Problem 17

Question

For exercises \(5-48\), simplify. $$ \frac{n^{2}}{n^{2}+3 n+2}-\frac{1}{n^{2}+3 n+2} $$

Step-by-Step Solution

Verified
Answer
\( \frac{n - 1}{n + 2} \)
1Step 1: Identify the common denominator
Notice that both fractions share the same denominator: \( n^2 + 3n + 2 \).
2Step 2: Combine the fractions
Combine the fractions over the common denominator: \( \frac{n^{2}}{n^{2}+3n+2} - \frac{1}{n^{2}+3n+2} = \frac{n^{2} - 1}{n^{2}+3n+2} \).
3Step 3: Simplify the numerator
Notice that the numerator \( n^2 - 1 \) can be factored using the difference of squares: \( n^2 - 1 = (n - 1)(n + 1) \).
4Step 4: Factor the denominator
Factor the denominator \( n^2 + 3n + 2 \). Find the factors of 2 that add up to 3: \( (n + 1)(n + 2) \).
5Step 5: Simplify the fraction
Combine your factored parts to get \( \frac{(n - 1)(n + 1)}{(n + 1)(n + 2)} \). Cancel out the common term \( (n + 1) \) to simplify to \( \frac{n - 1}{n + 2} \).

Key Concepts

Factoring PolynomialsCombining FractionsDifference of SquaresCommon Denominators
Factoring Polynomials
Factoring polynomials breaks down complex expressions into simpler components. In our solution, we factor the denominator \( n^2 + 3n + 2 \). This expression is simplified by finding two numbers that multiply to give the constant term (2) and add to give the middle coefficient (3).
This leads us to the factors \( (n + 1) \) and \( (n + 2) \). Thus, \( n^2 + 3n + 2 = (n + 1)(n + 2) \).
The numerator \( n^2 - 1 \) is factored using the difference of squares, resulting in \( (n - 1)(n + 1) \).
Factoring helps in straightforward manipulation and simplification.
Combining Fractions
Combining fractions means to express them as a single fraction. Fractions can only be combined directly if they have a common denominator. In the given problem:
  • We start with two fractions: \( \frac{n^2}{n^2 + 3n + 2} \) and \( \frac{1}{n^2 + 3n + 2} \).
  • Since both have the same denominator \( n^2 + 3n + 2 \), we can combine them.
By placing them over a common denominator, we get:
\[ \frac{n^2 - 1}{n^2 + 3n + 2} \]Combining fractions simplifies the equation and makes it easier to further simplify and solve.
Difference of Squares
The difference of squares is a special factoring formula:\( a^2 - b^2 = (a - b)(a + b) \). In our problem:
  • The numerator \( n^2 - 1 \) can be seen as the difference of squares with \( n^2 \) and \( 1 \) or \( (n)^2 - (1)^2 \).
  • Using the difference of squares formula, we get \( (n - 1)(n + 1) \).
This step is crucial as it simplifies the numerator, allowing for possible cancellations with the denominator further down the simplification process.
Common Denominators
Common denominators are key when combining fractions. A common denominator is a shared multiple of the denominators of each fraction involved. In this problem,\( n^2 + 3n + 2 \) acts as the common denominator.
Using the factored form:\( (n + 1)(n + 2) \), both fractions can be rewritten simply. This allows us to easily combine and later simplify the fractions. Here's a step-by-step breakdown:
  • Recognize the shared denominator in each fraction.
  • Write the fractions under a single denominator.
  • Simplify by reducing and canceling common factors.
This method helps in transforming complex equations into manageable ones, enabling further simplification and solution.