Problem 17
Question
\(f(x)=x-|x|\)
Step-by-Step Solution
Verified Answer
\(f(x) = 0\) for \(x \geq 0\); \(f(x) = 2x\) for \(x < 0\).
1Step 1: Understanding the Absolute Value
The function contains an absolute value, \(|x|\), which is defined as \(|x| = x\) when \(x \geq 0\) and \(|x| = -x\) when \(x < 0\). This means the absolute value function will split our function into two cases based on the sign of \(x\).
2Step 2: Case 1: When \(x \geq 0\)
For \(x \geq 0\), the absolute value \(|x| = x\). Thus, the function simplifies to:\[ f(x) = x - |x| = x - x = 0 \]So, for all non-negative \(x\), \(f(x) = 0\).
3Step 3: Case 2: When \(x < 0\)
For \(x < 0\), the absolute value \(|x| = -x\). Thus, the function becomes:\[ f(x) = x - |x| = x - (-x) = x + x = 2x \]So, for all negative \(x\), \(f(x) = 2x\).
4Step 4: Combining Both Cases
Now we combine the results of both cases: \[ f(x) = \begin{cases} 0, & \text{if } x \geq 0 \ 2x, & \text{if } x < 0 \end{cases} \]This piecewise function summarizes the behavior of \(f(x)\) based on the sign of \(x\).
Key Concepts
Piecewise FunctionFunction BehaviorAlgebraic Expressions
Piecewise Function
A piecewise function is a type of function characterized by different expressions for different intervals of the input variable. **These intervals usually depend on some conditions, such as the value of the input variable.**
In mathematics, unlike regular functions, piecewise functions can have different rules or expressions based on the input values.
\[f(x) = \begin{cases} 0, & \text{if } x \geq 0 \ 2x, & \text{if } x < 0 \end{cases} \]
This notation shows clearly how the expression for \( f(x) \) changes depending on whether \( x \) is non-negative or negative. Piecewise functions are very useful in representing situations where rules change based on certain conditions, like tax brackets or speed limits.
In mathematics, unlike regular functions, piecewise functions can have different rules or expressions based on the input values.
- They are written using different cases, each with its corresponding condition.
- Commonly, there are at least two cases, often split by a specific value of the input.
\[f(x) = \begin{cases} 0, & \text{if } x \geq 0 \ 2x, & \text{if } x < 0 \end{cases} \]
This notation shows clearly how the expression for \( f(x) \) changes depending on whether \( x \) is non-negative or negative. Piecewise functions are very useful in representing situations where rules change based on certain conditions, like tax brackets or speed limits.
Function Behavior
Function behavior refers to the changes in the function's output as its input varies. It helps to understand how the function reacts to different input values, and what patterns or properties can be observed.
- One key aspect of function behavior is identifying intervals where the function has specific expressions or rules, like in a piecewise function.
- This can involve determining when the function is increasing, decreasing, constant, or when it exhibits symmetry.
- When \( x \geq 0 \), the function remains constant at 0. This means it does not increase or decrease as long as \( x \) is non-negative.
- When \( x < 0 \), the function increases as \( x \) becomes less negative, since \( f(x) = 2x \) leads the value to be negative but smaller as \( x \) approaches 0 from the left.
Algebraic Expressions
Algebraic expressions form the backbone of mathematical problem-solving and are crucial in constructing and simplifying functions. **They consist of variables, numbers, and arithmetic operations.** In our function \( f(x) = x - |x| \), the expression involves a combination of a linear term and an absolute value.
Understanding and manipulating algebraic expressions enable us to break down complex problems into simpler parts.
Understanding and manipulating algebraic expressions enable us to break down complex problems into simpler parts.
- The expression \( x - |x| \) captures how subtraction of an absolute value affects the behavior of the function, leading to a transformation into a piecewise format.
- Algebraic techniques involve simplifying expressions by combining like parts and managing operations such as addition, subtraction, and factoring.
Other exercises in this chapter
Problem 16
\(V\) varies jointly as \(h\) and the square of \(r\), and \(V=1100\) when \(h=14\) and \(r=5 . \quad \frac{22}{7}\)
View solution Problem 16
If \(f(x)=\left\\{\begin{array}{ll}3 x+2 & \text { for } x \geq 0 \\ 5 x-1 & \text { for } x
View solution Problem 17
Determine the linear function whose graph is a line with a slope of \(\frac{2}{3}\) and contains the point \((-1,3)\). $$ f(x)=\frac{2}{3} x+\frac{11}{3} $$
View solution Problem 17
If \(f(x)=\left\\{\begin{array}{rl}2 x & \text { for } x \geq 0 \\ -2 x & \text { for } x
View solution