Problem 17
Question
In \(15-26,\) write the first five terms of each geometric sequence. $$ a_{1}=2, r=3 $$
Step-by-Step Solution
Verified Answer
The first five terms are 2, 6, 18, 54, 162.
1Step 1: Understanding the Problem
We need to find the first five terms of a geometric sequence. We are given the first term, \( a_1 = 2 \), and the common ratio, \( r = 3 \).
2Step 2: Formula for the nth Term
In a geometric sequence, the \( n \)-th term is given by the formula: \( a_n = a_1 \, r^{n-1} \). We will use this formula to calculate each of the first five terms.
3Step 3: Calculate the First Term
The first term is already given: \( a_1 = 2 \).
4Step 4: Calculate the Second Term
Using the formula \( a_n = a_1 \, r^{n-1} \), calculate \( a_2 \): \( a_2 = 2 \, (3)^1 = 2 \, \times \, 3 = 6 \).
5Step 5: Calculate the Third Term
Calculate \( a_3 \) using the formula: \( a_3 = 2 \, (3)^2 = 2 \, \times \, 9 = 18 \).
6Step 6: Calculate the Fourth Term
Calculate \( a_4 \): \( a_4 = 2 \, (3)^3 = 2 \, \times \, 27 = 54 \).
7Step 7: Calculate the Fifth Term
Calculate \( a_5 \): \( a_5 = 2 \, (3)^4 = 2 \, \times \, 81 = 162 \).
8Step 8: List the First Five Terms
The first five terms of the sequence are: 2, 6, 18, 54, 162.
Key Concepts
Common RatioNth Term FormulaSequence CalculationFirst Five Terms
Common Ratio
In a geometric sequence, understanding the common ratio is crucial. It tells you how each term relates to the one before it. You get it by dividing any term by the term that comes before it. For instance, with the sequence starting at 2 and having terms 2, 6, 18, and so on, the common ratio is 3. So, each term is three times the one before it.
- If you have the sequence 2, 6, 18, 54, the common ratio, 3, means: 6 is 3 times 2, 18 is 3 times 6, and so forth.
- The common ratio keeps the sequence growing or shrinking at a consistent rate.
Nth Term Formula
The nth term formula in a geometric sequence helps determine the specific position of any term without listing all previous ones. The formula is:\[ a_n = a_1 \, r^{n-1} \]Where:
- \( a_n \) is the term you want to find.
- \( a_1 \) is the first term in the sequence.
- \( r \) is the common ratio.
- \( n \) is the term number.
Sequence Calculation
To calculate terms in a geometric sequence, you repeatedly use the nth term formula. This method ensures accuracy because each calculation is based on solid mathematics. Ensuring your calculations are correct means understanding the base term and the common ratio well. Here’s the step-by-step to find terms:
- Start with the given first term, \( a_1 \). For example, 2.
- Use the common ratio to find subsequent terms by applying \( a_n = a_1 \, r^{n-1} \).
- Adjust the exponent in \( r^{n-1} \) according to the term number you find.
First Five Terms
Now that we know how to calculate the terms, let's focus on the first five terms of a geometric sequence. We already have the first term, which is 2. Starting from it, we apply the common ratio iteratively using the nth term formula.
- First term, \( a_1 \), is given as 2.
- Second term, \( a_2 = 2 \, (3)^{1} = 6 \).
- Third term, \( a_3 = 2 \, (3)^{2} = 18 \).
- Fourth term, \( a_4 = 2 \, (3)^{3} = 54 \).
- Fifth term, \( a_5 = 2 \, (3)^{4} = 162 \).
Other exercises in this chapter
Problem 17
In \(15-26,\) write each series in sigma notation. $$ 1^{1}+2^{2}+3^{3}+4^{4}+5^{5} $$
View solution Problem 17
In \(15-22 :\) a. Write each sum as a series. b. Find the sum of each series. $$ 10+\sum_{n=1}^{5} 10\left(\frac{1}{2}\right)^{n} $$
View solution Problem 17
The sum of the infinite series \(1+\frac{1}{2}+\frac{1}{2^{2}}+\frac{1}{2^{3}}+\cdots+\frac{1}{2^{n}}\) is \(2 .\) Find values of \(n\) such that \(2-a_{n}
View solution Problem 17
In \(3-18,\) write the first five terms of each sequence. $$ a_{n}=\frac{4 n}{3} $$
View solution