Problem 17
Question
Evaluate the expression. \(\log _{6}(216)\)
Step-by-Step Solution
Verified Answer
\(\log _{6}(216) = 3\)
1Step 1: Understand the Expression
The expression \(\log _{6}(216)\) is asking you to find the power to which the base 6 must be raised to obtain 216.
2Step 2: Change of Base Formula
To find \(\log _{6}(216)\), we can use the change of base formula which states that \[ \log_{b}(a) = \frac{\log_{10}(a)}{\log_{10}(b)} \] or using natural logarithms as \[ \log_{b}(a) = \frac{\ln(a)}{\ln(b)} \] depending on calculator availability.
3Step 3: Numerically Evaluate
Using a calculator, evaluate \( \log_{6}(216) \) as \[ \frac{\log_{10}(216)}{\log_{10}(6)} = \frac{2.334}{0.778} \approx 3 \] or using natural logarithms \[ \frac{\ln(216)}{\ln(6)} \approx 3 \]. Therefore, \(\log _{6}(216) = 3\).
Key Concepts
Change of Base FormulaLogarithmic ExpressionsNumerical Evaluation
Change of Base Formula
The change of base formula is a helpful way to simplify logarithmic expressions, especially when you need to compute them using a standard calculator. Often, calculators only have functions for logarithms base 10 (common logarithms) and base e (natural logarithms).
To overcome this, we can use the change of base formula:
To overcome this, we can use the change of base formula:
- For common logarithms: \( \log_{b}(a) = \frac{\log_{10}(a)}{\log_{10}(b)} \)
- For natural logarithms: \( \log_{b}(a) = \frac{\ln(a)}{\ln(b)} \)
- compute the logarithm of the number in the numerator, and
- compute the logarithm of the base in the denominator.
Logarithmic Expressions
Logarithmic expressions are mathematical statements that use the concept of logarithms. A logarithm answers the question: "To what power must a base be raised to obtain a certain number?"
Understanding how to interpret logarithmic expressions is essential in unraveling the question they pose. Through practice, reading and evaluating these expressions will become second nature.
- In the expression \( \log_{b}(x) \), "\( x \)" is the number you wish to express as a power of "\( b \)",
- "\( b \)" is the base,
- and the result indicates the power to which \( b \) must be raised to yield \( x \).
Understanding how to interpret logarithmic expressions is essential in unraveling the question they pose. Through practice, reading and evaluating these expressions will become second nature.
Numerical Evaluation
Numerical evaluation of logarithmic expressions involves using arithmetic and possibly a calculator to find a numerical approximation. When the numbers involved do not yield an obvious or simple answer, calculators come handy, especially with the change of base formula.
Let's break it down using the example \( \log_{6}(216) \). By applying the change of base formula, we evaluate the expression by performing the following calculations:
Let's break it down using the example \( \log_{6}(216) \). By applying the change of base formula, we evaluate the expression by performing the following calculations:
- First, calculate \( \log_{10}(216) \) or \( \ln(216) \) using a calculator.
- Then, calculate \( \log_{10}(6) \) or \( \ln(6) \) similarly.
- Finally, divide the first result by the second. This will give the power to which 6 must be raised to obtain 216.
Other exercises in this chapter
Problem 17
In Exercises \(1-33,\) solve the equation analytically. $$ 70+90 e^{-0.1 t}=75 $$
View solution Problem 17
Use the properties of logarithms to write the expression as a single logarithm. $$ \log _{2}(x)+\log _{2}(y)-\log _{2}(z) $$
View solution Problem 18
We list some radioactive isotopes and their associated half-lives. Assume that each decays according to the formula \(A(t)=A_{0} e^{k t}\) where \(A_{0}\) is th
View solution Problem 18
Solve the equation analytically. $$ \ln (x+1)-\ln (x)=3 $$
View solution