Problem 17
Question
Find the quotient \(\frac{z_{1}}{z_{2}}\) and express it in rectangular form. $$z_{1}=9\left[\cos \left(\frac{5 \pi}{12}\right)+i \sin \left(\frac{5 \pi}{12}\right)\right] \text { and } z_{2}=3\left[\cos \left(\frac{\pi}{12}\right)+i \sin \left(\frac{\pi}{12}\right)\right]$$
Step-by-Step Solution
Verified Answer
The quotient in rectangular form is \(\frac{3}{2} + i\frac{3\sqrt{3}}{2}\).
1Step 1: Identify Given Complex Numbers
The given complex numbers are \(z_1 = 9 \left[ \cos \left( \frac{5 \pi}{12} \right) + i \sin \left( \frac{5 \pi}{12} \right) \right]\) and \(z_2 = 3 \left[ \cos \left( \frac{\pi}{12} \right) + i \sin \left( \frac{\pi}{12} \right) \right]\). Both are provided in polar form: \(z = r (\cos \theta + i \sin \theta)\).
2Step 2: Apply Division Formula for Complex Numbers
To divide two complex numbers in polar form \(z_1 = r_1 (\cos \theta_1 + i \sin \theta_1)\) and \(z_2 = r_2 (\cos \theta_2 + i \sin \theta_2)\), use the formula: \(\frac{z_1}{z_2} = \frac{r_1}{r_2} \left( \cos(\theta_1 - \theta_2) + i \sin(\theta_1 - \theta_2) \right)\).
3Step 3: Calculate Magnitude of Quotient
Calculate the magnitude of the quotient: \(\frac{9}{3} = 3\).
4Step 4: Determine Angle of the Quotient
Subtract the angles: \(\theta_1 = \frac{5\pi}{12}\) and \(\theta_2 = \frac{\pi}{12}\). Using \(\theta_1 - \theta_2 = \frac{5\pi}{12} - \frac{\pi}{12} = \frac{4\pi}{12} = \frac{\pi}{3}\).
5Step 5: Express Quotient in Polar Form
The quotient in polar form is \(3 \left( \cos\left(\frac{\pi}{3}\right) + i \sin\left(\frac{\pi}{3}\right) \right)\).
6Step 6: Convert to Rectangular Form
We know \(\cos\left(\frac{\pi}{3}\right) = \frac{1}{2}\) and \(\sin\left(\frac{\pi}{3}\right) = \frac{\sqrt{3}}{2}\). Thus, \(3 \left( \frac{1}{2} + i \frac{\sqrt{3}}{2} \right) = \frac{3}{2} + i\frac{3\sqrt{3}}{2}\).
Key Concepts
Polar FormRectangular FormTrigonometric Form of Complex Numbers
Polar Form
When dealing with complex numbers, the polar form is a powerful tool. It represents complex numbers in terms of their modulus and argument, typically written as \( z = r ( \cos \theta + i \sin \theta ) \). Here, \(r\) denotes the modulus or magnitude of the complex number, while \(\theta\) is the argument or angle. This form is particularly beneficial for multiplication and division of complex numbers, as illustrated in our example.
- The modulus \(r\) is the distance from the origin to the point in the complex plane, making it a measure of the size of the number.
- The argument \(\theta\) is the angle formed with the positive x-axis, indicating the direction of the number.
Rectangular Form
The rectangular form of a complex number expresses it as \( a + bi \), where \(a\) is the real part and \(b\) is the imaginary part. For some, this form is more intuitive since it aligns with standard Cartesian coordinates.
- In rectangular form, complex numbers appear identical to ordered pairs \((a, b)\) on the complex plane.
- It captures both magnitude and direction but through real and imaginary parts instead of polar coordinates.
Trigonometric Form of Complex Numbers
The trigonometric form of complex numbers, often confused with polar form, is expressed as \( z = r ( \cos \theta + i \sin \theta ) \), much like the polar form. This expression highlights the trigonometric representation of angles and can be a helpful bridge between polar and rectangular forms.
- Using the trigonometric functions, we describe both the orientation and length of the vector representing the complex number.
- It emphasizes the use of sine and cosine to establish the direction, leveraging their periodic nature.
Other exercises in this chapter
Problem 17
Find the angle (round to the nearest degree) between each pair of vectors. $$\langle-4,6\rangle \text { and }\langle-6,8\rangle$$
View solution Problem 17
Convert each point to exact polar coordinates. Assume that \(0 \leq \theta
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Express each complex number in polar form. $$3+0 i$$
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Perform the indicated vector operation, given \(u=(-4,3)\) and \(v=\langle 2,-5\rangle\) $$\mathbf{u}+\mathbf{v}$$
View solution