Problem 17
Question
In Exercises \(17-26,\) let $$A=\left[\begin{array}{rr}-3 & -7 \\\2 & -9 \\\5 & 0\end{array}\right] \text { and } B=\left[\begin{array}{rr}-5 & -1 \\\0 & 0 \\\3 & -4\end{array}\right]$$ Solve each matrix equation for \(X\). $$X-A=B$$
Step-by-Step Solution
Verified Answer
The solution of the matrix equation is the matrix \(X = \begin{bmatrix} -8 & -8 \ 2 & -9 \ 8 & -4 \end{bmatrix}\)
1Step 1: Understand the problem
We have a matrix equation \(X - A = B\), two given matrices \(A\) & \(B\) of the same order and the task is to solve for matrix \(X\).
2Step 2: Matrix Subtraction
In the case of matrix subtraction \(X - A = B\), solving for \(X\) basically entails isolating \(X\) on one side of the equation. This can be done by adding \(A\) to both sides of the equation to cancel out \(-A\) on the left side.
3Step 3: Solve for X
After adding matrix \(A\) to both sides of the equation, we get \(X = A + B\). So, to find \(X\), sum matrices \(A\) and \(B\) element-wise. You simply add each element in \(A\) with the corresponding element in \(B\). The resulting matrix will be our solution matrix \(X\).
4Step 4: Compute the Result
Matrix \(A = \begin{bmatrix} -3 & -7 \ 2 & -9 \ 5 & 0 \end{bmatrix}\) and matrix \(B = \begin{bmatrix} -5 & -1 \ 0 & 0 \ 3 & -4 \end{bmatrix}\). Adding them gives, \(X = A + B = \begin{bmatrix} -8 & -8 \ 2 & -9 \ 8 & -4 \end{bmatrix}\)
Key Concepts
Matrix SubtractionMatrix AdditionSolving for XElement-wise Addition
Matrix Subtraction
Matrix subtraction is a fundamental concept in linear algebra. It is similar to the way we subtract numbers, but applied to matrices, which are arrays of numbers.
The order of the matrices must be the same to perform matrix subtraction, meaning they both need to have the same number of rows and columns. To subtract one matrix from another, such as in the equation \( X - A = B \), you simply subtract each corresponding element in matrix \( A \) from matrix \( X \).
Each element in matrix \( A \) must align exactly with an element in matrix \( X \) for the subtraction to be valid. Remember, subtraction is just the opposite of addition. When solving \( X - A = B \), it is often useful to add \( A \) to both sides to isolate \( X \).
The order of the matrices must be the same to perform matrix subtraction, meaning they both need to have the same number of rows and columns. To subtract one matrix from another, such as in the equation \( X - A = B \), you simply subtract each corresponding element in matrix \( A \) from matrix \( X \).
Each element in matrix \( A \) must align exactly with an element in matrix \( X \) for the subtraction to be valid. Remember, subtraction is just the opposite of addition. When solving \( X - A = B \), it is often useful to add \( A \) to both sides to isolate \( X \).
Matrix Addition
Matrix addition is another core concept in the study of matrices. It involves combining two matrices by adding their corresponding elements.
Just like with matrix subtraction, the matrices must be of the same dimension. When solving the equation \( X = A + B \), each element of the resultant matrix \( X \) is:
Just like with matrix subtraction, the matrices must be of the same dimension. When solving the equation \( X = A + B \), each element of the resultant matrix \( X \) is:
- The sum of the corresponding elements from matrix \( A \) and matrix \( B \).
- -3 + (-5) = -8
- -7 + (-1) = -8
Solving for X
In linear algebra, solving for \( X \) in equations involving matrices requires strategic manipulation. Consider the equation \( X - A = B \).
The goal is to have \( X \) by itself on one side of the equation. To achieve this, think of matrix subtraction as you would numerical subtraction. To move \( A \) across the equation, you need to do the inverse operation. This means adding \( A \) to both sides of the equation. The equation then becomes \( X = A + B \). This technique helps in isolating \( X \) and turns the problem into a simple addition problem. Once \( X \) is isolated, it becomes clear how to compute the values in \( X \) by executing matrix addition.
The goal is to have \( X \) by itself on one side of the equation. To achieve this, think of matrix subtraction as you would numerical subtraction. To move \( A \) across the equation, you need to do the inverse operation. This means adding \( A \) to both sides of the equation. The equation then becomes \( X = A + B \). This technique helps in isolating \( X \) and turns the problem into a simple addition problem. Once \( X \) is isolated, it becomes clear how to compute the values in \( X \) by executing matrix addition.
Element-wise Addition
Element-wise addition is a key aspect when working with matrices. Unlike regular addition, where single numbers are combined, matrix addition requires adding each corresponding element in two matrices.
Each entry in the resultant matrix is obtained by summing elements that occupy the same position in their respective matrices. Take matrices \( A \) and \( B \) for instance. If matrix \( A \) has elements arranged like this:
Each entry in the resultant matrix is obtained by summing elements that occupy the same position in their respective matrices. Take matrices \( A \) and \( B \) for instance. If matrix \( A \) has elements arranged like this:
- First row: -3 and -7
- Second row: 2 and -9
- Third row: 5 and 0
- First row: -5 and -1
- Second row: 0 and 0
- Third row: 3 and -4
- For the first row: -3 + (-5) = -8 and -7 + (-1) = -8
- For the second row: 2 + 0 = 2 and -9 + 0 = -9
- For the third row: 5 + 3 = 8 and 0 + (-4) = -4
Other exercises in this chapter
Problem 16
Use Gaussian elimination to find the complete solution to each system of equations, or show that none exists. $$\left\\{\begin{array}{r}3 x+2 y-z=5 \\\x+2 y-z=1
View solution Problem 16
perform each matrix row operation and write the new matrix. $$ \left[\begin{array}{rrr|r} 1 & -1 & 5 & -6 \\ 3 & 3 & -1 & 10 \\ 1 & 3 & 2 & 5 \end{array}\right]
View solution Problem 17
In Exercises \(13-18,\) use the fact that if \(A=\left[\begin{array}{ll}a & b \\\ c & d\end{array}\right]\), then \(A^{-1}=\frac{1}{a d-b c}\left[\begin{array}{
View solution Problem 17
Use Cramer's Rule to solve each system. $$\left\\{\begin{array}{r}x+2 y=3 \\\3 x-4 y=4\end{array}\right.$$
View solution