Problem 17
Question
In Exercises 17-34, solve the equation. \(6.24 x-5.2=5.2 x\)
Step-by-Step Solution
Verified Answer
The solution is \(x = 5\).
1Step 1: Move Variable Terms to One Side
First, we need to get all the terms with the variable \(x\) on one side of the equation. To do this, subtract \(5.2x\) from both sides of the equation. This will help isolate the variable. The equation will become:\[6.24x - 5.2x - 5.2 = 0\].
2Step 2: Simplify the Equation
Now, let’s simplify the expression by combining like terms. Subtract \(5.2x\) from \(6.24x\) to simplify the left side:\[(6.24 - 5.2)x - 5.2 = 0\].Calculate the subtraction: \[1.04x - 5.2 = 0\].
3Step 3: Isolate the Variable
Next, we want to get the \(x\) term by itself. Add \(5.2\) to both sides of the equation to get rid of the constant term on the left:\[1.04x = 5.2\].
4Step 4: Solve for the Variable
Finally, divide both sides by \(1.04\) to solve for \(x\):\[x = \frac{5.2}{1.04}\].Upon division, the result is:\[x = 5\].
Key Concepts
Solving EquationsVariable IsolationCombining Like TermsEquation Simplification
Solving Equations
The process of solving equations is all about finding the value of the unknown variable that makes the equation true. Usually, this involves several steps to simplify the equation by using arithmetic operations—addition, subtraction, multiplication, and division.
The aim is to rearrange the equation gradually until you isolate the variable and solve for its value.
The aim is to rearrange the equation gradually until you isolate the variable and solve for its value.
- First, identify the terms in the equation. For example, in our exercise, we have terms involving variable has coefficient as well as constant terms.
- Understand the operations involved: look out for signs and group similar operations together.
- Use inverse operations strategically to slowly unwind the equation, which will give you a clearer path toward the solution.
Variable Isolation
Variable isolation is all about getting the variable you’re solving for alone on one side of the equation. This often involves moving other terms to the opposite side.
In our example, we started by subtracting the term containing the same variable on the opposite side:
In our example, we started by subtracting the term containing the same variable on the opposite side:
- Note that each operation must be performed on both sides of the equation to keep it balanced.
- For example, subtracting the variable term like \(5.2x\) from both sides helps move all variable terms together on one side.
- Use arithmetic operations to isolate the variable.
Combining Like Terms
Combining like terms is a crucial step in simplifying equations and making them easier to solve. Like terms are terms that have exactly the same variable parts and can be combined by adding or subtracting the coefficients.
- Look for terms with the same variable. In our given equation, these were the terms \(6.24x\) and \(5.2x\).
- Simply add or subtract the coefficients. Here, we subtracted \(5.2\) from \(6.24\) to get \(1.04x\).
- This creates a simpler expression that’s easier to work with.
Equation Simplification
Equation simplification is the process of making an equation easier to work with. After combining like terms, you often need to simplify further to isolate the variable.
This involves removing constants and performing arithmetic operations until you get the simplest form of the equation.
This involves removing constants and performing arithmetic operations until you get the simplest form of the equation.
- Start by removing constant terms on the same side as the variable by using addition or subtraction.
- In our example, we add \(5.2\) to both sides to remove the constant term next to \(x\).
- Finally, solve the equation by performing division or multiplication if needed to completely isolate the variable.
Other exercises in this chapter
Problem 17
In Exercises 17-24, your solutions should include a well-labeled sketch. The lengths of two legs of a right triangle are 3 meters and 18 meters. Find the length
View solution Problem 17
In Exercises 17-32, compute the exact square root. If the square root is undefined, write "undefined". \(\sqrt{-9}\)
View solution Problem 17
Convert the given fraction to a terminating decimal. \(\frac{25}{10}\)
View solution Problem 17
In Exercises 17-40, divide the decimals. \(\frac{0.3478}{0.47}\)
View solution