Problem 17
Question
Helium atom is two times heavier than a hydrogen molecule. At 298 \(\mathrm{K}\), the average kinetic energy of a helium atom is (a) two times that of a hydrogen molecule. (b) same as that of a hydrogen molecule. (c) four times that of a hydrogen molecule. (d) half that of a hydrogen molecule.
Step-by-Step Solution
Verified Answer
(b) Same as that of a hydrogen molecule.
1Step 1: Understand the Relationship of Kinetic Energy
The average kinetic energy of a gas particle depends only on the temperature and is given by the formula \( \frac{3}{2}kT \), where \( k \) is the Boltzmann constant and \( T \) is the temperature in Kelvin. This implies that the average kinetic energy of a gas particle is the same for all gases at the same temperature.
2Step 2: Apply the Kinetic Energy Formula to Both Gases
Since the average kinetic energy formula \( \frac{3}{2}kT \) holds, we can say that at 298 K, both helium and hydrogen will have the same kinetic energy because their energies depend only on the temperature, not mass or any other factor.
3Step 3: Compare the Kinetic Energies
Since the temperature is the same for both helium atoms and hydrogen molecules, the average kinetic energy of helium atoms is the same as that of hydrogen molecules, regardless of the fact that helium atoms are heavier.
4Step 4: Select the Correct Option
Based on our analysis, the correct answer is option (b), which states that the average kinetic energy of a helium atom is the same as that of a hydrogen molecule at 298 K.
Key Concepts
Boltzmann ConstantTemperature Dependence of Kinetic EnergyGas Laws at Constant Temperature
Boltzmann Constant
The Boltzmann constant, denoted as \( k \), is a fundamental physical constant that plays a crucial role in the kinetic theory of gases. It relates the average kinetic energy of particles in a gas to the temperature of the gas. Mathematically, it can be expressed as:\[ k = 1.38 \times 10^{-23} \text{ J/K} \]This tiny value signifies that at the level of individual atoms and molecules, the energy is exceedingly small.
- It is the bridge between the macroscopic and microscopic worlds, allowing us to connect the temperature (a macroscopic property) with the kinetic energy of particles (a microscopic property).
- In calculations involving gases, the Boltzmann constant ensures that the units are consistent, particularly when dealing with temperature in Kelvin.
Temperature Dependence of Kinetic Energy
The temperature of a gas is directly related to the average kinetic energy of its particles. This relationship is vital for understanding how gases behave under different thermal conditions. The formula given by:\[ KE = \frac{3}{2}kT \]where \( KE \) is the average kinetic energy per particle, \( k \) is the Boltzmann constant, and \( T \) is the temperature in Kelvin, explains this dependency.
- As the temperature increases, the average kinetic energy of the gas particles also increases. This means they move faster and collide more vigorously.
- Conversely, a decrease in temperature leads to a decrease in kinetic energy, causing the particles to move more slowly.
Gas Laws at Constant Temperature
Gas laws, such as Boyle's Law and Charles's Law, describe how gases behave under various conditions. When the temperature is held constant, some interesting behaviors arise:
- Boyle's Law: This principle states that for a given mass of gas at a constant temperature, the volume of the gas is inversely proportional to the pressure. This means if the pressure increases, the volume decreases, and vice versa.
- Charles's Law: Although this law is more typically associated with variations in temperature, at constant pressure, it shows how the volume of a gas is directly proportional to its temperature. With a fixed temperature, gases maintain a steady volume when pressure is applied.
Other exercises in this chapter
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