Problem 17
Question
Draw \(\cos \theta\) and \(\sec \theta\) on the same graph. Find all points where \(\cos \theta=\sec \theta\).
Step-by-Step Solution
Verified Answer
The points are at \( \theta = 2\pi k \) and \( \theta = (2k + 1)\pi \), where \( k \) is an integer.
1Step 1: Understand the Functions
First, we need to understand what the cosine and secant functions represent. Cosine, denoted as \( \cos \theta \), is the ratio of the adjacent side to the hypotenuse in a right-angled triangle. Secant, \( \sec \theta \), is the reciprocal of cosine, so \( \sec \theta = \frac{1}{\cos \theta} \).
2Step 2: Set Up the Equation
Now, set the equation \( \cos \theta = \sec \theta \). This implies \( \cos \theta = \frac{1}{\cos \theta} \).
3Step 3: Solve the Equation
To solve \( \cos \theta = \frac{1}{\cos \theta} \), multiply both sides by \( \cos \theta \) to eliminate the fraction: \( \cos^2 \theta = 1 \).
4Step 4: Find Possible Solutions
Solve \( \cos^2 \theta = 1 \). This equation gives us two possible solutions: \( \cos \theta = 1 \) and \( \cos \theta = -1 \).
5Step 5: Determine \( \theta \) Values
For \( \cos \theta = 1 \), \( \theta = 2\pi k \) where \( k \) is an integer. For \( \cos \theta = -1 \), \( \theta = (2k + 1)\pi \) where \( k \) is an integer. These are the angles where the functions meet.
Key Concepts
Cosine FunctionSecant FunctionTrigonometric Identities
Cosine Function
The cosine function, denoted as \( \cos \theta \), is a fundamental trigonometric function that relates an angle \( \theta \) in a right-angled triangle to the ratios of two sides. Specifically, it is defined as the ratio of the adjacent side (the side next to the angle) over the hypotenuse (the longest side of the triangle).
- The input for the cosine function is an angle, often measured in radians or degrees.
- The output is a real number between -1 and 1.
- \( \cos \) is periodic with a period of \( 2\pi \), meaning the values repeat every \( 2\pi \) radians.
Secant Function
The secant function, \( \sec \theta \), is another crucial trigonometric function. It can be thought of as a sibling to the cosine function. Although not as commonly used as sine or cosine, the secant function holds its own place in trigonometry, especially in calculus and advanced geometry.
- It is defined as the reciprocal of the cosine function: \( \sec \theta = \frac{1}{\cos \theta} \).
- Since it is the reciprocal, wherever \( \cos \theta = 0 \), \( \sec \theta \) is undefined, leading to vertical asymptotes in its graph.
- \( \sec \theta \) shares the same period as \( \cos \theta \), which is \( 2\pi \).
Trigonometric Identities
Trigonometric identities are useful mathematical relationships that simplify the analysis and calculations of angles and lengths. They involve the trigonometric functions (such as sine, cosine, and secant) and are instrumental when solving trigonometric equations and verifying equivalences.
- The Pythagorean identity is one of the most fundamental: \( \cos^2 \theta + \sin^2 \theta = 1 \).
- This identity is particularly useful for transforming expressions and finding unknown trigonometric values.
- The reciprocal identities like \( \sec \theta = \frac{1}{\cos \theta} \) and \( \csc \theta = \frac{1}{\sin \theta} \) simplify calculations involving complex fractions.
Other exercises in this chapter
Problem 16
Show that \((\cos t+i \sin t)^{2}=\cos 2 t+i \sin 2 t,\) if \(i^{2}=-1\).
View solution Problem 17
Find the ares under \(v=\cos t\) from the change in \(f=\sin t:\) $$ \text { from } t=0 \text { to } t=2 \pi $$
View solution Problem 18
Find the ares under \(v=\cos t\) from the change in \(f=\sin t:\) $$ \text { from } t=\pi / 2 \text { to } t=3 \pi / 2 . $$
View solution Problem 18
Find all angles \(s\) and \(t\) between 0 and \(2 \pi\) where \(\sin (s+t)=\) \(\sin s+\sin t\).
View solution