Problem 17
Question
Find the domain of the vector-valued functions. Domain: \(\mathbf{r}(t)=\left\langle\csc (t), \frac{1}{\sqrt{t-3}}, \ln (t-2)\right\rangle\)
Step-by-Step Solution
Verified Answer
Domain: \( (3, \infty) \setminus \{ n\pi \mid n \in \mathbb{Z} \} \).
1Step 1: Understand the Constraints of Cosecant Function
The cosecant function, represented as \( \csc(t) \), is defined as the reciprocal of the sine function. Therefore, \( \csc(t) \) is undefined when \( \sin(t) = 0 \). Since sine is zero at integer multiples of \( \pi \) (i.e., \( t = n\pi \), where \( n \) is an integer), \( \csc(t) \) is undefined at these points. Thus, \( t eq n\pi \).
2Step 2: Analyze the Square Root Function Constraint
For the term \( \frac{1}{\sqrt{t-3}} \), the term \( \sqrt{t-3} \) implies that \( t - 3 \) must be positive (i.e., \( t > 3 \)) to avoid division by zero or taking the square root of a negative number. This further means that \( t \) must be greater than 3.
3Step 3: Consider the Natural Log Function
The natural logarithm, denoted by \( \ln(t-2) \), is defined only for positive numbers. Therefore, \( t-2 > 0 \), which simplifies to \( t > 2 \). However, since we know from Step 2 that \( t > 3 \), this constraint is already satisfied as it is stronger.
4Step 4: Combine All Constraints for the Domain
Combine all restrictions from the previous steps. We have: \( t > 3 \) due to the square root and natural logarithm constraints, and \( t eq n\pi \) due to the cosecant constraint. Thus, the domain of the function \( \mathbf{r}(t) \) is: \( (3, \infty) \), excluding \( n\pi \), i.e., \( t \in (3, \infty) \setminus \{ n\pi \mid n \in \mathbb{Z} \} \).
Key Concepts
Cosecant FunctionNatural LogarithmSquare Root Function
Cosecant Function
The cosecant function is a fascinating mathematical construct closely related to the sine function. It is denoted as \( \csc(t) \) and is defined as the reciprocal of sine:
Visually, the graph of the cosecant function approaches infinity when \( t \) nears the points where the sine function is zero.
Understanding these gaps is crucial because they directly affect the domain of expressions involving the cosecant function.
- \( \csc(t) = \frac{1}{\sin(t)} \)
Visually, the graph of the cosecant function approaches infinity when \( t \) nears the points where the sine function is zero.
Understanding these gaps is crucial because they directly affect the domain of expressions involving the cosecant function.
Natural Logarithm
The natural logarithm, symbolized as \( \ln(x) \), is a special type of logarithmic function with base \( e \), where \( e \approx 2.71828 \). It is particularly useful in various scientific and engineering contexts. Essential properties of the natural logarithm include:
In our domain analysis, the constraint \( t > 2 \) from the natural logarithm is important, although other constraints can make it redundant when \( t > 3 \).
This shows the integral role the natural logarithm can play in defining the domain of more complex functions.
- It is defined only for positive values. Thus, the expression \( \ln(t-2) \) requires \( t-2 > 0 \), meaning \( t > 2 \).
- The function grows logarithmically, which means it increases but at a decreasing rate.
In our domain analysis, the constraint \( t > 2 \) from the natural logarithm is important, although other constraints can make it redundant when \( t > 3 \).
This shows the integral role the natural logarithm can play in defining the domain of more complex functions.
Square Root Function
The square root function is represented mathematically as \( \sqrt{x} \) and is a fundamental function in algebra and calculus. It extracts the principal (non-negative) square root of a given number. Key points to understand include:
These properties help shape the domain of more complex vector-valued functions, demonstrating how the square root function's constraints guide calculations and analysis in various mathematical contexts.
- The function is defined only for non-negative inputs, which means \( \sqrt{x} \) is only valid for \( x \geq 0 \).
- In the case of \( \frac{1}{\sqrt{t-3}} \), not only must \( t-3 \) be non-negative, but to prevent division by zero, \( t-3 > 0 \).
These properties help shape the domain of more complex vector-valued functions, demonstrating how the square root function's constraints guide calculations and analysis in various mathematical contexts.
Other exercises in this chapter
Problem 15
Find the domain of the vector-valued functions. Domain: \(\mathbf{r}(t)=\left\langle t^{2}, \tan t, \ln t\right\rangle\)
View solution Problem 16
Find the domain of the vector-valued functions. Domain: \(\mathbf{r}(t)=\left\langle t^{2}, \sqrt{t-3}, \frac{3}{2 t+1}\right\rangle\)
View solution Problem 18
Let \(\mathbf{r}(t)=\langle\cos t, t, \sin t\rangle\) and use it to answer the following questions. For what values of \(t\) is \(\mathbf{r}(t)\) continuous?
View solution Problem 19
Let \(\mathbf{r}(t)=\langle\cos t, t, \sin t\rangle\) and use it to answer the following questions. Sketch the graph of \(\mathbf{r}(t)\).
View solution