Problem 17
Question
\(\frac{5}{3 n}-\frac{1}{9}=\frac{1}{n}\)
Step-by-Step Solution
Verified Answer
The value of \(n\) is 6.
1Step 1: Clear the Denominators
First, identify the common denominator for the fractions, which is \(9n\). Multiply each term of the equation by \(9n\) to eliminate the fractions: \(9n \times \frac{5}{3n} - 9n \times \frac{1}{9} = 9n \times \frac{1}{n}\). This simplifies to: \(3 imes 5 - n = 9\). So, the equation becomes \(15 - n = 9\).
2Step 2: Isolate the Variable
To solve for \(n\), add \(n\) to both sides of the equation to move it to the right side:\(15 = n + 9\).
3Step 3: Solve the Equation
Subtract \(9\) from both sides to isolate \(n\): \(15 - 9 = n\). Therefore, \(n = 6\).
4Step 4: Verify the Solution
Substitute \(n = 6\) back into the original equation to check if it satisfies the equation:\(\frac{5}{3 \times 6}-\frac{1}{9} = \frac{1}{6}\). This simplifies to \(\frac{5}{18} - \frac{2}{18} = \frac{3}{18}\), which is the same as \(\frac{1}{6}\), confirming the solution is correct.
Key Concepts
Solving EquationsFractionsVariable IsolationVerification of Solution
Solving Equations
Solving equations is a fundamental skill in elementary algebra. It's like solving a puzzle where each piece must fit to reveal the correct solution.
In equations, we have variables that represent unknown values, and the goal is to determine their value. This often involves simplifying both sides of the equation and performing operations that maintain the balance of the equation.
A key principle is that whatever operation you perform on one side, you must also perform on the other side.
In equations, we have variables that represent unknown values, and the goal is to determine their value. This often involves simplifying both sides of the equation and performing operations that maintain the balance of the equation.
A key principle is that whatever operation you perform on one side, you must also perform on the other side.
- This can include:
- Adding or subtracting the same number from both sides
- Multiplying or dividing both sides by the same number (except zero)
Fractions
Fractions can seem tricky at first, but they are just another way to represent numbers.
When dealing with fractions in equations, it's important to remember that a fraction is just a division problem: the numerator is divided by the denominator.
One way to simplify equations with fractions is to eliminate the fractions altogether.
This is usually done by finding a common denominator, which allows the fractions to be rewritten with the same bottom number, making them easier to combine or eliminate.
In our exercise example, we used a similar method to clear the fractions by multiplying the entire equation by the least common multiple of the denominators. This step helps to convert the equation into an easier form without fractions, making it simpler to solve.
Always simplify the fractions if possible before further calculations, either by reducing them or by applying operations such as multiplication or division.
When dealing with fractions in equations, it's important to remember that a fraction is just a division problem: the numerator is divided by the denominator.
One way to simplify equations with fractions is to eliminate the fractions altogether.
This is usually done by finding a common denominator, which allows the fractions to be rewritten with the same bottom number, making them easier to combine or eliminate.
In our exercise example, we used a similar method to clear the fractions by multiplying the entire equation by the least common multiple of the denominators. This step helps to convert the equation into an easier form without fractions, making it simpler to solve.
Always simplify the fractions if possible before further calculations, either by reducing them or by applying operations such as multiplication or division.
Variable Isolation
Variable isolation is the technique of moving all terms containing the variable to one side of the equation.
Simply put, it's like trying to get the variable 'alone' on one side.
This is crucial because it allows us to find the value of the variable without confusion.
In practice, we achieve this by using inverse operations. For example:
Once isolated, it's easy to see what operation will solve for the variable.
Simply put, it's like trying to get the variable 'alone' on one side.
This is crucial because it allows us to find the value of the variable without confusion.
In practice, we achieve this by using inverse operations. For example:
- If a term with a variable is being added, subtract it from both sides.
- If it's being subtracted, add it to both sides.
- If it's being multiplied, divide both sides by that number.
- And if it's divided, multiply both sides accordingly.
Once isolated, it's easy to see what operation will solve for the variable.
Verification of Solution
Verification is an essential final step in solving algebraic equations. It acts like a safety net to ensure the solution is correct.
To verify a solution, substitute the value back into the original equation to see if it creates a true statement.
This step confirms that the solution works not just in our modified version of the equation, but in the original setup as well.
To verify a solution, substitute the value back into the original equation to see if it creates a true statement.
This step confirms that the solution works not just in our modified version of the equation, but in the original setup as well.
- Replace the variable in the equation with the value you found.
- Simplify both sides to verify they are equal.
Other exercises in this chapter
Problem 17
For Problems 1-40, perform the indicated operations and express answers in simplest form. $$ \frac{1}{x^{2}-6 x}-\frac{1}{x^{2}+6 x} $$
View solution Problem 17
$$ \text { For Problems 1-32, solve each equation. (Objective 1) } $$ $$ \frac{4}{x-1}-\frac{2 x-3}{x^{2}-1}=\frac{6}{x+1} $$
View solution Problem 18
Perform the indicated multiplications and divisions and express your answers in simplest form. $$\frac{-2}{7 a^{2} b^{3}} \div \frac{1}{9 a b^{4}}$$
View solution Problem 18
Add or subtract as indicated. Be sure to express your answers in simplest forn. (Objective 1) $$\frac{9 a-1}{6}-\frac{4 a-2}{6}$$
View solution