Problem 17
Question
Graph the linear equations and inequalities. $$ y-5<3 $$
Step-by-Step Solution
Verified Answer
Answer: The graph of the linear inequality \(y-5<3\) consists of a dashed horizontal line at \(y=8\), and the solution region is the area below this line, representing all points with y-values less than 8.
1Step 1: Rewrite the inequality in the slope-intercept form
We need to rewrite inequality \(y-5<3\) in the slope-intercept form (\(y=mx+b\)). To do this, we need to isolate the y. So in this case, we have:
$$
y<3+5
$$
$$
y<8
$$
Now, the inequality is in the slope-intercept form (\(y=8\)).
2Step 2: Sketch the boundary line
Next, we will draw the boundary line \(y=8\). Since the inequality is less than (\(<\)) and not less than or equal to (\(\le\)), we will draw a dashed (not solid) line at \(y=8\).
3Step 3: Shade the solution region
Now we need to shade the solution region for the inequality. Since the inequality states that \(y<8\), we will shade the region below the dashed line at \(y=8\). This shaded region represents all the points where the y values are less than 8 and satisfy the given inequality.
That's it! We have graphed the linear inequality \(y-5<3\). The dashed line at \(y=8\) represents the boundary, and the shaded region below the line represents the solution to the inequality.
Key Concepts
Graphing InequalitiesSlope-Intercept FormBoundary Lines
Graphing Inequalities
Graphing inequalities is a crucial skill in algebra. When we graph an inequality, we effectively show all the possible solutions that satisfy the inequality on a coordinate plane. For instance, in the case of the inequality \(y < 8\), we are interested in all the values of \(y\) that are less than 8. When graphing inequalities, you need to keep in mind a few key steps:
- First, graph the related equation as if the inequality were an equality. For \(y < 8\), this related equation is \(y = 8\).
- If the inequality is strict, such as \(>\) or \(<\), use a dashed line to indicate that points on this line are not included in the solution set. If the inequality includes equal to, such as \(\leq \) or \(\geq \), use a solid line to include all points on the line in the solution set.
- Shade the area of the graph where the inequality holds true. This shaded region represents all possible solutions. Keep a watch on the inequality sign and shade the correct side of the boundary line.
Slope-Intercept Form
The slope-intercept form is a standard way of writing the equation of a line. It makes graphing the line very straightforward. The general format is \(y = mx + b\), where \(m\) represents the slope of the line, and \(b\) is the y-intercept. For our inequality \(y < 8\), the slope-intercept form is particularly simple because there is no slope. However, understanding this form helps as:
- The y-intercept \(b=8\) directly tells us where the line intersects the y-axis. In our equation \(y=8\), the y-intercept is 8.
- The slope \(m\) is crucial in more complex problems where the line has a rise over run, but in this particular case, it's zero since it is a horizontal line.
Boundary Lines
Boundary lines are essential when graphing linear inequalities. They serve as a visual demarcation between the solutions and non-solutions of an inequality on the graph. In the inequality \(y < 8\), the boundary line is \(y = 8\), and it is dashed, indicating that it is not part of the solution.Here's what to keep in mind about boundary lines:
- An inequality like \(y < 8\) means we draw a dashed line because y can be any value less than 8, but not equal to 8. Hence, the line itself is not included in the solution set.
- Conversely, an inequality with \(\leq\) or \(\geq\) would mean drawing a solid boundary line because points on the line are included in the solution.
- Once the boundary line is drawn, shading below or above the line, depending on the inequality, completes the graph. This shading visually represents the solution set.
Other exercises in this chapter
Problem 17
The formula for finding the slope of a line through any two given points \(\left(x_{1}, y_{1}\right)\) and \(\left(x_{2}, y_{2}\right)\) is \(m=\frac{y_{2}-y_{1
View solution Problem 17
For the following problems, graph the equations. $$ 2 x-y+4=0 $$
View solution Problem 18
For the following problems, find the equation of the line using the information provided. Write the equation in slope-intercept form. passes through the points
View solution Problem 18
For the following problems, write the equation of the line using the given information in slope-intercept form. $$ m=-6, y \text { -intercept }(0,-1) $$
View solution