Problem 17
Question
Find the corresponding compartment diagram for each system of differential equations. \(\frac{d x_{1}}{d t}=-0.2 x_{1}\) \(\frac{d x_{2}}{d t}=-0.3 x_{2}\)
Step-by-Step Solution
Verified Answer
Two isolated compartments with outflows, \(-0.2 x_1\) and \(-0.3 x_2\).
1Step 1: Identify the Variables
In the given differential equations, the variables are \(x_1\) and \(x_2\). Each variable is related to a compartment in our diagram.
2Step 2: Understanding the Rate of Change
The equations \(\frac{d x_{1}}{d t}=-0.2 x_{1}\) and \(\frac{d x_{2}}{d t}=-0.3 x_{2}\) indicate that the rate of change of \(x_1\) and \(x_2\) is proportional to their current amounts. This suggests a self-limiting flow or decay process within each compartment.
3Step 3: Visualize Compartment Connections
The lack of interaction terms between \(x_1\) and \(x_2\) means that the compartments are isolated. Thus, neither transfers any substance to the other. Each compartment has an outflow proportional to its current value.
4Step 4: Drawing the Compartment Diagram
Draw two separate compartments, one for \(x_1\) and one for \(x_2\). Both compartments have arrows leading outwards, labeled with flows \(-0.2 x_1\) and \(-0.3 x_2\), respectively. This indicates that both \(x_1\) and \(x_2\) are being depleted or reduced independently over time.
Key Concepts
Compartmental AnalysisRate of ChangeIsolated Systems
Compartmental Analysis
Compartmental analysis is a method often used in biology and related fields to model the transfer of substances or quantities between different compartments, or sections, of a system. In the given problem, we have two compartments represented by the variables \(x_1\) and \(x_2\). Each compartment can be thought of as a separate "room" containing a specific quantity.
Understanding how these compartments interconnect or remain independent is crucial. In the exercise, since there are no interaction terms between \(x_1\) and \(x_2\), it indicates that each compartment operates in isolation. Therefore:
Understanding how these compartments interconnect or remain independent is crucial. In the exercise, since there are no interaction terms between \(x_1\) and \(x_2\), it indicates that each compartment operates in isolation. Therefore:
- There's no transfer of substance between \(x_1\) and \(x_2\).
- Each compartment has its unique inflows and outflows, depicted by the rates \( -0.2 x_1 \) and \( -0.3 x_2 \), respectively.
Rate of Change
The concept of rate of change in differential equations is central to understanding how quantities evolve within compartments over time. The equations provided in the exercise, \( \frac{d x_1}{dt} = -0.2 x_1 \) and \( \frac{d x_2}{dt} = -0.3 x_2 \), model how the quantities \(x_1\) and \(x_2\) decrease.
Each rate of change here is proportional to the current quantity contained within its compartment. This kind of relationship is characteristic of first-order decay processes often seen, for example, in radioactive decay or in the metabolism of drugs in pharmacokinetics:
Each rate of change here is proportional to the current quantity contained within its compartment. This kind of relationship is characteristic of first-order decay processes often seen, for example, in radioactive decay or in the metabolism of drugs in pharmacokinetics:
- The negative sign in each equation suggests a decay or reduction, implying that the quantity is diminishing over time, not increasing.
- A proportional rate means the more you have, the faster it decreases—like how a large ice block melts more slowly than smaller pieces under the same conditions.
- The constants \(-0.2\) and \(-0.3\) are the decay rates, numerically describing how quickly the reduction happens for each compartment.
Isolated Systems
An isolated system in the context of differential equations and compartments refers to one where components do not interact or exchange materials with one another. In this exercise, both \(x_1\) and \(x_2\) are treated as isolated from each other.
This isolation implies several key ideas:
This isolation implies several key ideas:
- Each compartment operates independently, with no exchange of content between them. This simplifies the mathematical analysis because each can be considered and solved separately.
- The equations for \(x_1\) and \(x_2\) contain no terms involving the other variable—confirming no interaction.
- In an isolated system, understanding and predicting the behavior is often easier, providing clear insights into how each component behaves strictly based on its internal factors.
Other exercises in this chapter
Problem 16
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