Problem 17
Question
Determine whether each matrix has an inverse. If an inverse matrix exists, find it. $$ \left[\begin{array}{ll}{1} & {3} \\ {2} & {0}\end{array}\right] $$
Step-by-Step Solution
Verified Answer
The given matrix has an inverse, which is \[\left[\begin{array}{cc}0 & 1/2\ 1/3 & -1/6\end{array}\right]\].
1Step 1: Calculate the Determinant
To determine if an inverse exists for the given matrix, find the determinant. The determinant of a 2x2 matrix \( A = \left[\begin{array}{cc}a & b\ c & d\end{array}\right] \) can be calculated as \( \text{det}(A) = ad - bc \). For the given matrix \( \left[\begin{array}{ll}1 & 3\ 2 & 0\end{array}\right] \) the determinant is \( 1*0 - 2*3 = -6 \) which is not equal to zero.
2Step 2: Determine if the Inverse Exists
Since the determinant is non-zero (\( -6 \)), the matrix has an inverse.
3Step 3: Calculate the Inverse
The inverse of a 2x2 matrix \( A \) when \( \text{det}(A) \) is not equal to zero can be found using the formula \( A^{-1} = \frac{1}{\text{det}(A)} \left[\begin{array}{cc}d & -b\ -c & a\end{array}\right] \). Apply this to the given matrix: \( \left[\begin{array}{ll}1 & 3\ 2 & 0\end{array}\right]^{-1} = \frac{1}{-6} \left[\begin{array}{cc}0 & -3\ -2 & 1\end{array}\right] \) which simplifies to \( \left[\begin{array}{cc}0 & 1/2\ 1/3 & -1/6\end{array}\right] \).
Key Concepts
Determinant of a MatrixInverse of a 2x2 MatrixNon-Zero DeterminantMatrix Algebra
Determinant of a Matrix
In matrix algebra, the determinant is a special number that provides valuable information about a matrix. For a 2x2 matrix like
\( A = \left[\begin{array}{cc} a & b \ c & d \end{array}\right] \),
the determinant can be calculated with a simple formula:
\( \text{det}(A) = ad - bc \).
The determinant reflects certain properties of the matrix, such as whether it is invertible or singular, and the scale factor of linear transformations it represents. Moreover, the computation of the determinant is a crucial step in various matrix operations, including finding the inverse of a matrix.
\( A = \left[\begin{array}{cc} a & b \ c & d \end{array}\right] \),
the determinant can be calculated with a simple formula:
\( \text{det}(A) = ad - bc \).
The determinant reflects certain properties of the matrix, such as whether it is invertible or singular, and the scale factor of linear transformations it represents. Moreover, the computation of the determinant is a crucial step in various matrix operations, including finding the inverse of a matrix.
Inverse of a 2x2 Matrix
For a 2x2 matrix, finding the inverse is quite straightforward if the determinant is non-zero. Given a matrix
\( A = \left[\begin{array}{cc} a & b \ c & d \end{array}\right] \),
its inverse is given by:
\( A^{-1} = \frac{1}{\text{det}(A)} \left[\begin{array}{cc} d & -b \ -c & a \end{array}\right] \).
However, it is important to note that this formula is only applicable if the determinant of the matrix (\(ad - bc\)) is not equal to zero. The values \(d\) and \(a\) in the inverse matrix are switched, and the signs of \(b\) and \(c\) are flipped. This process is essential for various applications in linear algebra, such as solving systems of linear equations.
\( A = \left[\begin{array}{cc} a & b \ c & d \end{array}\right] \),
its inverse is given by:
\( A^{-1} = \frac{1}{\text{det}(A)} \left[\begin{array}{cc} d & -b \ -c & a \end{array}\right] \).
However, it is important to note that this formula is only applicable if the determinant of the matrix (\(ad - bc\)) is not equal to zero. The values \(d\) and \(a\) in the inverse matrix are switched, and the signs of \(b\) and \(c\) are flipped. This process is essential for various applications in linear algebra, such as solving systems of linear equations.
Non-Zero Determinant
When dealing with matrices, it's critical to understand the significance of a non-zero determinant. A non-zero determinant indicates that the matrix is invertible and has an inverse. Conversely, a determinant of zero implies that the matrix is singular, which means it does not have an inverse. In the context of systems of equations, a non-zero determinant suggests that the system has a unique solution. This is an essential concept since an inverse matrix is often used to compute solutions to linear equations or to change the basis in vector spaces.
Matrix Algebra
Matrix algebra comprises various operations that can be performed on matrices, including addition, subtraction, multiplication, and inversion. In usage, it’s akin to performing arithmetic on numbers but with a set of rules tailored for matrices. When solving for the inverse, a key aspect of matrix algebra, one must be aware of the prerequisites, such as the existence of a non-zero determinant. Learning matrix algebra is fundamental to understanding linear transformations, and it has wide-ranging applications in fields such as computer graphics, engineering, and data science.
Other exercises in this chapter
Problem 16
Find each product. $$ \left[\begin{array}{rr}{-3} & {5}\end{array}\right]\left[\begin{array}{rr}{0} & {-3} \\ {0} & {5}\end{array}\right] $$
View solution Problem 16
Find the value of each variable. $$ \left[\begin{array}{rr}{2} & {2} \\ {-1} & {6}\end{array}\right]-\left[\begin{array}{rr}{4} & {-1} \\ {0} & {5}\end{array}\r
View solution Problem 17
Use an augmented matrix to solve each system. $$ \left\\{\begin{array}{l}{3 x+6 y=2} \\ {2 x-y=3}\end{array}\right. $$
View solution Problem 17
Determine whether each system has a unique solution.$$ \left\\{\begin{array}{l}{20 x+5 y=240} \\ {y=20 x}\end{array}\right. $$
View solution