that don't resolve neatly in the real number world.
Other exercises in this chapter
Problem 16
Solve and check linear equation. \(45-[4-2 y-4(y+7)]=\) \(-4(1+3 y)-[4-3(y+2)-2(2 y-5)]\)
View solution Problem 16
Graph each equation in Exercises \(13-28\). Let \(x=-3,-2,-1,0\) \(1,2,\) and 3 $$ y=x+2 $$
View solution Problem 17
Find all values of \(x\) satisfying the given conditions. \(y_{1}=\frac{1}{x}, y_{2}=\frac{1}{2 x}, y_{3}=\frac{1}{x-1},\) and the sum of 3 times \(y_{1}\) and
View solution Problem 17
Solve each equation in Exercises \(15-34\) by the square root property. $$ 5 x^{2}+1=51 $$
View solution