Problem 17
Question
For the following problems, factor the trinomials when possible. $$ a^{2}+3 a-4 $$
Step-by-Step Solution
Verified Answer
Answer: The factored form of the trinomial is $$(a-1)(a+4)$$.
1Step 1: Identify the factors of the constant term
Find the factors of the constant term, -4. The pairs of factors are (-1, 4) and (1, -4).
2Step 2: Determine the correct factors to sum up to the linear term coefficient
Now, we want to find the pair of factors of -4 that sum up to the coefficient of the linear term, which is 3. In this case, the correct pair is (-1, 4) because -1 + 4 = 3.
3Step 3: Write the factored form
We found that the pair (-1, 4) satisfies both conditions. So the factored form will be:
(a-1) (a+4)
4Step 4: Final Answer
The factored form of the trinomial is
$$
(a-1)(a+4)
$$
Key Concepts
Polynomial FactorizationQuadratic EquationsAlgebraic Expressions
Polynomial Factorization
Factoring trinomials is an essential part of polynomial factorization, which helps to simplify and solve polynomial equations. When we factor a polynomial, we are essentially expressing it as a product of simpler polynomials. This process is somewhat similar to factoring numbers, where we decompose a number into its prime factors. In the context of the polynomial \( a^2 + 3a - 4 \), we'd like to express it in the form of \((a + m)(a + n)\). By understanding the relationships between the coefficients and the constant term, we can break down complex expressions into simpler, more manageable ones.
Here's a more intuitive way to think about it: each term in the trinomial is related. The constant term, in our example \(-4\), is the product of the numbers \(m\) and \(n\), and the linear term coefficient \(3\) is the sum of \(m\) and \(n\). By working through this step-by-step, we can find appropriate values for \(m\) and \(n\) that satisfy both conditions.
Here's a more intuitive way to think about it: each term in the trinomial is related. The constant term, in our example \(-4\), is the product of the numbers \(m\) and \(n\), and the linear term coefficient \(3\) is the sum of \(m\) and \(n\). By working through this step-by-step, we can find appropriate values for \(m\) and \(n\) that satisfy both conditions.
Quadratic Equations
Quadratic equations are a particular type of polynomial equation characterized by the term \(ax^2\) where \(a eq 0\). They follow the standard form \(ax^2 + bx + c\). In our exercise, the quadratic equation \(a^2 + 3a - 4\) is factored as \((a-1)(a+4)\). This form allows us to solve the equation by setting each factor equal to zero.
Solving quadratic equations through factoring involves these steps:
Solving quadratic equations through factoring involves these steps:
- Express the quadratic in standard form.
- Factor the quadratic expression into two binomials.
- Set each binomial equal to zero to solve for the variable.
Algebraic Expressions
Algebraic expressions, like \(a^2 + 3a - 4\) in our exercise, are combinations of variables, coefficients, and constants linked together by operations such as addition, subtraction, multiplication, and division. Understanding how to manipulate these expressions is key to solving a wide range of algebra problems.
Here are some key insights about dealing with algebraic expressions:
Here are some key insights about dealing with algebraic expressions:
- A trinomial is an algebraic expression consisting of three terms.
- Each term is separated by either an addition or subtraction sign.
- Factoring transforms a complex expression into a simpler product of factors.
Other exercises in this chapter
Problem 16
In the following problems, the first quantity represents the product and the second quantity represents a factor of that product. Find the other factor. $$ 25 a
View solution Problem 17
For the following problems, the first quantity represents the product and the second quantity a factor. Find the other factor. $$ 6 y^{2}-24 y, 6 y $$
View solution Problem 17
For the following problems, factor the binomials. $$ x^{2}-16 $$
View solution Problem 17
For the following problems, use the grouping method to factor the polynomials. Some polynomials may not. be factorable using the grouping method. $$ 8 y^{4}-5 y
View solution