Problem 17
Question
Find the center and radius of each circle and graph it. $$ x^{2}+(y+3)^{2}=1 $$
Step-by-Step Solution
Verified Answer
Center: (0, -3), Radius: 1.
1Step 1: Identify the Standard Form
The equation provided is in the standard form for a circle: \[(x-h)^2 + (y-k)^2 = r^2\] where \(h\) and \(k\) represent the coordinates of the center of the circle, and \(r\) is the radius of the circle.
2Step 2: Determine the Center of the Circle
Compare the given equation \(x^2 + (y+3)^2 = 1\) with the standard form: \[(x-0)^2 + (y+(-3))^2 = 1\] It shows that the center of the circle is \((h, k) = (0, -3)\).
3Step 3: Calculate the Radius of the Circle
The radius \(r\) is the square root of the constant on the right side of the equation. Since \(1\) is on the right side:\[r = \sqrt{1} = 1\]Thus, the radius of the circle is 1.
Key Concepts
Standard Form of a CircleCenter of a CircleRadius of a CircleGraphing Circles
Standard Form of a Circle
The standard form of a circle equation is a fundamental concept in geometry, allowing us to easily identify key properties such as the center and radius of a circle. It is expressed as:\[ (x-h)^2 + (y-k)^2 = r^2 \]Here,
- \((h, k)\) represents the center of the circle.
- \(r\) is the radius of the circle.
Center of a Circle
Determining the center of a circle from its equation is straightforward when using the standard form. In the context of the equation \(x^2 + (y+3)^2 = 1\), it aligns with the standard form of:\[ (x-h)^2 + (y-k)^2 = r^2 \]By observation, we can see:
- \(h = 0\)
- \(k = -3\)
Radius of a Circle
The radius of a circle is the distance from its center to any point on the circle itself. It is found by taking the square root of the constant on the right side of the standard form equation. In the equation provided, \(x^2 + (y+3)^2 = 1\), the constant is 1.Calculating the radius involves extracting the square root from this constant value:
- \(r = \sqrt{1} = 1\)
Graphing Circles
Graphing a circle involves plotting its center on a coordinate plane and then using its radius to draw the boundary. For the circle described by the equation \(x^2 + (y+3)^2 = 1\), we have already identified:
- The center at \((0, -3)\)
- The radius of 1
Other exercises in this chapter
Problem 16
Find the center and radius of each circle and graph it. $$ x^{2}+y^{2}=16 $$
View solution Problem 16
Write each denominator in the equation \(\frac{x^{2}}{81}+\frac{y^{2}}{49}=1\) as the square of a number.
View solution Problem 17
Graph each equation. \(\frac{x^{2}}{25}+\frac{y^{2}}{4}=1\)
View solution Problem 18
Find the center and radius of each circle and graph it. $$ (x+4)^{2}+y^{2}=1 $$
View solution