Problem 17
Question
In Exercises 17 and \(18,\) use the summation capabilities of a graphing utility to evaluate the sum. Then use the properties of summation and Theorem 4.2 to verify the sum. $$ \sum_{i=1}^{20}\left(i^{2}+3\right) $$
Step-by-Step Solution
Verified Answer
The sum of the series \( \sum_{i=1}^{20}(i^{2}+3) \) is 2930.
1Step 1: Breaking the Summation
Break down the summation into two separate sums: \[ \sum_{i=1}^{20}(i^{2}+3) = \sum_{i=1}^{20}i^{2} + \sum_{i=1}^{20}3 \]. Here, we used the property of summation that allows us to distribute the sum over addition.
2Step 2: Evaluate the First Summation
Evaluate the sum of squares using the formula for the sum of squares of first n natural numbers, which is \[\frac{n(n+1)(2n+1)}{6}\], where n = 20 in this case. So the sum becomes \[ \sum_{i=1}^{20}i^{2} = \frac{20(20+1)(2*20+1)}{6} = 2870 \].
3Step 3: Evaluate the Second Summation
Evaluate the second summation. Here, we have 20 terms, each of which is 3, so \[ \sum_{i=1}^{20}3 = 20 * 3 = 60 \].
4Step 4: Combine the Results
Combine the results obtained in Step 2 and Step 3 to get the final sum. So, the result is \[ \sum_{i=1}^{20}(i^{2}+3) = 2870 + 60 = 2930 \].
Key Concepts
Sum of SquaresSummation PropertiesGraphing UtilityTheorem 4.2
Sum of Squares
The sum of squares is a concept you'll often encounter in mathematics, particularly in algebra and calculus. The sum of squares of the first \(n\) natural numbers can be calculated using a specific formula: \[\sum_{i=1}^{n} i^{2} = \frac{n(n+1)(2n+1)}{6}\]. This formula is a quick and efficient way to find the sum of squares without having to add each square individually.
For example, if you want the sum of squares for the numbers from 1 to 20, simply substitute \(n = 20\) into the formula:
For example, if you want the sum of squares for the numbers from 1 to 20, simply substitute \(n = 20\) into the formula:
- Calculate \(20 \times 21 = 420\)
- Calculate \(2 \times 20 + 1 = 41\)
- Multiply these values: \(420 \times 41 = 17220\)
- Finally, divide by 6: \(\frac{17220}{6} = 2870\)
Summation Properties
Summation is a mathematical notation used to denote the sum of a sequence of terms. It's compact and efficient. Summation has several key properties that make calculations easier:
- Linearity: The sum can be distributed over addition, meaning \(\sum(a_i + b_i) = \sum a_i + \sum b_i\).
- Constant Multiplication: A constant can be factored out of a summation, such as \(\sum(c \times a_i) = c \times \sum a_i\).
- Summation of Constants: The sum of a constant repeated \(n\) times is \(n \times c\).
Graphing Utility
Graphing utilities are powerful tools that help visualize mathematical data and perform complex calculations like summation. These can be found in standalone graphing calculators or software like GeoGebra and Desmos.
Using a graphing utility, you can:
Using a graphing utility, you can:
- Quickly calculate sums and visualize their graphs.
- Verify manual calculations, like the sum of squares.
- Explore mathematical patterns and properties graphically.
Theorem 4.2
Theorem 4.2 is an essential concept in understanding summation and its properties. Although this particular theorem might differ slightly depending on context, it generally involves standardizing complex calculations. The theorem often provides:
- Formulas or methods to simplify computations.
- Rules on how specific functions behave under summation.
- Techniques to verify or prove results.
Other exercises in this chapter
Problem 17
Find the indefinite integral by \(u\) -substitution. (Hint: Let \(u\) be the denominator of the integrand.) $$ \int \frac{\sqrt{x}}{\sqrt{x}-3} d x $$
View solution Problem 17
In Exercises \(17-20,\) use the error formulas in Theorem 4.19 to estimate the error in approximating the integral, with \(n=4\), using (a) the Trapezoidal Rule
View solution Problem 18
Find the derivative of the function. \(g(x)=\ln (\cosh x)\)
View solution Problem 18
Evaluate the integral. $$ \int_{\sqrt{3}}^{3} \frac{1}{9+x^{2}} d x $$
View solution