Problem 17
Question
Find each indefinite integral. \(\int \frac{3}{2 v} d v\)
Step-by-Step Solution
Verified Answer
\( \frac{3}{2} \ln |v| + C \)
1Step 1: Identify the Integral Form
Recognize that the integral given is of the form \( \int \frac{a}{x} \, dx \), which can be directly integrated using the natural logarithm rule.
2Step 2: Apply the Natural Logarithm Rule
The integral \( \int \frac{1}{x} \, dx \) is equal to \( \ln |x| + C \), where \( C \) is the constant of integration. For the given integral, \( a = \frac{3}{2} \), so it becomes \( \frac{3}{2} \int \frac{1}{v} \, dv \).
3Step 3: Integrate Using the Coefficient Rule
Factor out the constant coefficient \( \frac{3}{2} \) from the integral to write it as \( \frac{3}{2} \ln |v| + C \). This is the result of integrating \( \int \frac{1}{v} \, dv \).
4Step 4: Write the Solution
Thus, the indefinite integral \( \int \frac{3}{2v} \, dv \) is \( \frac{3}{2} \ln |v| + C \), where \( C \) is the integration constant.
Key Concepts
Indefinite IntegralsNatural Logarithm RuleConstant of Integration
Indefinite Integrals
When we talk about indefinite integrals, we are essentially dealing with a function whose derivative is given. Unlike definite integrals, which calculate an area or a value over an interval, indefinite integrals focus on the general form of antiderivatives.
This is crucial because the process reverses differentiation, leading us back to the original function (up to a constant). To solve the exercise, we integrate the expression \( \frac{3}{2v} \) without specifying boundaries, so the result will always include \( +C \), representing any constant number.
- An indefinite integral is represented by the integral symbol followed by a function and its differential, such as \( \int f(x) \, dx \).
- The result is a family of functions, known as antiderivatives, which differ only by a constant.
This is crucial because the process reverses differentiation, leading us back to the original function (up to a constant). To solve the exercise, we integrate the expression \( \frac{3}{2v} \) without specifying boundaries, so the result will always include \( +C \), representing any constant number.
Natural Logarithm Rule
One of the most handy rules in calculus is the natural logarithm rule. It simplifies the integration process significantly when applied correctly. This rule comes in when you have an integral of the form \( \int \frac{1}{x} \, dx \). The result is the natural logarithm of the absolute value of \( x \), which is expressed as \( \ln |x| \).
Using this rule makes the integration process extremely efficient, cutting down complex algebraic manipulations otherwise necessary.
- The natural logarithm rule is applied because taking the derivative of \( \ln |x| \) returns \( \frac{1}{x} \), which perfectly aligns with the original integral we are trying to solve.
- In the exercise, identifying the integral formula allows us to use this rule on \( \frac{1}{v} \), resulting in \( \ln |v| \).
Using this rule makes the integration process extremely efficient, cutting down complex algebraic manipulations otherwise necessary.
Constant of Integration
When dealing with indefinite integrals, we must always remember the constant of integration, denoted by \( C \). This term represents an unknown constant that is added to the function after integrating.
In our indefinite integral \( \int \frac{3}{2v} \, dv \), the "+ \( C \)" in \( \frac{3}{2} \ln |v| + C \) indicates that there is a whole set of functions that differ only by a constant. This is very important because it tells us that the antiderivative family extends over all these possible constants, showcasing the general nature of the solution.
- The constant accounts for the fact that when you take the derivative of a constant, it vanishes.
- Thus, any constant in the original function before differentiation can't be recovered through integration without incorporating \( C \).
In our indefinite integral \( \int \frac{3}{2v} \, dv \), the "+ \( C \)" in \( \frac{3}{2} \ln |v| + C \) indicates that there is a whole set of functions that differ only by a constant. This is very important because it tells us that the antiderivative family extends over all these possible constants, showcasing the general nature of the solution.
Other exercises in this chapter
Problem 16
Find each indefinite integral. \(\int\left(12 x^{3}+3 x^{2}-5\right) d x\)
View solution Problem 17
Find each indefinite integral by the substitution method or state that it cannot be found by our substitution formulas. $$ \int e^{3 x} d x $$
View solution Problem 17
For each demand function \(d(x)\) and supply function \(s(x)\) : a. Find the market demand (the positive value of \(x\) at which the demand function intersects
View solution Problem 17
Find the average value of each function over the given interval. \(f(t)=e^{0.01 t}\) on [0,10]
View solution