Problem 17
Question
In Exercises \(17-24,\) write a formula for the general term (the nth term) of each geometric sequence. Then use the formula for \(a_{n}\) to find \(a_{7},\) the seventh term of the sequence. $$ 3,12,48,192, \dots $$
Step-by-Step Solution
Verified Answer
The seventh term of the given geometric sequence is 12288.
1Step 1: Identify the first term and the ratio
The first term \(a_{1}\) of the given sequence is 3. To find the common ratio, divide the second term by the first term, or the third term by the second term and so on. Doing this we find that \(r = 12 / 3 = 4\). So, the first term a_{1} is 3 and the common ratio \(r\) is 4.
2Step 2: Formulate the formula for the nth term of the geometric sequence
The formula for the nth term of a geometric sequence is \(a_{n} = a_{1} * r^{(n-1)}\). Substituting our found values in, we find the formula for the nth term for this sequence is \(a_{n} = 3 * 4^{(n-1)}\).
3Step 3: Use the formula to find the seventh term of the sequence
Now, we can use the derived formula to find the seventh term of the sequence. Substitute \(n=7\) into the formula, we get \(a_{7} = 3 * 4^{(7-1)} = 3 * 4096 = 12288\).
Key Concepts
nth termcommon ratioseventh term calculationgeneral term formula
nth term
In a geometric sequence, the nth term is all about understanding the position and value of a particular element within the sequence. It is important because it helps us predict any term in the sequence without having to list all of them.
The formula for the nth term of a geometric sequence is given by: \( a_{n} = a_{1} \cdot r^{(n-1)} \).
The formula for the nth term of a geometric sequence is given by: \( a_{n} = a_{1} \cdot r^{(n-1)} \).
- \(a_{n}\) represents the nth term of the sequence.
- \(a_{1}\) is the first term of the sequence.
- \(r\) is the common ratio.
- \(n\) is the term number.
common ratio
The common ratio in a geometric sequence is the factor by which we multiply each term to get the next term. It's crucial to identifying the pattern of the sequence.
To find the common ratio \(r\), you divide any term in the sequence by the previous term. For instance, using the sequence provided:
To find the common ratio \(r\), you divide any term in the sequence by the previous term. For instance, using the sequence provided:
- Divide the second term by the first term, \(\frac{12}{3} = 4\).
- You can also divide the third term by the second term, \(\frac{48}{12} = 4\).
seventh term calculation
Calculating the seventh term effectively involves plugging into the nth term formula. Once you've established the formula, the process becomes straightforward.
Given the formula \[ a_{n} = 3 \times 4^{(n-1)} \], you need to substitute \(n = 7\) to find the seventh term.
This looks like:
Given the formula \[ a_{n} = 3 \times 4^{(n-1)} \], you need to substitute \(n = 7\) to find the seventh term.
This looks like:
- Calculate \(4^{(7-1)} = 4^6 = 4096\). You raise 4 to the power of 6.
- Multiply the result by the first term, \(3 \times 4096\), giving you \(12288\).
general term formula
The general term formula is a powerful mathematical expression that provides a universal way to find any term in a sequence, given the position of the term required. In a geometric sequence, this formula is: \( a_{n} = a_{1} * r^{(n-1)} \).
Breaking down its components:
Breaking down its components:
- \(a_{1}\), the first term, anchors the sequence.
- The exponent \(r^{(n-1)}\) involves the common ratio raised to one less than the term number, reflecting the repeated multiplication needed to reach \(a_{n}\).
Other exercises in this chapter
Problem 16
Find the indicated term of the arithmetic sequence with first term, \(a_{1},\) and common difference, \(d .\) Find \(a_{16}\) when \(a_{1}=9, d=2\)
View solution Problem 17
You are dealt one card from a standard 52-card deck. Find the probability of being dealt $$\text{a queen.}$$
View solution Problem 17
Use the Binomial Theorem to expand each binomial and express the result in simplified form. $$ \left(x^{2}+2 y\right)^{4} $$
View solution Problem 17
A medical researcher needs 6 people to test the effectiveness of an experimental drug. If 13 people have volunteered for the test, in how many ways can 6 people
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