Problem 17
Question
For each matrix, find \(A^{-1}\) if it exists. Do not use a calculator. $$A=\left[\begin{array}{lll} 0 & 0 & 1 \\ 1 & 0 & 0 \\ 0 & 1 & 0 \end{array}\right]$$
Step-by-Step Solution
Verified Answer
The inverse of matrix \(A\) is \(\begin{bmatrix} 0 & 0 & 1 \\ 0 & 0 & 0 \\ 1 & 0 & 0 \end{bmatrix}\).
1Step 1: Verify if the Matrix is Square
The first step in finding the inverse of a matrix is to check if it is square, which means it should have the same number of rows and columns. The given matrix \(A\) is a 3x3 matrix. Therefore, it is square.
2Step 2: Calculate the Determinant
For a 3x3 matrix, the determinant \( \text{det}(A) \) needs to be non-zero for an inverse to exist. Calculate the determinant using the formula:\[\text{det}(A) = a(ei − fh) − b(di − fg) + c(dh − eg)\]For matrix \( A = \begin{bmatrix} 0 & 0 & 1 \ 1 & 0 & 0 \ 0 & 1 & 0 \end{bmatrix} \), substitute:\[\text{det}(A) = 0(0 \cdot 0 - 1 \cdot 1) - 0(1 \cdot 0 - 0 \cdot 0) + 1(1 \cdot 1 - 0 \cdot 0) = 1\]Since the determinant is 1, the inverse exists.
3Step 3: Find the Adjoint Matrix
The adjoint of a 3x3 matrix is the transpose of its cofactor matrix. Find the cofactor for each element and form the cofactor matrix. For matrix \( A \):- The cofactor of element at (1,1): \(+1(0 \cdot 0 - 1 \cdot 0) = 0\)- The cofactor of element at (1,2): \(-1(1 \cdot 0 - 0 \cdot 0) = 0\)- The cofactor of element at (1,3): \(+1(1 \cdot 1 - 0 \cdot 0) = 1\)Continue this for all elements and transpose the cofactor matrix:\[\text{Adj}(A) = \begin{bmatrix} 0 & 0 & 1 \ 0 & 0 & 0 \ 1 & 0 & 0 \end{bmatrix}\]
4Step 4: Compute the Inverse Using Adjoint
The inverse of matrix \( A \) is given by the formula:\[A^{-1} = \frac{1}{\text{det}(A)} \cdot \text{Adj}(A)\]Substitute the known values:\[A^{-1} = \frac{1}{1} \cdot \begin{bmatrix} 0 & 0 & 1 \ 0 & 0 & 0 \ 1 & 0 & 0 \end{bmatrix} = \begin{bmatrix} 0 & 0 & 1 \ 0 & 0 & 0 \ 1 & 0 & 0 \end{bmatrix}\]
Key Concepts
DeterminantAdjoint MatrixCofactor MatrixSquare Matrix
Determinant
The determinant of a matrix is a special number that can be calculated from its elements. It's an important factor in finding out if a matrix can be inverted. For a square matrix, if the determinant is zero, it means the matrix doesn't have an inverse.
To calculate the determinant of a 3x3 matrix, like matrix \( A \) in our exercise, use the specific formula:
To calculate the determinant of a 3x3 matrix, like matrix \( A \) in our exercise, use the specific formula:
- Identify elements of the matrix as \( a, b, c \) in the first row, \( d, e, f \) in the second row, and \( g, h, i \) in the third row.
- Apply the formula: \( ext{det}(A) = a(ei − fh) − b(di − fg) + c(dh − eg)\).
Adjoint Matrix
The adjoint matrix, also known as the adjugate matrix, is a helpful tool when calculating the inverse of a square matrix.
To find the adjoint:
To find the adjoint:
- Calculate the cofactor for each entry in the matrix and form a new matrix from these cofactors. This matrix is known as the cofactor matrix.
- Transpose this cofactor matrix. Transposing involves flipping the matrix over its diagonal, swapping rows with columns.
Cofactor Matrix
The cofactor matrix is an essential part of calculating the adjoint. Each element in a cofactor matrix is a signed minor of the original matrix. Let’s break it down:
- The "minor" of an element is the determinant of the submatrix that remains after removing the row and column of that element.
- The "sign" follows a checkerboard pattern starting with a positive at the top left, alternating signs in a consistent manner.
Square Matrix
A square matrix is simply a matrix with the same number of rows and columns. This property is a prerequisite for calculating an inverse.
- Identifying if a matrix is square is the first step.
- Only square matrices can potentially have an inverse.
Other exercises in this chapter
Problem 17
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Perform each operation if possible. $$\left[\begin{array}{rrr}6 & -9 & 2 \\ 4 & 1 & 3\end{array}\right]+\left[\begin{array}{rrr}-8 & 2 & 5 \\ 6 & -3 & 4\end{arr
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Solve each system analytically. If the equations are dependent, write the solution set in terms of the variable \(z\). $$\begin{aligned} x+2 y+3 z &=8 \\ 3 x-y+
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