Problem 17
Question
Find the value of each expression. \(\csc \theta,\) if \(\cos \theta=-\frac{2}{3} ; 180^{\circ}<\theta<270\)
Step-by-Step Solution
Verified Answer
\( \csc \theta = -\frac{3\sqrt{5}}{5} \)
1Step 1: Determine the Quadrant
Given that \(180^{\circ} < \theta < 270^{\circ}\), \(\theta\) is in the third quadrant. In the third quadrant, sine is negative.
2Step 2: Use the Pythagorean Identity
We know \( \cos \theta = -\frac{2}{3} \), and in any triangle, \( \sin^2 \theta + \cos^2 \theta = 1 \).Substituting the value of \( \cos \theta \) into this equation:\[ \sin^2 \theta + \left(-\frac{2}{3}\right)^2 = 1 \]\[ \sin^2 \theta + \frac{4}{9} = 1 \]Rearrange to solve for \( \sin^2 \theta \):\[ \sin^2 \theta = 1 - \frac{4}{9} = \frac{5}{9} \].
3Step 3: Solve for \( \sin \theta \)
Since \( \theta \) is in the third quadrant where sine is negative, we take the negative square root:\[ \sin \theta = -\sqrt{\frac{5}{9}} = -\frac{\sqrt{5}}{3} \].
4Step 4: Find \( \csc \theta \)
The cosecant function is the reciprocal of sine, therefore:\[ \csc \theta = \frac{1}{\sin \theta} = \frac{1}{-\frac{\sqrt{5}}{3}} = -\frac{3}{\sqrt{5}} \].To rationalize the denominator, multiply by \( \frac{\sqrt{5}}{\sqrt{5}} \):\[ \csc \theta = -\frac{3\sqrt{5}}{5} \].
Key Concepts
Cosecant FunctionPythagorean IdentityTrigonometric IdentitiesThird Quadrant
Cosecant Function
The cosecant function, denoted as \( \csc \theta \), is a fundamental trigonometric function. It is used often in trigonometry to relate an angle in a right triangle to the lengths of its sides. This function is defined as the reciprocal of the sine function, which means that:
- \( \csc \theta = \frac{1}{\sin \theta} \)
Pythagorean Identity
In trigonometry, the Pythagorean identity is a fundamental relationship amongst the sine, cosine, and tangent functions. One of the most common forms of this identity is:
In the provided solution, we used this identity to find \( \sin \theta \) when \( \cos \theta \) was given as \(-\frac{2}{3}\). By rearranging the identity, we were able to determine \( \sin^2 \theta = \frac{5}{9} \) and subsequently the correct sign for \( \sin \theta \) based on the quadrant.
- \( \sin^2 \theta + \cos^2 \theta = 1 \)
In the provided solution, we used this identity to find \( \sin \theta \) when \( \cos \theta \) was given as \(-\frac{2}{3}\). By rearranging the identity, we were able to determine \( \sin^2 \theta = \frac{5}{9} \) and subsequently the correct sign for \( \sin \theta \) based on the quadrant.
Trigonometric Identities
Trigonometric identities are equations involving trigonometric functions that are always true, regardless of the angle. This powerful concept includes a variety of equations like basic identities (sine, cosine, tangent) and their reciprocals (cosecant, secant, cotangent), as well as compound and double angle identities.
- Reciprocal identities like \( \csc \theta = \frac{1}{\sin \theta} \)
- Pythagorean identities like \( \sin^2 \theta + \cos^2 \theta = 1 \)
- Coffunction identities such as \( \sin(90^\circ - \theta) = \cos \theta \)
Third Quadrant
Understanding the behavior of trigonometric functions in different quadrants is essential in trigonometry. The angle \( \theta \) given as between \(180^{\circ}\) and \(270^{\circ}\) places it squarely in the third quadrant of the unit circle. Each quadrant has distinct characteristics:
- First Quadrant: All trigonometric functions are positive.
- Second Quadrant: Sine is positive; others are negative.
- **Third Quadrant**: Tangents and cotangents are positive; sine and cosine are negative.
- Fourth Quadrant: Cosine is positive; others are negative.
Other exercises in this chapter
Problem 17
Find the exact value of each expression. \(\cos 225^{\circ}\)
View solution Problem 17
Verify that each of the following is an identity. $$ \frac{\sin \theta}{1-\cos \theta}+\frac{1-\cos \theta}{\sin \theta}=2 \csc \theta $$
View solution Problem 17
Find the amplitude, if it exists, and period of each function. Then graph each function. \(y=\frac{1}{3} \sec \theta\)
View solution Problem 18
Solve each equation for all values of ? if ? is measured in radians. \(\cos ^{2} \theta-\frac{5}{2} \cos \theta-\frac{3}{2}=0\)
View solution